# 8.1 Graphs of the sine and cosine functions  (Page 6/13)

 Page 6 / 13

## Identifying the properties of a sinusoidal function

Given $\text{\hspace{0.17em}}y=-2\mathrm{cos}\left(\frac{\pi }{2}x+\pi \right)+3,\text{\hspace{0.17em}}$ determine the amplitude, period, phase shift, and horizontal shift. Then graph the function.

Begin by comparing the equation to the general form and use the steps outlined in [link] .

$y=A\mathrm{cos}\left(Bx-C\right)+D$
• Step 1. The function is already written in general form.
• Step 2. Since $\text{\hspace{0.17em}}A=-2,\text{\hspace{0.17em}}$ the amplitude is $\text{\hspace{0.17em}}|A|=2.$
• Step 3. $\text{\hspace{0.17em}}|B|=\frac{\pi }{2},\text{\hspace{0.17em}}$ so the period is $\text{\hspace{0.17em}}P=\frac{2\pi }{|B|}=\frac{2\pi }{\frac{\pi }{2}}=2\pi \cdot \frac{2}{\pi }=4.\text{\hspace{0.17em}}$ The period is 4.
• Step 4. $\text{\hspace{0.17em}}C=-\pi ,$ so we calculate the phase shift as $\text{\hspace{0.17em}}\frac{C}{B}=\frac{-\pi ,}{\frac{\pi }{2}}=-\pi \cdot \frac{2}{\pi }=-2.\text{\hspace{0.17em}}$ The phase shift is $\text{\hspace{0.17em}}-2.$
• Step 5. $D=3,$ so the midline is $\text{\hspace{0.17em}}y=3,$ and the vertical shift is up 3.

Since $\text{\hspace{0.17em}}A\text{\hspace{0.17em}}$ is negative, the graph of the cosine function has been reflected about the x -axis.

[link] shows one cycle of the graph of the function.

## Using transformations of sine and cosine functions

We can use the transformations of sine and cosine functions in numerous applications. As mentioned at the beginning of the chapter, circular motion can be modeled using either the sine or cosine function    .

## Finding the vertical component of circular motion

A point rotates around a circle of radius 3 centered at the origin. Sketch a graph of the y -coordinate of the point as a function of the angle of rotation.

Recall that, for a point on a circle of radius r , the y -coordinate of the point is $\text{\hspace{0.17em}}y=r\text{\hspace{0.17em}}\mathrm{sin}\left(x\right),\text{\hspace{0.17em}}$ so in this case, we get the equation $\text{\hspace{0.17em}}y\left(x\right)=3\text{\hspace{0.17em}}\mathrm{sin}\left(x\right).\text{\hspace{0.17em}}$ The constant 3 causes a vertical stretch of the y -values of the function by a factor of 3, which we can see in the graph in [link] .

What is the amplitude of the function $\text{\hspace{0.17em}}f\left(x\right)=7\mathrm{cos}\left(x\right)?\text{\hspace{0.17em}}$ Sketch a graph of this function.

7

## Finding the vertical component of circular motion

A circle with radius 3 ft is mounted with its center 4 ft off the ground. The point closest to the ground is labeled P , as shown in [link] . Sketch a graph of the height above the ground of the point $\text{\hspace{0.17em}}P\text{\hspace{0.17em}}$ as the circle is rotated; then find a function that gives the height in terms of the angle of rotation.

Sketching the height, we note that it will start 1 ft above the ground, then increase up to 7 ft above the ground, and continue to oscillate 3 ft above and below the center value of 4 ft, as shown in [link] .

Although we could use a transformation of either the sine or cosine function, we start by looking for characteristics that would make one function easier to use than the other. Let’s use a cosine function because it starts at the highest or lowest value, while a sine function    starts at the middle value. A standard cosine starts at the highest value, and this graph starts at the lowest value, so we need to incorporate a vertical reflection.

Second, we see that the graph oscillates 3 above and below the center, while a basic cosine has an amplitude of 1, so this graph has been vertically stretched by 3, as in the last example.

Finally, to move the center of the circle up to a height of 4, the graph has been vertically shifted up by 4. Putting these transformations together, we find that

$y=-3\mathrm{cos}\left(x\right)+4$

A weight is attached to a spring that is then hung from a board, as shown in [link] . As the spring oscillates up and down, the position $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ of the weight relative to the board ranges from $\text{\hspace{0.17em}}–1\text{\hspace{0.17em}}$ in. (at time $\text{\hspace{0.17em}}x=0\right)\text{\hspace{0.17em}}$ to $\text{\hspace{0.17em}}–7\text{\hspace{0.17em}}$ in. (at time $\text{\hspace{0.17em}}x=\pi \right)\text{\hspace{0.17em}}$ below the board. Assume the position of $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ is given as a sinusoidal function of $\text{\hspace{0.17em}}x.\text{\hspace{0.17em}}$ Sketch a graph of the function, and then find a cosine function that gives the position $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ in terms of $\text{\hspace{0.17em}}x.$

$y=3\mathrm{cos}\left(x\right)-4$

In a triangle ABC prove that. (b+c)cosA+(c+a)cosB+(a+b)cisC=a+b+c.
give me the waec 2019 questions
the polar co-ordinate of the point (-1, -1)
prove the identites sin x ( 1+ tan x )+ cos x ( 1+ cot x )= sec x + cosec x
tanh`(x-iy) =A+iB, find A and B
B=Ai-itan(hx-hiy)
Rukmini
what is the addition of 101011 with 101010
If those numbers are binary, it's 1010101. If they are base 10, it's 202021.
Jack
extra power 4 minus 5 x cube + 7 x square minus 5 x + 1 equal to zero
the gradient function of a curve is 2x+4 and the curve passes through point (1,4) find the equation of the curve
1+cos²A/cos²A=2cosec²A-1
test for convergence the series 1+x/2+2!/9x3
a man walks up 200 meters along a straight road whose inclination is 30 degree.How high above the starting level is he?
100 meters
Kuldeep
Find that number sum and product of all the divisors of 360
Ajith
exponential series
Naveen
what is subgroup
Prove that: (2cos&+1)(2cos&-1)(2cos2&-1)=2cos4&+1
e power cos hyperbolic (x+iy)
10y
Michael