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We will see these toolkit functions, combinations of toolkit functions, their graphs, and their transformations frequently throughout this book. It will be very helpful if we can recognize these toolkit functions and their features quickly by name, formula, graph, and basic table properties. The graphs and sample table values are included with each function shown in [link] .

Toolkit Functions
Name Function Graph
Constant f ( x ) = c , where c is a constant Graph of a constant function.
Identity f ( x ) = x Graph of a straight line.
Absolute value f ( x ) = | x | Graph of absolute function.
Quadratic f ( x ) = x 2 Graph of a parabola.
Cubic f ( x ) = x 3 Graph of f(x) = x^3.
Reciprocal f ( x ) = 1 x Graph of f(x)=1/x.
Reciprocal squared f ( x ) = 1 x 2 Graph of f(x)=1/x^2.
Square root f ( x ) = x Graph of f(x)=sqrt(x).
Cube root f ( x ) = x 3 Graph of f(x)=x^(1/3).

Access the following online resources for additional instruction and practice with functions.

Key equations

Constant function f ( x ) = c , where c is a constant
Identity function f ( x ) = x
Absolute value function f ( x ) = | x |
Quadratic function f ( x ) = x 2
Cubic function f ( x ) = x 3
Reciprocal function f ( x ) = 1 x
Reciprocal squared function f ( x ) = 1 x 2
Square root function f ( x ) = x
Cube root function f ( x ) = x 3

Key concepts

  • A relation is a set of ordered pairs. A function is a specific type of relation in which each domain value, or input, leads to exactly one range value, or output. See [link] and [link] .
  • Function notation is a shorthand method for relating the input to the output in the form y = f ( x ) . See [link] and [link] .
  • In tabular form, a function can be represented by rows or columns that relate to input and output values. See [link] .
  • To evaluate a function, we determine an output value for a corresponding input value. Algebraic forms of a function can be evaluated by replacing the input variable with a given value. See [link] and [link] .
  • To solve for a specific function value, we determine the input values that yield the specific output value. See [link] .
  • An algebraic form of a function can be written from an equation. See [link] and [link] .
  • Input and output values of a function can be identified from a table. See [link] .
  • Relating input values to output values on a graph is another way to evaluate a function. See [link] .
  • A function is one-to-one if each output value corresponds to only one input value. See [link] .
  • A graph represents a function if any vertical line drawn on the graph intersects the graph at no more than one point. See [link] .
  • The graph of a one-to-one function passes the horizontal line test. See [link] .

Section exercises


What is the difference between a relation and a function?

A relation is a set of ordered pairs. A function is a special kind of relation in which no two ordered pairs have the same first coordinate.

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What is the difference between the input and the output of a function?

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Why does the vertical line test tell us whether the graph of a relation represents a function?

When a vertical line intersects the graph of a relation more than once, that indicates that for that input there is more than one output. At any particular input value, there can be only one output if the relation is to be a function.

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How can you determine if a relation is a one-to-one function?

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Questions & Answers

the gradient function of a curve is 2x+4 and the curve passes through point (1,4) find the equation of the curve
Kc Reply
Ramesh Reply
test for convergence the series 1+x/2+2!/9x3
success Reply
a man walks up 200 meters along a straight road whose inclination is 30 degree.How high above the starting level is he?
Lhorren Reply
100 meters
Find that number sum and product of all the divisors of 360
jancy Reply
exponential series
what is subgroup
Purshotam Reply
Prove that: (2cos&+1)(2cos&-1)(2cos2&-1)=2cos4&+1
Macmillan Reply
e power cos hyperbolic (x+iy)
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tan hyperbolic inverse (x+iy)=alpha +i bita
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prove that cos(π/6-a)*cos(π/3+b)-sin(π/6-a)*sin(π/3+b)=sin(a-b)
Tejas Reply
why {2kπ} union {kπ}={kπ}?
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why is {2kπ} union {kπ}={kπ}? when k belong to integer
if 9 sin theta + 40 cos theta = 41,prove that:41 cos theta = 41
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what is complex numbers
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Solve 2cos x + 3sin x = 0.5
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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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