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[T] The transformation T a , 0 : 2 2 , T a , 0 ( u , v ) = ( u + a v , v ) , where a 0 is a real number, is called a shear in the x -direction . The transformation, T b , 0 : R 2 R 2 , T o , b ( u , v ) = ( u , b u + v ) , where b 0 is a real number, is called a shear in the y -direction .

  1. Find transformations T 0 , 2 T 3 , 0 .
  2. Find the image R of the trapezoidal region S bounded by u = 0 , v = 0 , v = 1 , and v = 2 u through the transformation T 0 , 2 T 3 , 0 .
  3. Use a CAS to graph the image R in the x y -plane .
  4. Find the area of the region R by using the area of region S .

a. T 0 , 2 T 3 , 0 ( u , v ) = ( u + 3 v , 2 u + 7 v ) ; b. The image S is the quadrilateral of vertices ( 0 , 0 ) , ( 3 , 7 ) , ( 2 , 4 ) , and ( 4 , 9 ) ; c. S is graphed in the following figure;
A four-sided figure with points the origin, (2, 4), (4, 9), and (3, 7).
d. 3 2

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Use the transformation, x = a u , y = a v , z = c w and spherical coordinates to show that the volume of a region bounded by the spheroid x 2 + y 2 a 2 + z 2 c 2 = 1 is 4 π a 2 c 3 .

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Find the volume of a football whose shape is a spheroid x 2 + y 2 a 2 + z 2 c 2 = 1 whose length from tip to tip is 11 inches and circumference at the center is 22 inches. Round your answer to two decimal places.

2662 3 π 282.45 in 3

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[T] Lamé ovals (or superellipses) are plane curves of equations ( x a ) n + ( y b ) n = 1 , where a , b , and n are positive real numbers.

  1. Use a CAS to graph the regions R bounded by Lamé ovals for a = 1 , b = 2 , n = 4 and n = 6 , respectively.
  2. Find the transformations that map the region R bounded by the Lamé oval x 4 + y 4 = 1 , also called a squircle and graphed in the following figure, into the unit disk.
    A square of side length 2 with rounded corners.
  3. Use a CAS to find an approximation of the area A ( R ) of the region R bounded by x 4 + y 4 = 1 . Round your answer to two decimal places.
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[T] Lamé ovals have been consistently used by designers and architects. For instance, Gerald Robinson, a Canadian architect, has designed a parking garage in a shopping center in Peterborough, Ontario, in the shape of a superellipse of the equation ( x a ) n + ( y b ) n = 1 with a b = 9 7 and n = e . Use a CAS to find an approximation of the area of the parking garage in the case a = 900 yards, b = 700 yards, and n = 2.72 yards.

A ( R ) 83,999.2

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Chapter review exercises

True or False? Justify your answer with a proof or a counterexample.

a b c d f ( x , y ) d y d x = c d a b f ( x , y ) d y d x

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Fubini’s theorem can be extended to three dimensions, as long as f is continuous in all variables.

True.

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The integral 0 2 π 0 1 r 1 d z d r d θ represents the volume of a right cone.

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The Jacobian of the transformation for x = u 2 2 v , y = 3 v 2 u v is given by −4 u 2 + 6 u + 4 v .

False.

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Evaluate the following integrals.

R ( 5 x 3 y 2 y 2 ) d A , R = { ( x , y ) | 0 x 2 , 1 y 4 }

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D y 3 x 2 + 1 d A , D = { ( x , y ) | 0 x 1 , x y x }

0

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D sin ( x 2 + y 2 ) d A where D is a disk of radius 2 centered at the origin

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0 1 y 1 x y e x 2 d x d y

1 4

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−1 1 0 z 0 x z 6 d y d x d z

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R 3 y d V , where R = { ( x , y , z ) | 0 x 1 , 0 y x , 0 z 9 y 2 }

1.475

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0 2 0 2 π r 1 r d z d θ d r

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0 2 π 0 π / 2 1 3 ρ 2 sin ( φ ) d ρ d φ d θ

52 3 π

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0 1 1 x 2 1 x 2 1 x 2 y 2 1 x 2 y 2 d z d y d x

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For the following problems, find the specified area or volume.

The area of region enclosed by one petal of r = cos ( 4 θ ) .

π 16

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The volume of the solid that lies between the paraboloid z = 2 x 2 + 2 y 2 and the plane z = 8 .

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The volume of the solid bounded by the cylinder x 2 + y 2 = 16 and from z = 1 to z + x = 2 .

93.291

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The volume of the intersection between two spheres of radius 1, the top whose center is ( 0 , 0 , 0.25 ) and the bottom, which is centered at ( 0 , 0 , 0 ) .

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For the following problems, find the center of mass of the region.

ρ ( x , y ) = x y on the circle with radius 1 in the first quadrant only.

( 8 15 , 8 15 )

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ρ ( x , y ) = ( y + 1 ) x in the region bounded by y = e x , y = 0 , and x = 1 .

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ρ ( x , y , z ) = z on the inverted cone with radius 2 and height 2 .

( 0 , 0 , 8 5 )

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The volume an ice cream cone that is given by the solid above z = ( x 2 + y 2 ) and below z 2 + x 2 + y 2 = z .

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The following problems examine Mount Holly in the state of Michigan. Mount Holly is a landfill that was converted into a ski resort. The shape of Mount Holly can be approximated by a right circular cone of height 1100 ft and radius 6000 ft.

If the compacted trash used to build Mount Holly on average has a density 400 lb/ft 3 , find the amount of work required to build the mountain.

1.452 π × 10 15 ft-lb

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In reality, it is very likely that the trash at the bottom of Mount Holly has become more compacted with all the weight of the above trash. Consider a density function with respect to height: the density at the top of the mountain is still density 400 lb/ft 3 and the density increases. Every 100 feet deeper, the density doubles. What is the total weight of Mount Holly?

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The following problems consider the temperature and density of Earth’s layers.

[T] The temperature of Earth’s layers is exhibited in the table below. Use your calculator to fit a polynomial of degree 3 to the temperature along the radius of the Earth. Then find the average temperature of Earth. ( Hint : begin at 0 in the inner core and increase outward toward the surface)

Source: http://www.enchantedlearning.com/subjects/astronomy/planets/earth/Inside.shtml
Layer Depth from center (km) Temperature ° C
Rocky Crust 0 to 40 0
Upper Mantle 40 to 150 870
Mantle 400 to 650 870
Inner Mantel 650 to 2700 870
Molten Outer Core 2890 to 5150 4300
Inner Core 5150 to 6378 7200

y = −1.238 × 10 −7 x 3 + 0.001196 x 2 3.666 x + 7208 ; average temperature approximately 2800 ° C

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[T] The density of Earth’s layers is displayed in the table below. Using your calculator or a computer program, find the best-fit quadratic equation to the density. Using this equation, find the total mass of Earth.

Source: http://hyperphysics.phy-astr.gsu.edu/hbase/geophys/earthstruct.html
Layer Depth from center (km) Density (g/cm3)
Inner Core 0 12.95
Outer Core 1228 11.05
Mantle 3488 5.00
Upper Mantle 6338 3.90
Crust 6378 2.55
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The following problems concern the Theorem of Pappus (see Moments and Centers of Mass for a refresher), a method for calculating volume using centroids. Assuming a region R , when you revolve around the x -axis the volume is given by V x = 2 π A y , and when you revolve around the y-axis the volume is given by V y = 2 π A x , where A is the area of R . Consider the region bounded by x 2 + y 2 = 1 and above y = x + 1 .

Find the volume when you revolve the region around the x -axis.

π 3

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Find the volume when you revolve the region around the y -axis.

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Practice Key Terms 4

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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