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The body of the method named f4 is similar to the body of the method named f3 , except that f4 computes and returns sine values instead of cosine values. Also, the value of x is used differently so that the period of the curve produced by f4 is twice the period of the curve produced by f3 .

The method named f5

Finally, the bottom white plotting area in Figure 1 shows the output produced by the method named f5 , which is shown in Listing 8 .

Listing 8. The method named f5.
public double f5(double x){ return 100*(Math.sin(x/20.0)*Math.cos(x/10.0));}//end f5

This method computes and returns the product of sine and cosine functions identical to those discussed above.

The end of the class definition

Listing 8 also shows the closing curly brace that signifies the end of the class definition for the class named Graph01Demo .

That's really all that you need to know to be able to make effective use of the generalized plotting program named Graph01 . If you can define the methods named f1 through f5 , which will return the required values for your computational experiment, then you canmake use of this program to plot your data.

The class named Dsp002

Lest you go away believing that this is all too trivial to be interesting, I am going to show you another example that is far from trivial. In the nextexample, I will demonstrate two of the most important operations in the field commonly referred to as digital signal processing, or DSP for short.

Because many of you are unlikely to be familiar with the techniques and terminology involved, the discussion will of necessity be fairly shallow.However, I do want to show at least one example of how you can perform substantive computational experiments using this approach.

A DSP example

A DSP example involving convolution filtering and spectral analysis is shown in Figure 3 .

Figure 3. A Digital Signal Processing (DSP) Example.
missing image

In the field of DSP, the five individual plots shown in the plotting areas of Figure 3 are commonly referred to as traces. I will use that terminology in this discussion.

White random noise

The top trace in the area with the white background shows about 256 samples of white random noise. When we get to the code, we will see that this data wascreated using a Java pseudo-random number generator.

A convolution filter

The second trace from the top shows a 33-point narrow-band convolution filter, which is simply a chunk taken out of a sinusoid whose frequency isone-fourth the sampling frequency. In other words, the sinusoid is represented by four samples per cycle.

The convolution filter output

The middle trace shows the result of applying the narrow-band convolution filter to the white noise. The output from the convolution process was amplifiedto bring it back into an appropriate amplitude range for visual analysis.

If you compare the middle trace with the top trace, you will notice that much of the high-frequency energy and much of the low-frequency energy has beenremoved. Most of the energy in the middle trace appears to be about the same frequency as the design frequency of the convolution filter (which is what we would expect) .

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
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I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
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Commplementary angles
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what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
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Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
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Damian Reply
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
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Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
what is system testing
what is the application of nanotechnology?
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
anybody can imagine what will be happen after 100 years from now in nano tech world
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
silver nanoparticles could handle the job?
not now but maybe in future only AgNP maybe any other nanomaterials
I'm interested in Nanotube
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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