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Npr02_04

% file npr02_04.m % Data for problem P2-4pm = [0.0168  0.0392  0.0672  0.1568  0.0072  0.0168  0.0288  0.0672 ...       0.0252  0.0588  0.1008  0.2352  0.0108  0.0252  0.0432  0.1008]; disp('Minterm probabilities are in pm.  Use mintable(4)')

Npr02_05

% file npr02_05.m % Data for problem P2-5pm = [0.0216  0.0144  0.0504  0.0336  0.0324  0.0216  0.0756  0.0504  0.0216 ...       0.0144  0.0504  0.0336  0.0324  0.0216  0.0756  0.0504  0.0144  0.0096 ...      0.0336  0.0224  0.0216  0.0144  0.0504  0.0336  0.0144  0.0096  0.0336 ...       0.0224  0.0216  0.0144  0.0504  0.0336]; disp('Minterm probabilities are in pm.  Use mintable(5)')

Npr02_06

% file npr02_06.m % Data for problem P2-6minvec3 DV = [A|Ac; A|(Bc&C); A&C; Ac&B; Ac&Cc; B&Cc];DP = [1      0.65     0.20 0.25  0.25   0.30];TV = [((A&Cc)|(Ac&C))&Bc; ((A&Bc)|Ac)&Cc; Ac&(B|Cc)];disp('Call for mincalc')

Npr02_07

% file npr02_07.m % Data for problem P2-7minvec3 DV = [A|Ac; ((A&Bc)|(Ac&B))&C; A&B; Ac&Cc;  A;  C; A&Bc&Cc];DP = [ 1        0.4            0.2   0.3   0.6 0.5   0.1];TV = [(Ac&Cc)|(A&C); ((A&Bc)|Ac)&Cc; Ac&(B|Cc)];disp('Call for mincalc')

Npr02_08

% file npr02_08.m % Data for problem P2-8minvec3 DV = [A|Ac; A;  C;  A&C; Ac&B; Ac&Bc&Cc];DP = [ 1   0.6 0.4  0.3  0.2     0.1];TV = [(A|B)&Cc; (A&Cc)|(Ac&C); (A&Cc)|(Ac&B)];disp('Call for mincalc')

Npr02_09

% file npr02_09.m % Data for problem P2-9minvec3 DV = [A|Ac;  A; A&B; A&C; A&B&Cc];DP = [ 1    0.5 0.3  0.3   0.1];TV = [A&(~(B&Cc)); (A&B)|(A&C)|(B&C)];disp('Call for mincalc')  % Modification for part 2 % DV = [DV; Ac&Bc&Cc; Ac&B&C];% DP = [DP 0.1 0.05];

Npr02_10

% file npr02_10.m % Data for problem P2-10minvec4 DV = [A|Ac;  A;  Ac&Bc; A&Cc; A&C&Dc];DP = [1     0.6  0.2    0.4    0.1];TV = [(Ac&B)|(A&(Cc|D))];disp('Call for mincalc')

Npr02_11

% file npr02_11.m % Data for problem P2-11% A = male;  B = on campus;  C = active in sports minvec3DV = [A|Ac;  A;   B;  A|C; B&Cc; A&B&C; A&Bc; A&Cc];DP = [ 1    0.52 0.85 0.78 0.30  0.32   0.08 0.17];TV = [A&B; A&B&Cc; Ac&C];disp('Call for mincalc')

Npr02_12

% file npr02_12.m % Data for problem P2-12% A = male;  B = party member; C = voted last election minvec3DV = [A|Ac;  A;  A&Bc;  B;  Bc&C; Ac&Bc&C];DP = [  1   0.60 0.30  0.50 0.20  0.10];TV = [Bc&Cc];disp('Call for mincalc')

Npr02_13

% file npr02_13.m % Data for problem P2-13% A = rain in Austin;  B = rain in Houston; % C = rain in San Antoniominvec3 DV = [A|Ac; A&B; A&Bc; A&C; (A&Bc)|(Ac&B); B&C; Bc&C; Ac&Bc&Cc];DP = [  1   0.35 0.15  0.20    0.45        0.30 0.05   0.15];TV = [A&B&C; (A&B&Cc)|(A&Bc&C)|(Ac&B&C); (A&Bc&Cc)|(Ac&B&Cc)|(Ac&Bc&C)];disp('Call for mincalc')

Npr02_14

% file npr02_14.m % Data for problem P2-14% A = male;  B = engineering; % C = foreign language; D = graduate studyminvec4 DV = [A|Ac; A; B; Ac&B; C; Ac&C; A&D; Ac&D; A&B&D; ...       Ac&B&D; B&C&D; Bc&Cc&D; Ac&Bc&C&D];DP = [1 0.55 0.23 0.10 0.75 0.45 0.26 0.19 0.13 0.08 0.20 0.05 0.11];TV = [C&D; Ac&Dc; A&((C&Dc)|(Cc&D))];disp('Call for mincalc')

Npr02_15

% file npr02_15.m % Data for problem P2-15% A = men; B = on campus; C = readers; D = active minvec4DV = [A|Ac; A;  B;  Ac&B;  C;  Ac&C;  D;  B&D; C&D; ...      Ac&B&D; Ac&Bc&D; Ac&B&C&D; Ac&Bc&C&D; A&Bc&Cc&D];DP = [1  0.6 0.55 0.25 0.40 0.25 0.70 0.50 0.35 0.25 0.05 0.10 0.05 0.05];TV = [A&D&(Cc|Bc); A&Dc&Cc];disp('Call for mincalc')

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
how did I we'll learn this
Noor Reply
f(x)= 2|x+5| find f(-6)
Prince Reply
f(n)= 2n + 1
Samantha Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
A fair die is tossed 180 times. Find the probability P that the face 6 will appear between 29 and 32 times inclusive
Samson Reply

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Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
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