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Npr05_17

% file npr05_17.m % Data for problem P5-17PG1 = 84/150; PG2 = 66/125;A = [0.61 0.31 0.08      0.50 0.38 0.12     0.23 0.64 0.13      0.29 0.63 0.08     0.32 0.62 0.06      0.58 0.23 0.19     0.19 0.70 0.11      0.56 0.38 0.06     0.65 0.20 0.15      0.29 0.63 0.08]; B = [0.41 0.51 0.08     0.29 0.65 0.06      0.59 0.33 0.08     0.57 0.29 0.14      0.42 0.50 0.08     0.29 0.62 0.09      0.56 0.32 0.12     0.29 0.64 0.08      0.41 0.50 0.09     0.59 0.32 0.09];disp('Call for oddsdp')

Npr06_10

% file npr06_10.m % Data for problem P6-10pm = [ 0.072 0.048 0.018 0.012 0.168 0.112 0.042 0.028 ...        0.062 0.048 0.028 0.010 0.170 0.110 0.040 0.032]; c  = [-5.3 -2.5 2.3 4.2 -3.7]; disp('Minterm probabilities are in pm, coefficients in c')

Npr06_12

% file npr06_12.m % Data for problem P6-12pm = 0.001*[5 7 6 8 9 14 22 33 21 32 50 75 86 129 201 302]; c = [1 1 1 1 0]; disp('Minterm probabilities in pm, coefficients in c')

Npr06_18.m

% file npr06_18.m % Data for problem P6-18cx = [5 17 21 8 15 0];cy = [8 15 12 18 15 12 0];pmx = minprob(0.01*[37 22 38 81 63]);pmy = minprob(0.01*[77 52 23 41 83 58]);disp('Data in cx, cy, pmx, pmy')

Npr07_01

\begin{verbatim} % file npr07_01.m% Data for problem P7-1 T = [1 3 2 3 4 2 1 3 5 2]; pc = 0.01*[ 8 13 6 9 14 11 12 7 11 9]; disp('Data are in T and pc')\end{verbatim}

Npr07_02

% file npr07_02.m % Data for problem P7-2T = [3.5 5.0 3.5 7.5 5.0 5.0 3.5 7.5];pc = 0.01*[10 15 15 20 10 5 10 15];disp('Data are in T, pc')

Npr08_01

% file npr08_01.m % Solution for problem P8-1X = 0:2; Y = 0:2;Pn = [132  24   0; 864 144  6; 1260 216 6];P = Pn/(52*51); disp('Data in Pn, P, X, Y')

Npr08_02

% file npr08_02.m % Solution for problem P8-2X = 0:2; Y = 0:2;Pn = [6 0 0; 18 12 0; 6 12 2];P = Pn/56; disp('Data are in X, Y,Pn, P')

Npr08_03

% file npr08_03.m % Solution for problem  P8-3X = 1:6; Y = 0:6;P0 = zeros(6,7);       % Initialize for i = 1:6            % Calculate rows of Y probabilities    P0(i,1:i+1) = (1/6)*ibinom(i,1/2,0:i); endP = rot90(P0);         % Rotate to orient as on the plane PY = fliplr(sum(P'));  % Reverse to put in normal orderdisp('Answers are in X, Y, P, PY')

Npr08_04

% file npr08_04.m % Solution for problem P8-4X = 2:12; Y = 0:12;PX = (1/36)*[1 2 3 4 5 6 5 4 3 2 1];P0 = zeros(11,13); for i = 1:11    P0(i,1:i+2) = PX(i)*ibinom(i+1,1/2,0:i+1); endP = rot90(P0); PY = fliplr(sum(P'));disp('Answers are in X, Y, PY, P')

Npr08_05

% file npr08_05.m % Data and basic calculations for P8-5PX = (1/36)*[1 2 3 4 5 6 5 4 3 2 1];X = 2:12; Y = 0:12;P0 = zeros(11,13); for i = 1:11  P0(i,1:i+2) = PX(i)*ibinom(i+1,1/6,0:i+1); endP = rot90(P0); PY = fliplr(sum(P'));disp('Answers are in X, Y, P, PY')

Npr08_06

% file  Newprobs/pr08_06.m % Data for problem P8-6 (from Exam 2, 95f)P = [0.0483    0.0357    0.0420    0.0399    0.0441      0.0437    0.0323    0.0380    0.0361    0.0399     0.0713    0.0527    0.0620    0.0609    0.0551      0.0667    0.0493    0.0580    0.0651    0.0589]; X = [-2.3 -0.7 1.1 3.9 5.1]; Y = [ 1.3  2.5 4.1 5.3]; disp('Data are in X, Y, P')

Npr08_07

% file pr08_07.m  (from Exam3, 96s) % Data for problem P8-7X = [-3.1 -0.5  1.2  2.4  3.7 4.9];Y = [-3.8 -2.0  4.1  7.5];P = [ 0.0090    0.0396    0.0594    0.0216    0.0440    0.0203;       0.0495         0    0.1089    0.0528    0.0363    0.0231;      0.0405    0.1320    0.0891    0.0324    0.0297    0.0189;       0.0510    0.0484    0.0726    0.0132         0    0.0077]; disp('Data are in X, Y, P')

Npr08_08

% file Newprobs/pr08_08.m (from Exam 4 96s) % Data for problem P8-8P = [0.0156  0.0191  0.0081  0.0035  0.0091  0.0070  0.0098  0.0056  0.0091  0.0049;      0.0064  0.0204  0.0108  0.0040  0.0054  0.0080  0.0112  0.0064  0.0104  0.0056;     0.0196  0.0256  0.0126  0.0060  0.0156  0.0120  0.0168  0.0096  0.0056  0.0084;      0.0112  0.0182  0.0108  0.0070  0.0182  0.0140  0.0196  0.0012  0.0182  0.0038;     0.0060  0.0260  0.0162  0.0050  0.0160  0.0200  0.0280  0.0060  0.0160  0.0040;      0.0096  0.0056  0.0072  0.0060  0.0256  0.0120  0.0268  0.0096  0.0256  0.0084;     0.0044  0.0134  0.0180  0.0140  0.0234  0.0180  0.0252  0.0244  0.0234  0.0126;      0.0072  0.0017  0.0063  0.0045  0.0167  0.0090  0.0026  0.0172  0.0217  0.0223];  X = 1:2:19; Y = [-5  -3  -1  3  5 9 10 12]; disp('Data are in X, Y, P')

Npr08_09

% file pr08_09.m   (from Exam3 95f) % Data for problem P8-9P = [0.0390    0.0110    0.0050    0.0010    0.0010;      0.0650    0.0700    0.0500    0.0150    0.0100;     0.0310    0.0610    0.1370    0.0510    0.0330;      0.0120    0.0490    0.1630    0.0580    0.0390;     0.0030    0.0090    0.0450    0.0250    0.0170];X = [1 1.5 2 2.5 3];Y = [1 2 3 4 5];disp('Data are in X, Y, P')

Npr09_02

\begin{verbatim} % file Newprobs/npr09_02.m% Data for problem P9-2 P = [0.0589 0.0342 0.0304 0.0456 0.0209;0.0961 0.0556 0.0498 0.0744 0.0341; 0.0682 0.0398 0.0350 0.0528 0.0242;0.0868 0.0504 0.0448 0.0672 0.0308];X = [-3.9 -1.7 1.5 2.8 4.1];Y = [-2 1 2.6 5.1];disp('Data are in X, Y, P') \end{verbatim}

Npr10_16

\begin{verbatim} % file npr10_16.m% Data for problem P10-16 cx = [-2 1 3 0]; pmx = 0.001*[255 25 375 45 108 12 162 18]; cy = [1 3 1 -3]; pmy = minprob(0.01*[32 56 40]); Z = [-1.3 1.2 2.7 3.4 5.8]; PZ = 0.01*[12 24 43 13 8]; disp('Data are in cx, pmx, cy, pmy, Z, PZ')\end{verbatim}

Npr12_10

% file npr12_10.m % Data for problems P12-10, P12_11cx = [-3.3 -1.7 2.3 7.6 -3.4];pmx = 0.0001*[475 725 120 180 1125 1675 280 420 480 720 130 170 1120 1680 270 430];cy = [10 17 20 -10];pmy = 0.01*[6 14 9 21 6 14 9 21];disp('Data are in cx, cy, pmx and pmy')

Npr16_07

\begin{verbatim} % file npr16_07.m% Transition matrix for problem P16-7 P = [0.23 0.32 0.02 0.22 0.21;0.29 0.41 0.10 0.08 0.12; 0.22 0.07 0.31 0.14 0.26;0.32 0.15 0.05 0.33 0.15; 0.08 0.23 0.31 0.09 0.29]; disp('Transition matrix is P')\end{verbatim}

Npr16_09

% file npr16_09.m % Transition matrix for problem P16-9P = [0.2 0.5 0.3  0   0   0   0;      0.6 0.1 0.3  0   0   0   0;     0.2 0.7 0.1  0   0   0   0;      0   0   0  0.6 0.4  0   0;       0   0   0  0.5 0.5  0   0;     0.1 0.3  0  0.2 0.1 0.1 0.2;      0.1 0.2 0.1 0.2 0.2 0.2  0 ]; disp('Transition matrix is P')

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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A fair die is tossed 180 times. Find the probability P that the face 6 will appear between 29 and 32 times inclusive
Samson Reply

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Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
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