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You may notice that the graphs in parts a. and b. are identical. This happens because the function describing curve b is a so-called reparameterization    of the function describing curve a. In fact, any curve has an infinite number of reparameterizations; for example, we can replace t with 2 t in any of the three previous curves without changing the shape of the curve. The interval over which t is defined may change, but that is all. We return to this idea later in this chapter when we study arc-length parameterization.

As mentioned, the name of the shape of the curve of the graph in [link] c. is a helix    ( [link] ). The curve resembles a spring, with a circular cross-section looking down along the z -axis. It is possible for a helix to be elliptical in cross-section as well. For example, the vector-valued function r ( t ) = 4 cos t i + 3 sin t j + t k describes an elliptical helix. The projection of this helix into the x , y -plane is an ellipse. Last, the arrows in the graph of this helix indicate the orientation of the curve as t progresses from 0 to 4 π .

Create a graph of the vector-valued function r ( t ) = ( t 2 1 ) i + ( 2 t 3 ) j , 0 t 3 .

This figure is a graph of the function r(t) = (t^2-1)i + (2t-3)j, for the values of t from 0 to 3. The curve begins in the 3rd quadrant at the ordered pair (-1,-3) and increases up through the 1st quadrant. It is increasing and has arrows on the curve representing orientation to the right.

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At this point, you may notice a similarity between vector-valued functions and parameterized curves. Indeed, given a vector-valued function r ( t ) = f ( t ) i + g ( t ) j , we can define x = f ( t ) and y = g ( t ) . If a restriction exists on the values of t (for example, t is restricted to the interval [ a , b ] for some constants a < b ) , then this restriction is enforced on the parameter. The graph of the parameterized function would then agree with the graph of the vector-valued function, except that the vector-valued graph would represent vectors rather than points. Since we can parameterize a curve defined by a function y = f ( x ) , it is also possible to represent an arbitrary plane curve by a vector-valued function.

Limits and continuity of a vector-valued function

We now take a look at the limit of a vector-valued function    . This is important to understand to study the calculus of vector-valued functions.

Definition

A vector-valued function r approaches the limit L as t approaches a, written

lim t a r ( t ) = L ,

provided

lim t a | r ( t ) L | = 0 .

This is a rigorous definition of the limit of a vector-valued function. In practice, we use the following theorem:

Limit of a vector-valued function

Let f, g, and h be functions of t. Then the limit of the vector-valued function r ( t ) = f ( t ) i + g ( t ) j as t approaches a is given by

lim t a r ( t ) = [ lim t a f ( t ) ] i + [ lim t a g ( t ) ] j ,

provided the limits lim t a f ( t ) and lim t a g ( t ) exist. Similarly, the limit of the vector-valued function r ( t ) = f ( t ) i + g ( t ) j + h ( t ) k as t approaches a is given by

lim t a r ( t ) = [ lim t a f ( t ) ] i + [ lim t a g ( t ) ] j + [ lim t a h ( t ) ] k ,

provided the limits lim t a f ( t ) , lim t a g ( t ) and lim t a h ( t ) exist.

In the following example, we show how to calculate the limit of a vector-valued function.

Evaluating the limit of a vector-valued function

For each of the following vector-valued functions, calculate lim t 3 r ( t ) for

  1. r ( t ) = ( t 2 3 t + 4 ) i + ( 4 t + 3 ) j
  2. r ( t ) = 2 t 4 t + 1 i + t t 2 + 1 j + ( 4 t 3 ) k
  1. Use [link] and substitute the value t = 3 into the two component expressions:
    lim t 3 r ( t ) = lim t 3 [ ( t 2 3 t + 4 ) i + ( 4 t + 3 ) j ] = [ lim t 3 ( t 2 3 t + 4 ) ] i + [ lim t 3 ( 4 t + 3 ) ] j = 4 i + 15 j .
  2. Use [link] and substitute the value t = 3 into the three component expressions:
    lim t 3 r ( t ) = lim t 3 ( 2 t 4 t + 1 i + t t 2 + 1 j + ( 4 t 3 ) k ) = [ lim t 3 ( 2 t 4 t + 1 ) ] i + [ lim t 3 ( t t 2 + 1 ) ] j + [ lim t 3 ( 4 t 3 ) ] k = 1 2 i + 3 10 j + 9 k .
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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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