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Wiskunde

Desimale breuke

Opvoeders afdeling

Memorandum

20.1

a) 260

b) 2 600

c) 26,7

d) 267

e) 2 670

f) 26,79

g) 267,9

h) 2 679

20.2 x10: Elke syfer skuif 1 plek na links / komma skuif 1 plek na regs.

x100: Elke syfer skuif 2 plekke na links / komma skuif 2 plekke na regs.

x1000: Elke syfer skuif 3 plekke na links / komma skuif 3 plekke na regs.

20.4

a) 54,8 548 5480
b) 3,67 36,7 367
c) 8,9 89 890
d) 165,38 1653,8 16 538
e) 282,51 2825,1 28 251

20.5.1

a) 21,522

b) 46,215

c) 1,4

d) 4,64

e) 12 250

f) 2 370,6

  • Antwoord is kleiner.

x met getal<1

20.8

a) 0,4964

b) 1,3737

c) 0,109

d) 5,53724

e) 38,57997

f) 16,78164

23.1 size 12{ div } {} 10: Komma skuif 1 plek na links

Elke syfer skuif een plek na regs

size 12{ div } {} 100: Komma skuif 2 plekke na links

Elke syfer skuif 2 plekke na regs

size 12{ div } {} 1000: Komma skuif 3 plekke na links

Elke syfer skuif 3 plekke na regs

23.3

8,21 0,729 0,6
0,864 0,6254 0,0392 8,791 0,035 0,08
74,68

Leerders afdeling

Inhoud

Aktiwiteit: vermenigvuldiging van desimale breuke [lu 1.3.4, lu 1.7.7, lu 1.9.2, lu 1.10, lu 2.3.3]

20. VERMENIGVULDIGING VAN DESIMALE BREUKE

20.1 Kom ons hersien

Do the following with the help of your calculator:

SOM ANTWOORD
Bv. 2,6 × 10 26
a) 2,6 × 100 .........................
b) 2,6 × 1 000 .........................
c) 2,67 × 10 .........................
d) 2,67 × 100 .........................
e) 2,67 × 1 000 .........................
f) 2,679 × 10 .........................
g) 2,679 × 100 .........................
h) 2,679 × 1 000 .........................

20.2 Werk in groepe van drie. Formuleer gou reëls vir die vermenigvuldiging van desimale breuke met 10, 100 en 1 000.

20.3 Onthou jy nog?

10 x 1 = 10 = 101

10 x 10 = 100 = 102

10 x 10 x 10 = 1 000 = 103

10 x 10 x 10 x 10 = 10 000 = 104

10 x 10 x 10 x 10 x 10 = 100 000 = 105

10 x 10 x 10 x 10 x 10 x 10 = 1 000 000 = 106

20.4 Voltooi die volgende tabel:

× 10 1 10 2 10 3
e.g. 3,2 32 320 3 200
a) 5,48 ..................... ..................... .....................
b) 0,367 ..................... ..................... .....................
c) 0,89 ..................... ..................... .....................
d) 16,538 ..................... ..................... .....................
e) 28,251 ..................... ..................... .....................

20.5 Nog hersiening

20.5.1 Werk saam met ’n maat. Bereken die antwoorde sonder om ’n sakrekenaar te gebruik:

a) s = 3,587 x 6

………………………………………………

………………………………………………

………………………………………………

………………………………………………

b) f = 9,243 x 5

………………………………………………

………………………………………………

………………………………………………

………………………………………………

c) p = 0,02 x 70

………………………………………………

………………………………………………

………………………………………………

………………………………………………

d) r = 0,058 x 80

………………………………………………

………………………………………………

………………………………………………

………………………………………………

e) t = 24,5 x 500

………………………………………………

………………………………………………

………………………………………………

………………………………………………

f) h = 2,634 x 900

………………………………………………

………………………………………………

………………………………………………

………………………………………………

20.5.2 Kontroleer jul antwoorde met ’n sakrekenaar.

20.6 VERMENIGVULDIGING VAN DESIMALE BREUKE MET DESIMALE BREUKE

20.6.1 Lees die volgende probleem en werk dan weer saam met ’n maat deur die verskillende oplossings:

’n Skilpad stap 0,8 km in een uur. Hoe ver sal hy in 0,6 uur stap?

Questions & Answers

what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
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J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
how did I we'll learn this
Noor Reply
f(x)= 2|x+5| find f(-6)
Prince Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
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AMJAD
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AMJAD
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Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
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Source:  OpenStax, Wiskunde graad 7. OpenStax CNX. Oct 21, 2009 Download for free at http://cnx.org/content/col11076/1.2
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