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This error occurs when a syntactically correct statement does not appear where it should. Examples:
max ; // Error, missing =
Eclipse: Syntax error, insert "AssignmentOperator Expression"
to complete Expression else :
if (i > j)
max = i;els ; // Error, else not spelled correctly The reason you do not get “else expected” is that you need not write an
else alternative so this just looks like a bad statement.
if (i > j)
max = i;els // Error, else not spelled correctly
max = j; results in a weird error message:
x.java:6: cannot find symbol
symbol : class elslocation: class x
els The reason is that the compiler interprets this as a declaration:
els max = j; and can't find a class
els as the type of the variable
max .
void f() {
int default = 10;}
Eclipse:
Syntax error on token "default", invalid VariableDeclaratorId This is probably the most common compile-time error. All identifiers in Java must be declared before being used and an inconsistency between the declarationof an identifier and its use will give rise to this error. Carefully check the spelling of the identifier. It is easy to make a mistake by using a lower-case letter instead of an upper case one, or to confuse the letter O withthe numeral 0 and the letter l with the numeral 1.
Other sources of this error are: calling a constructor
with an incorrect parameter signature, andusing an identifier outside its scope, for example,
using an identifier declared in a
for -loop outside the loop:
int[] a = {1, 2, 3};int sum = 0;
for (int i = 0; i < a.length; i++)
sum = sum + a[i];
System.out.println("Last = " + i); // Error, i not in scope
Eclipse: ... cannot be resolved
An identifier can only be declared once in the same scope:
int sum = 0;
double sum = 0.0; // Error, sum already defined
Eclipse: Duplicate local variable sum
This error is caused by attempting to index a variable which is not an array.
int max(int i, int j) {
if (i > j) return i;
else return j[i]; // Error, j is not an array
}
Eclipse: The type of the expression must be an array type but it resolved to int
It is illegal to access a variable declared private outside its class.
Eclipse: The field ... is not visible
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