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The program performs spectral analysis on five separate time series, each 400 samples in length. Each time series contains a pulse and the pulses aredifferent lengths.

Each pulse consists of the sum of two sinusoids at closely spaced frequencies. The frequencies of the two sinusoids are equidistant from a centerfrequency of 0.0625 times the sampling frequency. The total separation between the frequencies of the two sinusoids is the reciprocal of the length of thepulse.

All frequency values are specified as type double as a fraction of the sampling frequency.

The lengths of the pulses are:

  • 25 samples
  • 50 samples
  • 100 samples
  • 200 samples
  • 400 samples

The spectral analysis

The spectral analysis computes the spectra at 400 equally spaced frequencies between zero and the folding frequency (one-half the sampling frequency) .

The results of the spectral analysis are multiplied by the reciprocal of the lengths of the individual pulses to normalize the five plots. Otherwise, theresults for the short pulses would be too small to see on the plots.

Because of the similarity of this program to the previous programs, my discussion of the code will be very brief.

Computation of the frequencies

The code in Listing 7 shows the computation of the frequencies of the sinusoids that will be added together to form each of the five pulses.

Listing 7. Computation of the frequencies.
//Frequencies of the sinusoidsdouble freq1a = 0.0625 - 8.0/len; double freq2a = 0.0625 + 8.0/len;double freq1b = 0.0625 - 4.0/len; double freq2b = 0.0625 + 4.0/len;double freq1c = 0.0625 - 2.0/len; double freq2c = 0.0625 + 2.0/len;double freq1d = 0.0625 - 1.0/len; double freq2d = 0.0625 + 1.0/len;double freq1e = 0.0625 - 0.5/len; double freq2e = 0.0625 + 0.5/len;

Create the pulses

The code in Listing 8 uses those frequency values to create the data for the pulses and to store that data in the arrays used to hold the pulses.

Listing 8. Create the pulses.
//Create the raw data for(int x = 0;x<len/16;x++){ data1[x]= amp*Math.cos(2*pi*x*freq1a) + amp*Math.cos(2*pi*x*freq2a);}//end for loop for(int x = 0;x<len/8;x++){ data2[x]= amp*Math.cos(2*pi*x*freq1b) + amp*Math.cos(2*pi*x*freq2b);}//end for loop for(int x = 0;x<len/4;x++){ data3[x]= amp*Math.cos(2*pi*x*freq1c) + amp*Math.cos(2*pi*x*freq2c);}//end for loop for(int x = 0;x<len/2;x++){ data4[x]= amp*Math.cos(2*pi*x*freq1d) + amp*Math.cos(2*pi*x*freq2d);}//end for loop for(int x = 0;x<len;x++){ data5[x]= amp*Math.cos(2*pi*x*freq1e) + amp*Math.cos(2*pi*x*freq2e);}//end for loop

Other than the code shown in Listing 7 and Listing 8 , the program named Dsp033 is the same as the programs that were previously explained, and I won'tdiscuss it further.

Run the programs

I encourage you to copy, compile, and run the programs provided in this module. Experiment with them, making changes and observing the results of yourchanges.

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
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hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
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the value of V1 and V2
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advantages of electrons in a circuit
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we're do you find electromagnetism past papers
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it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
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how to calculate coefficient of static friction
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how to calculate static friction
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How to calculate force
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a structure of a thermocouple used to measure inner temperature
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a rate of change in velocity of an object whith respect to time
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Kidist
Acceleration is a rate of change in velocity.
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t =r×f
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Precious Reply
hi
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Leago
use fnet method. how many obects are being calculated ?
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Hulisani
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Lungile Reply
you use Fnet equals ma , newtoms second law formula
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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