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Let's see some code!

I will present and explain this class in fragments. A complete listing of the class is provided in Listing 35 near the end of the module.

Beginning of the class named PlotALot01

As mentioned earlier, this class contains a main method. The main method is provided so that the class can be run as an application for self-test purposes, which is common practice in Javaprogramming. The main method also illustrates the proper use of the class.

The beginning of the class and the beginning of the main method are shown in Listing 1 .

Listing 1. Beginning of the class named PlotALot01.
public class PlotALot01{ public static void main(String[]args){ PlotALot01 plotObjectA =new PlotALot01("A",158,237,36,5,4,4); PlotALot01 plotObjectB = new PlotALot01("B");

Instantiate two plotting objects

Listing 1 instantiates two independent plotting objects. The first plotting object, referred to by plotObjectA is instantiated by calling the constructor that accepts plotting parameters. A description of each of theconstructor parameters was provided earlier . You may find it useful to compare the values shown in Listing 1 with the overall plotting parameters listed earlier to confirm how they are related.

The second plotting object, referred to by plotObjectB is instantiated by calling the constructor that accepts only the page title as aparameter and uses default values for all of the plotting parameters. You will see those default values later in the code.

Feed the plotting object titled "A"

Listing 2 contains a for loop that feeds 275 values to the plotting object titled "A". Most of the code in Listing 2 is required to set fifteen specific values to test for propertransitions as described earlier. This code is straightforward and shouldn't require further explanation.

(I was able to determine the correct locations for these values by knowing the size of the Frame, inset values for the Frame, the space betweentraces, the number of pixels dedicated to each sample, etc.)

Listing 2. Feed the plotting object titled "A".
for(int cnt = 0;cnt<275;cnt++){ if(cnt == 147){plotObjectA.feedData(0); }else if(cnt == 148){plotObjectA.feedData(0); }else if(cnt == 149){plotObjectA.feedData(25); }else if(cnt == 150){plotObjectA.feedData(-25); }else if(cnt == 151){plotObjectA.feedData(25); }else if(cnt == 152){plotObjectA.feedData(0); }else if(cnt == 153){plotObjectA.feedData(0); }else if(cnt == 26){plotObjectA.feedData(0); }else if(cnt == 27){plotObjectA.feedData(0); }else if(cnt == 28){plotObjectA.feedData(20); }else if(cnt == 29){plotObjectA.feedData(20); }else if(cnt == 30){plotObjectA.feedData(-20); }else if(cnt == 31){plotObjectA.feedData(-20); }else if(cnt == 32){plotObjectA.feedData(0); }else if(cnt == 33){plotObjectA.feedData(0); }else{plotObjectA.feedData( (Math.random() - 0.5)*25);}//end else }//end for loop

White random noise

The final statement in Listing 2 uses a random number generator to feed white random noise to the plotting object for all data values other than the fifteendata values specified in the preceding statements. You can see the random values plotted and marked by round ovals in Figure 5 .

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
Idrissa Reply
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
how do you translate this in Algebraic Expressions
linda Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
what's the easiest and fastest way to the synthesize AgNP?
Damian Reply
China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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