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Die hars wat sommige bome afgee, is ook belangrik vir sekere diere.

Wanneer blare of vrugte van die bome afval en op die grond om die bome lê, kan ’n ander reeks organismes intree. Die ontbinders soos mikro-organismes wat die dooie materiaal laat verrot en ontbind, dra by tot die afbreek van die voedingstowwe sodat hulle teruggeplaas word in die grond. So word humus gevorm. Humus is dooie organiese materiaal. Ander diertjies wat ook van verrotte organiese materiaal lewe, nl. die detrivore , bevorder ook hierdie ontbindingsproses.

  • Plakkaat om die Rolspelers in ’n Boom-ekosisteem te illustreer
  • Bring prente van diere, bome en ander plante na die klas. Die onderwyser sal julle in groepe verdeel.
  • Elke groep berei ’n plakkaat voor om die onderlinge afhanklikheid van die bome, ander plante en diere te illustreer. Elke groep dra uiteindelik sy plakkaat aan die res van die klas voor.
  • Beantwoord die volgende vrae na aanleiding van die klasbespreking:

VRAE

1. Gestel die boom in jou plakkaat val om.

1.1 Watter organismes sal doodgaan?

1.2 Watter organismes sal wegtrek?

1.3 Watter organismes sal in getalle toeneem?

2. Beskryf die rol wat bome in ’n ekosisteem speel.

3. Waarom is dit ekologies gesien sleg om blare rondom bome weg te hark?

4. Noem nog drie voorbeelde waar die mens ekosisteme benadeel.

Assessering van PLAKKAAT en interpretasie van vrae daarom:

Kon jy die gesamentlike inligting gebruik om die vrae te beantwoord?

[LU 1.2; 1.3; 2.4]

Aktiwiteit 3:

Om rotspoel-ekosisteme te bespreek

[lu 2.1; 2.2; 2.3]

Hierdie ekosisteme is uiters sensitief. Die belangrikste faktor wat hier ’n rol speel, is GETYE.

Getye wissel twee keer elke 24 uur. Deur branderaksies word vars, koue suurstofryke seewater oor die rotspoelgemeenskappe gespoel. Tydens laaggetye is daar weer verhitting van die water in die rotspoele en verdamping vind plaas. Hierdie veranderinge dra daartoe by dat die organismes wat in rotspoele bly, aangepas moet wees om verskeie aanslae van die natuur die hoof te kan bied.

1. Beskryf wat jy verstaan onder “’n rotspoel”.

2. Maak ‘n lys van al die abiotiese faktore wat ’n inpak op rotspoele het:

Plante in rotspoele

Die algemeenste plante is seewier of see-alge. Hulle is rooi, groen of bruin.

Alhoewel hulle nie altyd groen is nie, kan hulle voedingstowwe deur fotosintese vervaardig. Dus is hulle ook produseerders.

Hulle is ook voedsel vir ’n wye reeks ander organismes wat op hulle teer, soos platmossels en sommige slakke.

Diere in rotspoele

Doen naleeswerk en beskryf wat elkeen van die volgende is:

(a) filtreervoeders:

(b) aasvreters:

2. Wat sou die doel van tentakels by see-anemone wees?

3. Watter onderlinge afhanklikheid bestaan tussen die organismes in ’n rotspoel?

Assessering van interpretasie van SKETSE

Kon jy basiese rotspoelkomponente onderskei?

[LU 2.1; 2.2; 2.3]

Assessering

LU 1

Wetenskaplike Ondersoek

Die leerder is in staat om met selfvertroue op weetgierigheid oor natuurlike verskynsels te reageer, en om binne die konteks van wetenskap, tegnologie en die omgewing verbande te ondersoek en probleme op te los.

Dit is bewys as die leerder:

1.1 ondersoeke kan beplan;

1.2 ondersoeke kan uitvoer en data kan insamel;

1.3 data kan evalueer en bevindinge kan kommunikeer.

LU 2

Wetenskaplike Kennis

Die leerder ken, interpreteer en pas wetenskaplike, tegnologiese en omgewingskennis toe.

Dit is bewys as die leerder:

2.1 sinvolle inligting kan onthou;

2.2 inligting in kategorieë kan plaas;

2.3 inligting kan interpreteer;

2.4 kennis kan toepas.

Memorandum

Module 2

Aktiwiteit

VOORDELE VAN BRAND NADELE VAN BRAND
  • Sade se harde saadhuide bars oop
  • Lugbesoedeling – rook
  • Spesies word herontdek soos vleiroos
  • Diere en mense beseer of gedood
  • Aggressiewe groeiers ingeperk
  • Maak grondorganismes dood – humus verminder
  • Vars plante voedsaam (groen gras na ’n strawwe winter)
  • Verswak grasse indien teen verkeerde tyd gebrand

Aktiwiteit

Vrae

1. Gestel die boom in jou plakkaat val om

a. Plante wat in die skaduwee gegroei het en nie bestand is teen direkte sonlig nie

b. Sommige diertjies soos voëls en eekhorinkies

c. Ontbinders soos bakterieë en fungi

2. Aanvaar leerders se antwoorde, maar sorg dat die volgende genoem word: habitat, skuiling, voedselbron, skadu

3. Verrotting en humusvorming word belemmer: grondstowwe keer nie terug na grond nie en die grond verarm

4. Oorbeweiding, inbring van uitheemse plante, besoedeling

Aktiwiteit

1. Aanvaar leerders se beskrywings. Die volgende moet figureer: soutwater, vlak water, hoogety en laaggety, abiotiese toestande wissel drasties.

2. Branderaksie, wind, uitdroging, sonverhitting, besoedeling deur mens

DIERE IN ROTSPOELE

Vrae

1. Naleeswerk

(a) Filtreervoeders: mossels: water word deur fyn strukture gespoel en fyn kosdeeltjies word uit die water gefiltreer

(b) Aasvreter: eet dooie diere bv krappe

2. Tentakels: gryp kosstukkies uit alle rigtings omdat daar geen oë of reuksintuie is nie, en druk dit in die mond in

3. Voedselverwantskappe soos in vorige vrae aangeroer

4. Skuiling: plante bied skuiling teen predatore

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Natuurwetenskappe graad 8. OpenStax CNX. Sep 12, 2009 Download for free at http://cnx.org/content/col11049/1.1
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