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When does an extraneous solution occur? How can an extraneous solution be recognized?

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When can the one-to-one property of logarithms be used to solve an equation? When can it not be used?

The one-to-one property can be used if both sides of the equation can be rewritten as a single logarithm with the same base. If so, the arguments can be set equal to each other, and the resulting equation can be solved algebraically. The one-to-one property cannot be used when each side of the equation cannot be rewritten as a single logarithm with the same base.

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Algebraic

For the following exercises, use like bases to solve the exponential equation.

4 3 v 2 = 4 v

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64 4 3 x = 16

x = 1 3

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2 3 n 1 4 = 2 n + 2

n = 1

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36 3 b 36 2 b = 216 2 b

b = 6 5

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( 1 64 ) 3 n 8 = 2 6

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For the following exercises, use logarithms to solve.

e r + 10 10 = −42

No solution

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8 10 p + 7 7 = −24

p = log ( 17 8 ) 7

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7 e 3 n 5 + 5 = −89

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e 3 k + 6 = 44

k = ln ( 38 ) 3

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5 e 9 x 8 8 = −62

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6 e 9 x + 8 + 2 = −74

x = ln ( 38 3 ) 8 9

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e 2 x e x 132 = 0

x = ln 12  

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7 e 8 x + 8 5 = −95

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10 e 8 x + 3 + 2 = 8

x = ln ( 3 5 ) 3 8

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8 e 5 x 2 4 = −90

no solution

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e 2 x e x 6 = 0

x = ln ( 3 )

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3 e 3 3 x + 6 = −31

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For the following exercises, use the definition of a logarithm to rewrite the equation as an exponential equation.

log ( 1 100 ) = −2

10 2 = 1 100

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For the following exercises, use the definition of a logarithm to solve the equation.

4 + log 2 ( 9 k ) = 2

k = 1 36

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2 log ( 8 n + 4 ) + 6 = 10

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10 4 ln ( 9 8 x ) = 6

x = 9 e 8

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For the following exercises, use the one-to-one property of logarithms to solve.

ln ( 10 3 x ) = ln ( 4 x )

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log 13 ( 5 n 2 ) = log 13 ( 8 5 n )

n = 1

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log ( x + 3 ) log ( x ) = log ( 74 )

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ln ( 3 x ) = ln ( x 2 6 x )

No solution

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log 4 ( 6 m ) = log 4 3 m

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ln ( x 2 ) ln ( x ) = ln ( 54 )

No solution

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log 9 ( 2 n 2 14 n ) = log 9 ( 45 + n 2 )

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ln ( x 2 10 ) + ln ( 9 ) = ln ( 10 )

x = ± 10 3

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For the following exercises, solve each equation for x .

log ( x + 12 ) = log ( x ) + log ( 12 )

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ln ( x ) + ln ( x 3 ) = ln ( 7 x )

x = 10

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ln ( 7 ) + ln ( 2 4 x 2 ) = ln ( 14 )

x = 0

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log 8 ( x + 6 ) log 8 ( x ) = log 8 ( 58 )

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ln ( 3 ) ln ( 3 3 x ) = ln ( 4 )

x = 3 4

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log 3 ( 3 x ) log 3 ( 6 ) = log 3 ( 77 )

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Graphical

For the following exercises, solve the equation for x , if there is a solution . Then graph both sides of the equation, and observe the point of intersection (if it exists) to verify the solution.

log 9 ( x ) 5 = −4

x = 9

Graph of log_9(x)-5=y and y=-4.
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ln ( 3 x ) = 2

x = e 2 3 2.5

Graph of ln(3x)=y and y=2.
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log ( 4 ) + log ( 5 x ) = 2

x = 5

Graph of log(4)+log(-5x)=y and y=2.
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7 + log 3 ( 4 x ) = −6

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ln ( 4 x 10 ) 6 = 5

x = e + 10 4 3.2

Graph of ln(4x-10)-6=y and y=-5.
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log ( 4 2 x ) = log ( 4 x )

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log 11 ( 2 x 2 7 x ) = log 11 ( x 2 )

No solution

Graph of log_11(-2x^2-7x)=y and y=log_11(x-2).
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ln ( 2 x + 9 ) = ln ( 5 x )

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log 9 ( 3 x ) = log 9 ( 4 x 8 )

x = 11 5 2.2

Graph of log_9(3-x)=y and y=log_9(4x-8).
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log ( x 2 + 13 ) = log ( 7 x + 3 )

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3 log 2 ( 10 ) log ( x 9 ) = log ( 44 )

x = 101 11 9.2

Graph of 3/log_2(10)-log(x-9)=y and y=log(44).
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ln ( x ) ln ( x + 3 ) = ln ( 6 )

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For the following exercises, solve for the indicated value, and graph the situation showing the solution point.

An account with an initial deposit of $6,500 earns 7.25 % annual interest, compounded continuously. How much will the account be worth after 20 years?

about $ 27 , 710.24

Graph of f(x)=6500e^(0.0725x) with the labeled point at (20, 27710.24).
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The formula for measuring sound intensity in decibels D is defined by the equation D = 10 log ( I I 0 ) , where I is the intensity of the sound in watts per square meter and I 0 = 10 12 is the lowest level of sound that the average person can hear. How many decibels are emitted from a jet plane with a sound intensity of 8.3 10 2 watts per square meter?

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The population of a small town is modeled by the equation P = 1650 e 0.5 t where t is measured in years. In approximately how many years will the town’s population reach 20,000?

about 5 years

Graph of P(t)=1650e^(0.5x) with the labeled point at (5, 20000).
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Technology

For the following exercises, solve each equation by rewriting the exponential expression using the indicated logarithm. Then use a calculator to approximate x to 3 decimal places .

1000 ( 1.03 ) t = 5000 using the common log.

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e 5 x = 17 using the natural log

ln ( 17 ) 5 0.567

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3 ( 1.04 ) 3 t = 8 using the common log

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3 4 x 5 = 38 using the common log

x = log ( 38 ) + 5 log ( 3 )     4 log ( 3 ) 2.078

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50 e 0.12 t = 10 using the natural log

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For the following exercises, use a calculator to solve the equation. Unless indicated otherwise, round all answers to the nearest ten-thousandth.

7 e 3 x 5 + 7.9 = 47

x 2.2401

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ln ( 3 ) + ln ( 4.4 x + 6.8 ) = 2

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log ( 0.7 x 9 ) = 1 + 5 log ( 5 )

x 44655 . 7143

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Atmospheric pressure P in pounds per square inch is represented by the formula P = 14.7 e 0.21 x , where x is the number of miles above sea level. To the nearest foot, how high is the peak of a mountain with an atmospheric pressure of 8.369 pounds per square inch? ( Hint : there are 5280 feet in a mile)

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The magnitude M of an earthquake is represented by the equation M = 2 3 log ( E E 0 ) where E is the amount of energy released by the earthquake in joules and E 0 = 10 4.4 is the assigned minimal measure released by an earthquake. To the nearest hundredth, what would the magnitude be of an earthquake releasing 1.4 10 13 joules of energy?

about 5.83

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Extensions

Use the definition of a logarithm along with the one-to-one property of logarithms to prove that b log b x = x .

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Recall the formula for continually compounding interest, y = A e k t . Use the definition of a logarithm along with properties of logarithms to solve the formula for time t such that t is equal to a single logarithm.

t = ln ( ( y A ) 1 k )

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Recall the compound interest formula A = a ( 1 + r k ) k t . Use the definition of a logarithm along with properties of logarithms to solve the formula for time t .

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Newton’s Law of Cooling states that the temperature T of an object at any time t can be described by the equation T = T s + ( T 0 T s ) e k t , where T s is the temperature of the surrounding environment, T 0 is the initial temperature of the object, and k is the cooling rate. Use the definition of a logarithm along with properties of logarithms to solve the formula for time t such that t is equal to a single logarithm.

t = ln ( ( T T s T 0 T s ) 1 k )

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Questions & Answers

preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
A hedge is contrusted to be in the shape of hyperbola near a fountain at the center of yard.the hedge will follow the asymptotes y=x and y=-x and closest distance near the distance to the centre fountain at 5 yards find the eqution of the hyperbola
ayesha Reply
A doctor prescribes 125 milligrams of a therapeutic drug that decays by about 30% each hour. To the nearest hour, what is the half-life of the drug?
Sandra Reply
Find the domain of the function in interval or inequality notation f(x)=4-9x+3x^2
prince Reply
hello
Jessica Reply
Outside temperatures over the course of a day can be modeled as a sinusoidal function. Suppose the high temperature of ?105°F??105°F? occurs at 5PM and the average temperature for the day is ?85°F.??85°F.? Find the temperature, to the nearest degree, at 9AM.
Karlee Reply
if you have the amplitude and the period and the phase shift ho would you know where to start and where to end?
Jean Reply
rotation by 80 of (x^2/9)-(y^2/16)=1
Garrett Reply
thanks the domain is good but a i would like to get some other examples of how to find the range of a function
bashiir Reply
what is the standard form if the focus is at (0,2) ?
Lorejean Reply
a²=4
Roy Reply
hil
Roy Reply
hi
Roy Reply
A bridge is to be built in the shape of a semi-elliptical arch and is to have a span of 120 feet. The height of the arch at a distance of 40 feet from the center is to be 8 feet. Find the height of the arch at its center
Abdulfatah Reply
Practice Key Terms 1

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Source:  OpenStax, Precalculus. OpenStax CNX. Jan 19, 2016 Download for free at https://legacy.cnx.org/content/col11667/1.6
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