# 6.6 Exponential and logarithmic equations  (Page 6/8)

 Page 6 / 8

How long will it take before twenty percent of our 1000-gram sample of uranium-235 has decayed?

Access these online resources for additional instruction and practice with exponential and logarithmic equations.

## Key equations

 One-to-one property for exponential functions For any algebraic expressions and and any positive real number where if and only if Definition of a logarithm For any algebraic expression S and positive real numbers and where if and only if One-to-one property for logarithmic functions For any algebraic expressions S and T and any positive real number where if and only if

## Key concepts

• We can solve many exponential equations by using the rules of exponents to rewrite each side as a power with the same base. Then we use the fact that exponential functions are one-to-one to set the exponents equal to one another and solve for the unknown.
• When we are given an exponential equation where the bases are explicitly shown as being equal, set the exponents equal to one another and solve for the unknown. See [link] .
• When we are given an exponential equation where the bases are not explicitly shown as being equal, rewrite each side of the equation as powers of the same base, then set the exponents equal to one another and solve for the unknown. See [link] , [link] , and [link] .
• When an exponential equation cannot be rewritten with a common base, solve by taking the logarithm of each side. See [link] .
• We can solve exponential equations with base $\text{\hspace{0.17em}}e,$ by applying the natural logarithm of both sides because exponential and logarithmic functions are inverses of each other. See [link] and [link] .
• After solving an exponential equation, check each solution in the original equation to find and eliminate any extraneous solutions. See [link] .
• When given an equation of the form $\text{\hspace{0.17em}}{\mathrm{log}}_{b}\left(S\right)=c,\text{}$ where $\text{\hspace{0.17em}}S\text{\hspace{0.17em}}$ is an algebraic expression, we can use the definition of a logarithm to rewrite the equation as the equivalent exponential equation $\text{\hspace{0.17em}}{b}^{c}=S,\text{}$ and solve for the unknown. See [link] and [link] .
• We can also use graphing to solve equations with the form $\text{\hspace{0.17em}}{\mathrm{log}}_{b}\left(S\right)=c.\text{\hspace{0.17em}}$ We graph both equations $\text{\hspace{0.17em}}y={\mathrm{log}}_{b}\left(S\right)\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}y=c\text{\hspace{0.17em}}$ on the same coordinate plane and identify the solution as the x- value of the intersecting point. See [link] .
• When given an equation of the form $\text{\hspace{0.17em}}{\mathrm{log}}_{b}S={\mathrm{log}}_{b}T,\text{}$ where $\text{\hspace{0.17em}}S\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}T\text{\hspace{0.17em}}$ are algebraic expressions, we can use the one-to-one property of logarithms to solve the equation $\text{\hspace{0.17em}}S=T\text{\hspace{0.17em}}$ for the unknown. See [link] .
• Combining the skills learned in this and previous sections, we can solve equations that model real world situations, whether the unknown is in an exponent or in the argument of a logarithm. See [link] .

## Verbal

How can an exponential equation be solved?

Determine first if the equation can be rewritten so that each side uses the same base. If so, the exponents can be set equal to each other. If the equation cannot be rewritten so that each side uses the same base, then apply the logarithm to each side and use properties of logarithms to solve.

the gradient function of a curve is 2x+4 and the curve passes through point (1,4) find the equation of the curve
1+cos²A/cos²A=2cosec²A-1
test for convergence the series 1+x/2+2!/9x3
a man walks up 200 meters along a straight road whose inclination is 30 degree.How high above the starting level is he?
100 meters
Kuldeep
Find that number sum and product of all the divisors of 360
Ajith
exponential series
Naveen
what is subgroup
Prove that: (2cos&+1)(2cos&-1)(2cos2&-1)=2cos4&+1
e power cos hyperbolic (x+iy)
10y
Michael
tan hyperbolic inverse (x+iy)=alpha +i bita
prove that cos(π/6-a)*cos(π/3+b)-sin(π/6-a)*sin(π/3+b)=sin(a-b)
why {2kπ} union {kπ}={kπ}?
why is {2kπ} union {kπ}={kπ}? when k belong to integer
Huy
if 9 sin theta + 40 cos theta = 41,prove that:41 cos theta = 41
what is complex numbers
Dua
Yes
ahmed
Thank you
Dua
give me treganamentry question
Solve 2cos x + 3sin x = 0.5