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What rocket thrust accelerates this sled?

Before manned space flights, rocket sleds were used to test aircraft, missile equipment, and physiological effects on human subjects at high speeds. They consisted of a platform that was mounted on one or two rails and propelled by several rockets.

Calculate the magnitude of force exerted by each rocket, called its thrust T , for the four-rocket propulsion system shown in [link] . The sled’s initial acceleration is 49 m/s 2 , the mass of the system is 2100 kg, and the force of friction opposing the motion is 650 N.

Figure shows a sled going right. It has four rockets at the back, with each thrust vector having the same magnitude and pointing right. Friction f points left. The upward normal force N and downward weight, are both equal in magnitude. Acceleration a is towards the right. All these forces are also shown in a free body diagram.
A sled experiences a rocket thrust that accelerates it to the right. Each rocket creates an identical thrust T . The system here is the sled, its rockets, and its rider, so none of the forces between these objects are considered. The arrow representing friction ( f ) is drawn larger than scale.

Strategy

Although forces are acting both vertically and horizontally, we assume the vertical forces cancel because there is no vertical acceleration. This leaves us with only horizontal forces and a simpler one-dimensional problem. Directions are indicated with plus or minus signs, with right taken as the positive direction. See the free-body diagram in [link] .

Solution

Since acceleration, mass, and the force of friction are given, we start with Newton’s second law and look for ways to find the thrust of the engines. We have defined the direction of the force and acceleration as acting “to the right,” so we need to consider only the magnitudes of these quantities in the calculations. Hence we begin with

F net = m a

where F net is the net force along the horizontal direction. We can see from the figure that the engine thrusts add, whereas friction opposes the thrust. In equation form, the net external force is

F net = 4 T f .

Substituting this into Newton’s second law gives us

F net = m a = 4 T f .

Using a little algebra, we solve for the total thrust 4 T :

4 T = m a + f .

Substituting known values yields

4 T = m a + f = ( 2100 kg ) ( 49 m / s 2 ) + 650 N .

Therefore, the total thrust is

4 T = 1.0 × 10 5 N ,

and the individual thrusts are

T = 1.0 × 10 5 N 4 = 2.5 × 10 4 N .

Significance

The numbers are quite large, so the result might surprise you. Experiments such as this were performed in the early 1960s to test the limits of human endurance, and the setup was designed to protect human subjects in jet fighter emergency ejections. Speeds of 1000 km/h were obtained, with accelerations of 45 g ’s. (Recall that g , acceleration due to gravity, is 9.80 m/s 2 . When we say that acceleration is 45 g ’s, it is 45 × 9.8 m/s 2 , which is approximately 440 m/s 2 .) Although living subjects are not used anymore, land speeds of 10,000 km/h have been obtained with a rocket sled.

In this example, as in the preceding one, the system of interest is obvious. We see in later examples that choosing the system of interest is crucial—and the choice is not always obvious.

Newton’s second law is more than a definition; it is a relationship among acceleration, force, and mass. It can help us make predictions. Each of those physical quantities can be defined independently, so the second law tells us something basic and universal about nature.

Practice Key Terms 1

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Source:  OpenStax, University physics volume 1. OpenStax CNX. Sep 19, 2016 Download for free at http://cnx.org/content/col12031/1.5
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