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Answer and Explanation

Question 4

What output is produced by the program shown in Listing 4 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. 2147483647
  • D. 2.147483647E9
Listing 4 . Listing for Question 4.
public class Ap013{ public static void main(String args[]){new Worker().doAsg(); }//end main()}//end class definition class Worker{public void doAsg(){ //Integer.MAX_VALUE = 2147483647double myDoubleVar = Integer.MAX_VALUE;int myIntVar; myIntVar = (int)myDoubleVar;System.out.println(myIntVar); }//end doAsg()}//end class definition

Answer and Explanation

Question 5

What output is produced by the program shown in Listing 5 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. 4.294967294E9
  • D. 4294967294
Listing 5 . Listing for Question 5.
public class Ap014{ public static void main(String args[]){new Worker().doMixed(); }//end main()}//end class definition class Worker{public void doMixed(){ //Integer.MAX_VALUE = 2147483647int myIntVar = Integer.MAX_VALUE; System.out.println(2.0 * myIntVar);}//end doMixed() }//end class definition

Answer and Explanation

Question 6

What output is produced by the program shown in Listing 6 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. 2147483649
  • D. -2147483647
Listing 6 . Listing for Question 6.
public class Ap015{ public static void main(String args[]){new Worker().doMixed(); }//end main()}//end class definition class Worker{public void doMixed(){ //Integer.MAX_VALUE = 2147483647int myVar01 = Integer.MAX_VALUE; int myVar02 = 2;System.out.println( myVar01 + myVar02);}//end doMixed() }//end class definition

Answer and Explanation

Question 7

What output is produced by the program shown in Listing 7 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. 33.666666
  • D. 34
  • E. 33
Listing 7 . Listing for Question 7.
public class Ap016{ public static void main(String args[]){new Worker().doMixed(); }//end main()}//end class definition class Worker{public void doMixed(){ int myVar01 = 101;int myVar02 = 3; System.out.println(myVar01/myVar02); }//end doMixed()}//end class definition

Answer and Explanation

Question 8

What output is produced by the program shown in Listing 8 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. Infinity
  • D. 11
Listing 8 . Listing for Question 8.
public class Ap017{ public static void main(String args[]){new Worker().doMixed(); }//end main()}//end class definition class Worker{public void doMixed(){ int myVar01 = 11;int myVar02 = 0; System.out.println(myVar01/myVar02); }//end doMixed()}//end class definition

Answer and Explanation

Question 9

What output is produced by the program shown in Listing 9 ?

  • A. Compiler Error
  • B. Runtime Error
  • C. Infinity
  • D. 11
Listing 9 . Listing for Question 9.
public class Ap018{ public static void main(String args[]){new Worker().doMixed(); }//end main()}//end class definition class Worker{public void doMixed(){ double myVar01 = 11;double myVar02 = 0; System.out.println(myVar01/myVar02); }//end doMixed()}//end class definition

Answer and Explanation

Question 10

What output is produced by the program shown in Listing 10 ?

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
Emedobi Reply
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
Mary Reply
is it 3×y ?
Joan Reply
J, combine like terms 7x-4y
Bridget Reply
im not good at math so would this help me
Rachael Reply
how did I we'll learn this
Noor Reply
f(x)= 2|x+5| find f(-6)
Prince Reply
f(n)= 2n + 1
Samantha Reply
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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