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(Note however, that you may not see the zero-valued points in the spectrum if you don't compute the spectral values at exactly those frequencyvalues. This is the case for some of the plots in Figure 11 .)

The frequency resolution of the Fourier transform

Some analysts regard a frequency interval equal to the reciprocal of the length of the time series as being the useful resolution of the spectrumanalysis process.

In other words, two peaks in the spectrum cannot be resolved if the frequency difference between them is less than the reciprocal of the length of the timeseries.

Illustration of frequency resolution

This is illustrated by the plots in Figure 15 . Figure 15 is similar to Figure 13 with one major difference. In Figure 13 , the frequency difference between the two sinusoids that made up each of the time series was rather large. In Figure 15 , the frequency difference between the two sinusoids that made up each of the time series was reduced to 1/400, (the reciprocal of the length of the longest time series).

Figure 15. Illustration of frequency resolution.
missing image

Each plot in Figure 15 shows the first 50 points produced by performing a Fourier transform on one of the time series. In each case, the time seriesconsisted of the sum of two sinusoids with a frequency separation of 1/400.

A match for the frequency resolution

The length of the time series for the bottom plot was 400 samples. Thus, the separation of the two sinusoids matched the frequency resolution available by performing a Fourier transform on that time series.

As you can see, the two peaks in the spectrum were resolved by the bottom plot in Figure 15 .

Insufficient frequency resolution

The other four time series were shorter, having lengths of 80, 160, 240, and 320 samples respectively, from top to bottom.

The important thing to note in Figure 15 is that the spectrum analysis performed on the 400-sample time series was successful in separating the twopeaks.

However, even though the spectrum analysis on the 320-sample time series hinted at a separation of the peaks, none of the spectrum analyses on the timeseries that were shorter than 400 samples successfully separated the peaks.

This illustrates that the frequency resolution of the Fourier transform is the reciprocal of the length of the time series.

Sufficient resolution in all five cases

I'm going to show you one more picture and then call it a wrap for this module. Figure 16 is similar to Figure 15 with one major difference.

Figure 16. Illustration of frequency resolution.
missing image

As before, the five plots in Figure 16 show the first 50 points produced by performing a Fourier transform on five different time series. Starting at thetop, the lengths of the time series were 80, 160, 240, 320, and 400 samples.

Adequate frequency resolution in all cases

Also as before, each time series was the sum of two sinusoids with closely-spaced frequencies. However, in Figure 16 , the difference between the sinusoidal frequencies was different from one time series to the next.

In Figure 16 , the frequency difference for the sinusoids contained in each time series was the reciprocal of the length of that particular time series.Therefore, the frequency difference for each case matched the frequency resolution of the Fourier transform.

The frequency of the lower-frequency peak was the same in all five cases. Therefore, this peak should line up vertically for the five plots in Figure 16 .

The frequency difference between the sinusoids was achieved by increasing the higher frequency by an amount equal to the reciprocal of the length of the timeseries.

Peaks were resolved in all five cases

If you examine Figure 16 , you will see that the peaks corresponding to the two sinusoids were resolved for all five time series.

As would be expected, the peaks appear to be broader for the shorter time series having the lower frequency resolution. The peaks are also separated inall five cases. However, the peaks for the lower-frequency sinusoid don't exactly line up vertically. Thus we see a small amount of measurement error inthe positions of the peaks

Summary

This module has presented a pseudo-mathematical discussion of issues involving the averaging of time series, and the impact of those issues onspectrum analysis.

Those averaging issues have an impact on many other areas of DSP as well, but the detrimental effect is probably more obvious in spectrum analysis than in otherareas.

Miscellaneous

This section contains a variety of miscellaneous information.

Housekeeping material
  • Module name: Dsp00108: Digital Signal Processing (DSP) in Java, Averaging Time Series
  • File: Dsp00108.htm
  • Published: 12/11/02

Baldwin begins with a discussion of averaging time series, and ends with a discussion of spectral resolution, covering several related topics in between.

Disclaimers:

Financial : Although the Connexions site makes it possible for you to download a PDF file for thismodule at no charge, and also makes it possible for you to purchase a pre-printed version of the PDF file, you should beaware that some of the HTML elements in this module may not translate well into PDF.

I also want you to know that, I receive no financial compensation from the Connexions website even if you purchase the PDF version of the module.

In the past, unknown individuals have copied my modules from cnx.org, converted them to Kindle books, and placed them for sale on Amazon.com showing me as the author. Ineither receive compensation for those sales nor do I know who does receive compensation. If you purchase such a book, please beaware that it is a copy of a module that is freely available on cnx.org and that it was made and published withoutmy prior knowledge.

Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.

-end-

Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
Haryormhidey Reply
how many start and codon
Esrael Reply
what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
Nassze Reply
how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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