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y = x*x
Listing 6 . The method named function for Parabola01. double function(double xVal){ double yVal = xVal*xVal;return yVal; }//end function

A plot of the output of the method named function would look like the curve shown in Figure 7 with no offsets if the x and y scaling values were set to one-half the width and height of the world respectively.

Figure 7. Parabola with zero offsets.

Missing image

It will be instructive to see how this program uses offsets and scaling values to transform the image shown in Figure 7 into the image shown in Figure 6 .

Drawing parameters for Parabola01

The code fragment shown in Listing 7 shows the drawing parameters that were used to produce the output shown in Figure 6 .

Listing 7 . Drawing parameters for Parabola01. double xOff = 0.25;//offset relative to 1.0 double yOff = -0.25;double xScale = 0.75*world.getWidth()/2; double yScale = 1.25*world.getHeight()/2;

Drawing parameters with zero offsets

The parameters that were used to produce the output shown in Figure 7 are shown below:

double xOff = 0.0;//offset relative to 1.0 double yOff = -0.0;double xScale = 1.0*world.getWidth()/2; double yScale = 1.0*world.getHeight()/2;

Note in particular that the offsets given by xOff and yOff are set to zero and the scale factors given by xScale and yScale are one-half the width and height of the world respectively.

Changing the offset values

Increasing the offsets for xOff and yOff to 0.25 and -0.25 respectively as shown in Figure 7 and making no other changes produces the output shown in Figure 8

Figure 8. A parabola with offsets.

Missing image

In comparison with Figure 7 , changing the value of xOff to 0.25 caused the peak to move to the right (positive direction) one-fourth of the way from the center origin to the right edge of the world. (That change also caused a portion of the curve to fall outside the right boundary of the world.)

Similarly, changing the value of yOff to -0.25 caused the peak to move up (negative direction) one-fourth of the way from the center origin to the top edge of the world.

Changing the scale factors

Following that, changing the values of xScale and yScale to the values shown in Listing 7 produces the graphic output shown in Figure 6 . The change in xScale decreased the total width of the curve and prevented it from exceeding the rightmost boundary of theworld. The change in yScale increased the overall height of the curve causing it to almost touch the lower boundary of the world.

Draw the parabolic function in BLUE

The code in Listing 8 draws the blue parabolic function shown in Figure 6 .

Listing 8 . Draw the parabolic function in BLUE. double yVal = 0; int row = 0;int col = 0; double xVal = -1;turtle.setPenColor(Color.BLUE); for(int cnt=0; cnt<=100;cnt++,xVal += 0.02){ //Get a y-value for the given x-value.yVal = function(xVal); //Apply the offsets and scale the resultscol = (int)((xOff+xVal)*xScale); row = (int)((yOff+yVal)*yScale);//Move to the first point without drawing a line because the// pen is not down. Translate the origin to the center in the // process.turtle.moveTo(col + world.getWidth()/2, row + world.getHeight()/2);//Lower the pen in order to draw a line from each point to the // next point.turtle.penDown(); }//end for loop}//end run method

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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