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Access the following online resource for additional instruction and practice with graphing polynomial functions.

Key concepts

  • Polynomial functions of degree 2 or more are smooth, continuous functions. See [link] .
  • To find the zeros of a polynomial function, if it can be factored, factor the function and set each factor equal to zero. See [link] , [link] , and [link] .
  • Another way to find the x - intercepts of a polynomial function is to graph the function and identify the points at which the graph crosses the x - axis. See [link] .
  • The multiplicity of a zero determines how the graph behaves at the x - intercepts. See [link] .
  • The graph of a polynomial will cross the horizontal axis at a zero with odd multiplicity.
  • The graph of a polynomial will touch the horizontal axis at a zero with even multiplicity.
  • The end behavior of a polynomial function depends on the leading term.
  • The graph of a polynomial function changes direction at its turning points.
  • A polynomial function of degree n has at most n 1 turning points. See [link] .
  • To graph polynomial functions, find the zeros and their multiplicities, determine the end behavior, and ensure that the final graph has at most n 1 turning points. See [link] and [link] .
  • Graphing a polynomial function helps to estimate local and global extremas. See [link] .
  • The Intermediate Value Theorem tells us that if f ( a )   and   f ( b ) have opposite signs, then there exists at least one value c between a and b for which f ( c ) = 0. See [link] .

Section exercises

Verbal

What is the difference between an x - intercept and a zero of a polynomial function f ?

The x - intercept is where the graph of the function crosses the x - axis, and the zero of the function is the input value for which f ( x ) = 0.

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If a polynomial function of degree n has n distinct zeros, what do you know about the graph of the function?

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Explain how the Intermediate Value Theorem can assist us in finding a zero of a function.

If we evaluate the function at a and at b and the sign of the function value changes, then we know a zero exists between a and b .

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Explain how the factored form of the polynomial helps us in graphing it.

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If the graph of a polynomial just touches the x -axis and then changes direction, what can we conclude about the factored form of the polynomial?

There will be a factor raised to an even power.

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Algebraic

For the following exercises, find the x - or t -intercepts of the polynomial functions.

C ( t ) = 2 ( t 4 ) ( t + 1 ) ( t 6 )

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C ( t ) = 3 ( t + 2 ) ( t 3 ) ( t + 5 )

( 2 , 0 ) , ( 3 , 0 ) , ( 5 , 0 )

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C ( t ) = 4 t ( t 2 ) 2 ( t + 1 )

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C ( t ) = 2 t ( t 3 ) ( t + 1 ) 2

( 3 , 0 ) , ( 1 , 0 ) , ( 0 , 0 )

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C ( t ) = 2 t 4 8 t 3 + 6 t 2

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C ( t ) = 4 t 4 + 12 t 3 40 t 2

( 0 , 0 ) ,   ( 5 , 0 ) ,   ( 2 , 0 )

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f ( x ) = x 4 x 2

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f ( x ) = x 3 + x 2 20 x

( 0 , 0 ) ,   ( 5 , 0 ) ,   ( 4 , 0 )

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f ( x ) = x 3 + 6 x 2 7 x

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f ( x ) = x 3 + x 2 4 x 4

( 2 , 0 ) ,   ( 2 , 0 ) ,   ( 1 , 0 )

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f ( x ) = x 3 + 2 x 2 9 x 18

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f ( x ) = 2 x 3 x 2 8 x + 4

( 2 , 0 ) , ( 2 , 0 ) , ( 1 2 , 0 )

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f ( x ) = x 6 7 x 3 8

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f ( x ) = 2 x 4 + 6 x 2 8

( 1 , 0 ) ,   ( 1 , 0 )

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f ( x ) = x 3 3 x 2 x + 3

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f ( x ) = x 6 2 x 4 3 x 2

( 0 , 0 ) , ( 3 , 0 ) , ( 3 , 0 )

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f ( x ) = x 6 3 x 4 4 x 2

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f ( x ) = x 5 5 x 3 + 4 x

( 0 , 0 ) ,   ( 1 , 0 ) ( 1 , 0 ) ,   ( 2 , 0 ) ,   ( 2 , 0 )

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For the following exercises, use the Intermediate Value Theorem to confirm that the given polynomial has at least one zero within the given interval.

f ( x ) = x 3 9 x , between x = −4 and x = −2.

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f ( x ) = x 3 9 x , between x = 2 and x = 4.

f ( 2 ) = 10 and f ( 4 ) = 28. Sign change confirms.

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Questions & Answers

the gradient function of a curve is 2x+4 and the curve passes through point (1,4) find the equation of the curve
Kc Reply
1+cos²A/cos²A=2cosec²A-1
Ramesh Reply
test for convergence the series 1+x/2+2!/9x3
success Reply
a man walks up 200 meters along a straight road whose inclination is 30 degree.How high above the starting level is he?
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100 meters
Kuldeep
Find that number sum and product of all the divisors of 360
jancy Reply
answer
Ajith
exponential series
Naveen
what is subgroup
Purshotam Reply
Prove that: (2cos&+1)(2cos&-1)(2cos2&-1)=2cos4&+1
Macmillan Reply
e power cos hyperbolic (x+iy)
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10y
Michael
tan hyperbolic inverse (x+iy)=alpha +i bita
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prove that cos(π/6-a)*cos(π/3+b)-sin(π/6-a)*sin(π/3+b)=sin(a-b)
Tejas Reply
why {2kπ} union {kπ}={kπ}?
Huy Reply
why is {2kπ} union {kπ}={kπ}? when k belong to integer
Huy
if 9 sin theta + 40 cos theta = 41,prove that:41 cos theta = 41
Trilochan Reply
what is complex numbers
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Solve 2cos x + 3sin x = 0.5
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Practice Key Terms 4

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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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