<< Chapter < Page Chapter >> Page >

Write each of the following products with a single base. Do not simplify further.

  1. k 6 k 9
  2. ( 2 y ) 4 ( 2 y )
  3. t 3 t 6 t 5
  1. k 15
  2. ( 2 y ) 5
  3. t 14
Got questions? Get instant answers now!

Using the quotient rule of exponents

The quotient rule of exponents allows us to simplify an expression that divides two numbers with the same base but different exponents. In a similar way to the product rule, we can simplify an expression such as y m y n , where m > n . Consider the example y 9 y 5 . Perform the division by canceling common factors.

y 9 y 5 = y y y y y y y y y y y y y y = y y y y y y y y y y y y y y = y y y y 1 = y 4

Notice that the exponent of the quotient is the difference between the exponents of the divisor and dividend.

a m a n = a m n

In other words, when dividing exponential expressions with the same base, we write the result with the common base and subtract the exponents.

y 9 y 5 = y 9 5 = y 4

For the time being, we must be aware of the condition m > n . Otherwise, the difference m n could be zero or negative. Those possibilities will be explored shortly. Also, instead of qualifying variables as nonzero each time, we will simplify matters and assume from here on that all variables represent nonzero real numbers.

The quotient rule of exponents

For any real number a and natural numbers m and n , such that m > n , the quotient rule of exponents states that

a m a n = a m n

Using the quotient rule

Write each of the following products with a single base. Do not simplify further.

  1. ( −2 ) 14 ( −2 ) 9
  2. t 23 t 15
  3. ( z 2 ) 5 z 2

Use the quotient rule to simplify each expression.

  1. ( −2 ) 14 ( −2 ) 9 = ( −2 ) 14 9 = ( −2 ) 5
  2. t 23 t 15 = t 23 15 = t 8
  3. ( z 2 ) 5 z 2 = ( z 2 ) 5 1 = ( z 2 ) 4
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Write each of the following products with a single base. Do not simplify further.

  1. s 75 s 68
  2. ( −3 ) 6 −3
  3. ( e f 2 ) 5 ( e f 2 ) 3
  1. s 7
  2. ( −3 ) 5
  3. ( e f 2 ) 2
Got questions? Get instant answers now!

Using the power rule of exponents

Suppose an exponential expression is raised to some power. Can we simplify the result? Yes. To do this, we use the power rule of exponents . Consider the expression ( x 2 ) 3 . The expression inside the parentheses is multiplied twice because it has an exponent of 2. Then the result is multiplied three times because the entire expression has an exponent of 3.

( x 2 ) 3 = ( x 2 ) ( x 2 ) ( x 2 ) 3  factors = ( x x 2  factors ) ( x x 2  factors ) ( x x 2  factors ) 3  factors = x x x x x x = x 6

The exponent of the answer is the product of the exponents: ( x 2 ) 3 = x 2 3 = x 6 . In other words, when raising an exponential expression to a power, we write the result with the common base and the product of the exponents.

( a m ) n = a m n

Be careful to distinguish between uses of the product rule and the power rule. When using the product rule, different terms with the same bases are raised to exponents. In this case, you add the exponents. When using the power rule, a term in exponential notation is raised to a power. In this case, you multiply the exponents.

Product Rule  Power Rule 5 3 5 4 = 5 3 + 4 = 5 7 but   ( 5 3 ) 4 = 5 3 4 = 5 12 x 5 x 2 = x 5 + 2 = x 7 but ( x 5 ) 2 = x 5 2 = x 10 ( 3 a ) 7 ( 3 a ) 10 = ( 3 a ) 7 + 10 = ( 3 a ) 17 but ( ( 3 a ) 7 ) 10 = ( 3 a ) 7 10 = ( 3 a ) 70

The power rule of exponents

For any real number a and positive integers m and n , the power rule of exponents states that

( a m ) n = a m n

Using the power rule

Write each of the following products with a single base. Do not simplify further.

  1. ( x 2 ) 7
  2. ( ( 2 t ) 5 ) 3
  3. ( ( −3 ) 5 ) 11

Use the power rule to simplify each expression.

  1. ( x 2 ) 7 = x 2 7 = x 14
  2. ( ( 2 t ) 5 ) 3 = ( 2 t ) 5 3 = ( 2 t ) 15
  3. ( ( −3 ) 5 ) 11 = ( −3 ) 5 11 = ( −3 ) 55
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
khuthadzo hii
Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
please help me with vectors in two dimensions
Mulaudzi Reply
how to calculate normal force
Mulaudzi
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 1

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Algebra and trigonometry' conversation and receive update notifications?

Ask