



If we assume the linear trend existed before 1950 and continues after 2000, the two states’ median house values will be (or were) equal in what year? (The answer might be absurd.)
Got questions? Get instant answers now!
For the following exercises, use the median home values in Indiana and Alabama (adjusted for inflation) shown in
[link] . Assume that the house values are changing linearly.
Year 
Indiana 
Alabama 
1950 
$37,700 
$27,100 
2000 
$94,300 
$85,100 
If we assume the linear trend existed before 1950 and continues after 2000, the two states’ median house values will be (or were) equal in what year? (The answer might be absurd.)
Got questions? Get instant answers now!
Realworld applications
In 2004, a school population was 1001. By 2008 the population had grown to 1697. Assume the population is changing linearly.
 How much did the population grow between the year 2004 and 2008?
 How long did it take the population to grow from 1001 students to 1697 students?
 What is the average population growth per year?
 What was the population in the year 2000?
 Find an equation for the population,
$\text{\hspace{0.17em}}P,$ of the school
t years after 2000.
 Using your equation, predict the population of the school in 2011.
Got questions? Get instant answers now!
In 2003, a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.
 How much did the population grow between the year 2003 and 2007?
 How long did it take the population to grow from 1431 people to 2134 people?
 What is the average population growth per year?
 What was the population in the year 2000?
 Find an equation for the population,
$\text{\hspace{0.17em}}P,$ of the town
$\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ years after 2000.
 Using your equation, predict the population of the town in 2014.

$21341431=703\text{\hspace{0.17em}}$ people

$20072003=4\text{\hspace{0.17em}}$ years
 Average rate of growth
$\text{\hspace{0.17em}}=\frac{703}{4}=175.75\text{\hspace{0.17em}}$ people per year
So, using
$\text{\hspace{0.17em}}y=mx+b,$ we have
$\text{\hspace{0.17em}}y=175.75x+1431.$
 The year 2000 corresponds to
$\text{\hspace{0.17em}}t=3.$
So,
$\text{\hspace{0.17em}}y=175.75(3)+1431=903.75\text{\hspace{0.17em}}$ or roughly 904 people in year 2000
 If the year 2000 corresponds to
$\text{\hspace{0.17em}}t\text{=0,}$ then we have ordered pair
$\text{\hspace{0.17em}}(0,903.75)$
$y=175.75x+903.75\text{\hspace{0.17em}}$ corresponds to
$\text{\hspace{0.17em}}P(t)=175.75t+903.75$
 The year 2014 corresponds to
$\text{\hspace{0.17em}}t=14.\text{\hspace{0.17em}}$ Therefore,
$\text{\hspace{0.17em}}P(14)=175.75(14)+903.75=3364.25$ .
So, a population of 3364.
Got questions? Get instant answers now!
A phone company has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 410 minutes, the monthly cost will be $71.50. If the customer uses 720 minutes, the monthly cost will be $118.
 Find a linear equation for the monthly cost of the cell plan as a function of
x , the number of monthly minutes used.
 Interpret the slope and
y intercept of the equation.
 Use your equation to find the total monthly cost if 687 minutes are used.
Got questions? Get instant answers now!
A phone company has a monthly cellular data plan where a customer pays a flat monthly fee of $10 and then a certain amount of money per megabyte (MB) of data used on the phone. If a customer uses 20 MB, the monthly cost will be $11.20. If the customer uses 130 MB, the monthly cost will be $17.80.
 Find a linear equation for the monthly cost of the data plan as a function of
$\text{\hspace{0.17em}}x,$ the number of MB used.
 Interpret the slope and
y intercept of the equation.
 Use your equation to find the total monthly cost if 250 MB are used.

$\begin{array}{l}\text{Orderedpairsare}(20,11.20)\text{and}(130,17.80)\hfill \\ \\ \begin{array}{ccc}\hfill m& =& \frac{17.8011.20}{13020}=0.06\text{and}(0,10)\hfill \\ \hfill y& =& mx+b\hfill \\ \hfill y& =& 0.06x+10\text{or}C(x)=0.06x+10\hfill \end{array}\end{array}$
 0.06 For every MB, the client is charged 6 cents.
$\text{\hspace{0.17em}}(0,10)\text{\hspace{0.17em}}$ If no usage occurs, the client is charged $10

$\begin{array}{ccc}\hfill C(250)& =& 0.06(250)+10\hfill \\ & =& \$25\hfill \end{array}$
Got questions? Get instant answers now!
Questions & Answers
In a triangle ABC prove that. (b+c)cosA+(c+a)cosB+(a+b)cisC=a+b+c.
give me the waec 2019 questions
the polar coordinate of the point (1, 1)
prove the identites sin x ( 1+ tan x )+ cos x ( 1+ cot x )= sec x + cosec x
tanh`(xiy) =A+iB, find A and B
B=Aiitan(hxhiy)
Rukmini
what is the addition of 101011 with 101010
If those numbers are binary, it's 1010101. If they are base 10, it's 202021.
Jack
extra power 4 minus 5 x cube + 7 x square minus 5 x + 1 equal to zero
the gradient function of a curve is 2x+4 and the curve passes through point (1,4) find the equation of the curve
test for convergence the series 1+x/2+2!/9x3
a man walks up 200 meters along a straight road whose inclination is 30 degree.How high above the starting level is he?
Find that number sum and product of all the divisors of 360
exponential series
Naveen
Prove that: (2cos&+1)(2cos&1)(2cos2&1)=2cos4&+1
e power cos hyperbolic (x+iy)
Source:
OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
Google Play and the Google Play logo are trademarks of Google Inc.