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The domain of function $\text{\hspace{0.17em}}f\text{\hspace{0.17em}}$ is $\text{\hspace{0.17em}}(1,\infty )\text{\hspace{0.17em}}$ and the range of function $\text{\hspace{0.17em}}f\text{\hspace{0.17em}}$ is $\text{\hspace{0.17em}}(\mathrm{-\infty},\mathrm{-2}).\text{\hspace{0.17em}}$ Find the domain and range of the inverse function.
The domain of function $\text{\hspace{0.17em}}{f}^{-1}\text{\hspace{0.17em}}$ is $\text{\hspace{0.17em}}(-\infty \text{,}-2)\text{\hspace{0.17em}}$ and the range of function $\text{\hspace{0.17em}}{f}^{-1}\text{\hspace{0.17em}}$ is $\text{\hspace{0.17em}}(1,\infty ).$
Once we have a one-to-one function, we can evaluate its inverse at specific inverse function inputs or construct a complete representation of the inverse function in many cases.
Suppose we want to find the inverse of a function represented in table form. Remember that the domain of a function is the range of the inverse and the range of the function is the domain of the inverse. So we need to interchange the domain and range.
Each row (or column) of inputs becomes the row (or column) of outputs for the inverse function. Similarly, each row (or column) of outputs becomes the row (or column) of inputs for the inverse function.
A function $\text{\hspace{0.17em}}f(t)\text{\hspace{0.17em}}$ is given in [link] , showing distance in miles that a car has traveled in $\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ minutes. Find and interpret $\text{\hspace{0.17em}}{f}^{-1}(70).$
$t\text{(minutes)}$ | 30 | 50 | 70 | 90 |
$f\left(t\right)\text{(miles)}$ | 20 | 40 | 60 | 70 |
The inverse function takes an output of $\text{\hspace{0.17em}}f\text{\hspace{0.17em}}$ and returns an input for $\text{\hspace{0.17em}}f.\text{\hspace{0.17em}}$ So in the expression $\text{\hspace{0.17em}}{f}^{-1}(70),\text{\hspace{0.17em}}$ 70 is an output value of the original function, representing 70 miles. The inverse will return the corresponding input of the original function $\text{\hspace{0.17em}}f,\text{\hspace{0.17em}}$ 90 minutes, so $\text{\hspace{0.17em}}{f}^{-1}(70)=90.\text{\hspace{0.17em}}$ The interpretation of this is that, to drive 70 miles, it took 90 minutes.
Alternatively, recall that the definition of the inverse was that if $\text{\hspace{0.17em}}f(a)=b,\text{\hspace{0.17em}}$ then $\text{\hspace{0.17em}}{f}^{-1}(b)=a.\text{\hspace{0.17em}}$ By this definition, if we are given $\text{\hspace{0.17em}}{f}^{-1}(70)=a,\text{\hspace{0.17em}}$ then we are looking for a value $\text{\hspace{0.17em}}a\text{\hspace{0.17em}}$ so that $\text{\hspace{0.17em}}f(a)=70.\text{\hspace{0.17em}}$ In this case, we are looking for a $\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ so that $\text{\hspace{0.17em}}f(t)=70,\text{\hspace{0.17em}}$ which is when $\text{\hspace{0.17em}}t=90.$
Using [link] , find and interpret (a) $\text{}f(60),$ and (b) $\text{}{f}^{-1}(60).$
$t\text{(minutes)}$ | 30 | 50 | 60 | 70 | 90 |
$f\left(t\right)\text{(miles)}$ | 20 | 40 | 50 | 60 | 70 |
We saw in Functions and Function Notation that the domain of a function can be read by observing the horizontal extent of its graph. We find the domain of the inverse function by observing the vertical extent of the graph of the original function, because this corresponds to the horizontal extent of the inverse function. Similarly, we find the range of the inverse function by observing the horizontal extent of the graph of the original function, as this is the vertical extent of the inverse function. If we want to evaluate an inverse function, we find its input within its domain, which is all or part of the vertical axis of the original function’s graph.
Given the graph of a function, evaluate its inverse at specific points.
A function $\text{\hspace{0.17em}}g(x)\text{\hspace{0.17em}}$ is given in [link] . Find $\text{\hspace{0.17em}}g(3)\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}{g}^{-1}(3).$
To evaluate $g(3),\text{\hspace{0.17em}}$ we find 3 on the x -axis and find the corresponding output value on the y -axis. The point $\text{\hspace{0.17em}}\left(3,1\right)\text{\hspace{0.17em}}$ tells us that $\text{\hspace{0.17em}}g(3)=1.$
To evaluate $\text{\hspace{0.17em}}{g}^{-1}(3),\text{\hspace{0.17em}}$ recall that by definition $\text{\hspace{0.17em}}{g}^{-1}(3)\text{\hspace{0.17em}}$ means the value of x for which $\text{\hspace{0.17em}}g(x)=3.\text{\hspace{0.17em}}$ By looking for the output value 3 on the vertical axis, we find the point $\text{\hspace{0.17em}}\left(5,3\right)\text{\hspace{0.17em}}$ on the graph, which means $\text{\hspace{0.17em}}g(5)=3,\text{\hspace{0.17em}}$ so by definition, $\text{\hspace{0.17em}}{g}^{-1}(3)=5.\text{\hspace{0.17em}}$ See [link] .
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