# 5.6 Inverse trigonometric functions  (Page 9/15)

 Page 9 / 15

What are the amplitude, period, and phase shift for the function?

amplitude: 8,000; period: 10; phase shift: 0

Over this domain, when does the population reach 18,000? 13,000?

What is the predicted population in 2007? 2010?

In 2007, the predicted population is 4,413. In 2010, the population will be 11,924.

For the following exercises, suppose a weight is attached to a spring and bobs up and down, exhibiting symmetry.

Suppose the graph of the displacement function is shown in [link] , where the values on the x -axis represent the time in seconds and the y -axis represents the displacement in inches. Give the equation that models the vertical displacement of the weight on the spring.

At time = 0, what is the displacement of the weight?

5 in.

At what time does the displacement from the equilibrium point equal zero?

What is the time required for the weight to return to its initial height of 5 inches? In other words, what is the period for the displacement function?

10 seconds

## Inverse Trigonometric Functions

For the following exercises, find the exact value without the aid of a calculator.

${\mathrm{sin}}^{-1}\left(1\right)$

${\mathrm{cos}}^{-1}\left(\frac{\sqrt{3}}{2}\right)$

$\frac{\pi }{6}$

${\mathrm{tan}}^{-1}\left(-1\right)$

${\mathrm{cos}}^{-1}\left(\frac{1}{\sqrt{2}}\right)$

$\frac{\pi }{4}$

${\mathrm{sin}}^{-1}\left(\frac{-\sqrt{3}}{2}\right)$

${\mathrm{sin}}^{-1}\left(\mathrm{cos}\left(\frac{\pi }{6}\right)\right)$

$\frac{\pi }{3}$

${\mathrm{cos}}^{-1}\left(\mathrm{tan}\left(\frac{3\pi }{4}\right)\right)$

$\mathrm{sin}\left({\mathrm{sec}}^{-1}\left(\frac{3}{5}\right)\right)$

No solution

$\mathrm{cot}\left({\mathrm{sin}}^{-1}\left(\frac{3}{5}\right)\right)$

$\mathrm{tan}\left({\mathrm{cos}}^{-1}\left(\frac{5}{13}\right)\right)$

$\frac{12}{5}$

$\mathrm{sin}\left({\mathrm{cos}}^{-1}\left(\frac{x}{x+1}\right)\right)$

Graph $\text{\hspace{0.17em}}f\left(x\right)=\mathrm{cos}\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}f\left(x\right)=\mathrm{sec}\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ on the interval $\text{\hspace{0.17em}}\left[0,2\pi \right)\text{\hspace{0.17em}}$ and explain any observations.

The graphs are not symmetrical with respect to the line $\text{\hspace{0.17em}}y=x.\text{\hspace{0.17em}}$ They are symmetrical with respect to the $\text{\hspace{0.17em}}y$ -axis.

Graph $\text{\hspace{0.17em}}f\left(x\right)=\mathrm{sin}\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}f\left(x\right)=\mathrm{csc}\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and explain any observations.

Graph the function $f\text{\hspace{0.17em}}\left(x\right)=\frac{x}{1}-\frac{{x}^{3}}{3!}+\frac{{x}^{5}}{5!}-\frac{{x}^{7}}{7!}\text{\hspace{0.17em}}$ on the interval $\text{\hspace{0.17em}}\left[-1,1\right]\text{\hspace{0.17em}}$ and compare the graph to the graph of $\text{\hspace{0.17em}}f\left(x\right)=\mathrm{sin}\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ on the same interval. Describe any observations.

The graphs appear to be identical.

## Chapter practice test

For the following exercises, sketch the graph of each function for two full periods. Determine the amplitude, the period, and the equation for the midline.

$f\left(x\right)=0.5\mathrm{sin}\text{\hspace{0.17em}}x$

amplitude: 0.5; period: $\text{\hspace{0.17em}}2\pi ;\text{\hspace{0.17em}}$ midline $\text{\hspace{0.17em}}y=0\text{\hspace{0.17em}}$

$f\left(x\right)=5\mathrm{cos}\text{\hspace{0.17em}}x$

$f\left(x\right)=5\mathrm{sin}\text{\hspace{0.17em}}x$

amplitude: 5; period: $\text{\hspace{0.17em}}2\pi ;\text{\hspace{0.17em}}$ midline: $\text{\hspace{0.17em}}y=0$

$f\left(x\right)=\mathrm{sin}\left(3x\right)$

$f\left(x\right)=-\mathrm{cos}\left(x+\frac{\pi }{3}\right)+1$

amplitude: 1; period: $\text{\hspace{0.17em}}2\pi ;\text{\hspace{0.17em}}$ midline: $\text{\hspace{0.17em}}y=1$

$f\left(x\right)=5\mathrm{sin}\left(3\left(x-\frac{\pi }{6}\right)\right)+4$

$f\left(x\right)=3\mathrm{cos}\left(\frac{1}{3}x-\frac{5\pi }{6}\right)$

amplitude: 3; period: $\text{\hspace{0.17em}}6\pi ;\text{\hspace{0.17em}}$ midline: $\text{\hspace{0.17em}}y=0$

$f\left(x\right)=\mathrm{tan}\left(4x\right)$

$f\left(x\right)=-2\mathrm{tan}\left(x-\frac{7\pi }{6}\right)+2$

amplitude: none; period: midline: asymptotes: where is an integer

$f\left(x\right)=\pi \mathrm{cos}\left(3x+\pi \right)$

$f\left(x\right)=5\mathrm{csc}\left(3x\right)$

amplitude: none; period: midline: asymptotes: where is an integer

$f\left(x\right)=\pi \mathrm{sec}\left(\frac{\pi }{2}x\right)$

$f\left(x\right)=2\mathrm{csc}\left(x+\frac{\pi }{4}\right)-3$

amplitude: none; period: $\text{\hspace{0.17em}}2\pi ;\text{\hspace{0.17em}}$ midline: $\text{\hspace{0.17em}}y=-3$

For the following exercises, determine the amplitude, period, and midline of the graph, and then find a formula for the function.

Give in terms of a sine function.

Give in terms of a sine function.

amplitude: 2; period: 2; midline: $\text{\hspace{0.17em}}y=0;$ $f\left(x\right)=2\mathrm{sin}\left(\pi \left(x-1\right)\right)$

Give in terms of a tangent function.

For the following exercises, find the amplitude, period, phase shift, and midline.

$y=\mathrm{sin}\left(\frac{\pi }{6}x+\pi \right)-3$

amplitude: 1; period: 12; phase shift: $\text{\hspace{0.17em}}-6;\text{\hspace{0.17em}}$ midline $\text{\hspace{0.17em}}y=-3$

$y=8\mathrm{sin}\left(\frac{7\pi }{6}x+\frac{7\pi }{2}\right)+6$

The outside temperature over the course of a day can be modeled as a sinusoidal function. Suppose you know the temperature is 68°F at midnight and the high and low temperatures during the day are 80°F and 56°F, respectively. Assuming $\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ is the number of hours since midnight, find a function for the temperature, $\text{\hspace{0.17em}}D,\text{\hspace{0.17em}}$ in terms of $\text{\hspace{0.17em}}t.$

$D\left(t\right)=68-12\mathrm{sin}\left(\frac{\pi }{12}x\right)$

Water is pumped into a storage bin and empties according to a periodic rate. The depth of the water is 3 feet at its lowest at 2:00 a.m. and 71 feet at its highest, which occurs every 5 hours. Write a cosine function that models the depth of the water as a function of time, and then graph the function for one period.

For the following exercises, find the period and horizontal shift of each function.

$g\left(x\right)=3\mathrm{tan}\left(6x+42\right)$

period: $\text{\hspace{0.17em}}\frac{\pi }{6};\text{\hspace{0.17em}}$ horizontal shift: $\text{\hspace{0.17em}}-7$

$n\left(x\right)=4\mathrm{csc}\left(\frac{5\pi }{3}x-\frac{20\pi }{3}\right)$

Write the equation for the graph in [link] in terms of the secant function and give the period and phase shift.

$f\left(x\right)=\mathrm{sec}\left(\pi x\right);\text{\hspace{0.17em}}$ period: 2; phase shift: 0

If $\text{\hspace{0.17em}}\mathrm{tan}\text{\hspace{0.17em}}x=3,\text{\hspace{0.17em}}$ find $\text{\hspace{0.17em}}\mathrm{tan}\left(-x\right).$

If $\text{\hspace{0.17em}}\mathrm{sec}\text{\hspace{0.17em}}x=4,\text{\hspace{0.17em}}$ find $\text{\hspace{0.17em}}\mathrm{sec}\left(-x\right).$

$4$

For the following exercises, graph the functions on the specified window and answer the questions.

Graph $\text{\hspace{0.17em}}m\left(x\right)=\mathrm{sin}\left(2x\right)+\mathrm{cos}\left(3x\right)\text{\hspace{0.17em}}$ on the viewing window $\text{\hspace{0.17em}}\left[-10,10\right]\text{\hspace{0.17em}}$ by $\text{\hspace{0.17em}}\left[-3,3\right].\text{\hspace{0.17em}}$ Approximate the graph’s period.

Graph $\text{\hspace{0.17em}}n\left(x\right)=0.02\mathrm{sin}\left(50\pi x\right)\text{\hspace{0.17em}}$ on the following domains in $\text{\hspace{0.17em}}x:$ $\left[0,1\right]\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}\left[0,3\right].\text{\hspace{0.17em}}$ Suppose this function models sound waves. Why would these views look so different?

The views are different because the period of the wave is $\text{\hspace{0.17em}}\frac{1}{25}.\text{\hspace{0.17em}}$ Over a bigger domain, there will be more cycles of the graph.

Graph $\text{\hspace{0.17em}}f\left(x\right)=\frac{\mathrm{sin}\text{\hspace{0.17em}}x}{x}\text{\hspace{0.17em}}$ on $\text{\hspace{0.17em}}\left[-0.5,0.5\right]\text{\hspace{0.17em}}$ and explain any observations.

For the following exercises, let $\text{\hspace{0.17em}}f\left(x\right)=\frac{3}{5}\mathrm{cos}\left(6x\right).$

What is the largest possible value for $\text{\hspace{0.17em}}f\left(x\right)?$

$\frac{3}{5}$

What is the smallest possible value for $\text{\hspace{0.17em}}f\left(x\right)?$

Where is the function increasing on the interval $\text{\hspace{0.17em}}\left[0,2\pi \right]?$

On the approximate intervals $\text{\hspace{0.17em}}\left(0.5,1\right),\left(1.6,2.1\right),\left(2.6,3.1\right),\left(3.7,4.2\right),\left(4.7,5.2\right),\left(5.6,6.28\right)$

For the following exercises, find and graph one period of the periodic function with the given amplitude, period, and phase shift.

Sine curve with amplitude 3, period $\text{\hspace{0.17em}}\frac{\pi }{3},\text{\hspace{0.17em}}$ and phase shift $\text{\hspace{0.17em}}\left(h,k\right)=\left(\frac{\pi }{4},2\right)$

Cosine curve with amplitude 2, period $\text{\hspace{0.17em}}\frac{\pi }{6},\text{\hspace{0.17em}}$ and phase shift $\text{\hspace{0.17em}}\left(h,k\right)=\left(-\frac{\pi }{4},3\right)$

$f\left(x\right)=2\mathrm{cos}\left(12\left(x+\frac{\pi }{4}\right)\right)+3$

For the following exercises, graph the function. Describe the graph and, wherever applicable, any periodic behavior, amplitude, asymptotes, or undefined points.

$f\left(x\right)=5\mathrm{cos}\left(3x\right)+4\mathrm{sin}\left(2x\right)$

$f\left(x\right)={e}^{\mathrm{sin}t}$

This graph is periodic with a period of $\text{\hspace{0.17em}}2\pi .$

For the following exercises, find the exact value.

${\mathrm{sin}}^{-1}\left(\frac{\sqrt{3}}{2}\right)$

${\mathrm{tan}}^{-1}\left(\sqrt{3}\right)$

$\frac{\pi }{3}$

${\mathrm{cos}}^{-1}\left(-\frac{\sqrt{3}}{2}\right)$

${\mathrm{cos}}^{-1}\left(\mathrm{sin}\left(\pi \right)\right)$

$\frac{\pi }{2}$

${\mathrm{cos}}^{-1}\left(\mathrm{tan}\left(\frac{7\pi }{4}\right)\right)$

$\mathrm{cos}\left({\mathrm{sin}}^{-1}\left(1-2x\right)\right)$

$\sqrt{1-{\left(1-2x\right)}^{2}}$

${\mathrm{cos}}^{-1}\left(-0.4\right)$

$\mathrm{cos}\left({\mathrm{tan}}^{-1}\left({x}^{2}\right)\right)$

$\frac{1}{\sqrt{1+{x}^{4}}}$

For the following exercises, suppose $\text{\hspace{0.17em}}\mathrm{sin}\text{\hspace{0.17em}}t=\frac{x}{x+1}.$

$\mathrm{tan}\text{\hspace{0.17em}}t$

$\mathrm{csc}\text{\hspace{0.17em}}t$

$\frac{x+1}{x}$

Given [link] , find the measure of angle $\text{\hspace{0.17em}}\theta \text{\hspace{0.17em}}$ to three decimal places. Answer in radians.

For the following exercises, determine whether the equation is true or false.

$\mathrm{arcsin}\left(\mathrm{sin}\left(\frac{5\pi }{6}\right)\right)=\frac{5\pi }{6}$

False

$\mathrm{arccos}\left(\mathrm{cos}\left(\frac{5\pi }{6}\right)\right)=\frac{5\pi }{6}$

The grade of a road is 7%. This means that for every horizontal distance of 100 feet on the road, the vertical rise is 7 feet. Find the angle the road makes with the horizontal in radians.

can someone help me with some logarithmic and exponential equations.
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
Commplementary angles
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Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
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a perfect square v²+2v+_
kkk nice
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or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
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yes
Asali
I'm not good at math so would you help me
Samantha
what is the problem that i will help you to self with?
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China
Cied
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I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
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Yasmin
what is the function of carbon nanotubes?
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Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
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Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
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Prasenjit
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Azam
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Prasenjit
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Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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