In a recent study reported Oct.29, 2012 on the Flurry Blog, the mean age of tablet users is 35 years. Suppose the standard deviation is ten years. The sample size is 39.
What are the mean and standard deviation for the sum of the ages of tablet users? What is the distribution?
Find the probability that the sum of the ages is between 1,400 and 1,500 years.
Find the 90
th percentile for the sum of the 39 ages.
μ
Σx =
nμ
x = 1,365 and
σ
Σx =
= 62.4
The distribution is normal for sums by the central limit theorem.
P (1400<
Σ
x <1500) =
normalcdf (1400,1500,(39)(35),(
)(10)) = 0.2723
Let
k = the 90
th percentile.
k =
invNorm (0.90,(39)(35),(
)
(10)) = 1445.0
The mean number of minutes for app engagement by a tablet user is 8.2 minutes. Suppose the standard deviation is one minute. Take a sample of size 70.
What are the mean and standard deviation for the sums?
Find the 95
th percentile for the sum of the sample. Interpret this value in a complete sentence.
Find the probability that the sum of the sample is at least ten hours.
μ
Σx =
nμ
x = 70(8.2) = 574 minutes and
σ
Σx =
=
(1) = 8.37 minutes
Let
k = the 95
th percentile.
k = invNorm
(0.95,(70)(8.2),
(1)) = 587.76 minutes
Ninety five percent of the app engagement times are at most 587.76 minutes.
ten hours = 600 minutes
P (Σ
x ≥ 600) =
normalcdf (600,E99,(70)(8.2),
(1)) = 0.0009
The mean number of minutes for app engagement by a table use is 8.2 minutes. Suppose the standard deviation is one minute. Take a sample size of 70.
What is the probability that the sum of the sample is between seven hours and ten hours? What does this mean in context of the problem?
Find the 84
th and 16
th percentiles for the sum of the sample. Interpret these values in context.
7 hours = 420 minutes
10 hours = 600 minutes
normalcdf
This means that for this sample sums there is a 99.9% chance that the sums of usage minutes will be between 420 minutes and 600 minutes.
Since 84% of the app engagement times are at most 582.32 minutes and 16% of the app engagement times are at most 565.68 minutes, we may state that 68% of the app engagement times are between 565.68 minutes and 582.32 minutes.
Farago, Peter. “The Truth About Cats and Dogs: Smartphone vs Tablet Usage Differences.” The Flurry Blog, 2013. Posted October 29, 2012. Available online at http://blog.flurry.com (accessed May 17, 2013).
Chapter review
The central limit theorem tells us that for a population with any distribution, the distribution of the sums for the sample means approaches a normal distribution as the sample size increases. In other words, if the sample size is large enough, the distribution of the sums can be approximated by a normal distribution even if the original population is not normally distributed. Additionally, if the original population has a mean of
μ
X and a standard deviation of
σ
x , the mean of the sums is
nμ
x and the standard deviation is
(
σ
x ) where
n is the sample size.
Step 1: Find the mean. To find the mean, add up all the scores, then divide them by the number of scores. ...
Step 2: Find each score's deviation from the mean. ...
Step 3: Square each deviation from the mean. ...
Step 4: Find the sum of squares. ...
Step 5: Divide the sum of squares by n – 1 or N.
The sample of 16 students is taken. The average age in the sample was 22 years with astandard deviation of 6 years. Construct a 95% confidence interval for the age of the population.
Bhartdarshan' is an internet-based travel agency wherein customer can see videos of the cities they plant to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400
a. what is the probability of getting more than 12,000 hits?
b. what is the probability of getting fewer than 9,000 hits?
Bhartdarshan'is an internet-based travel agency wherein customer can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400.
a. What is the probability of getting more than 12,000 hits
