<< Chapter < Page Chapter >> Page >

11. a. all employed adult women

12. 0.5773

13. 0.0522

14. b. The middle fifty percent of the members lost from 2 to 8.5 lbs.

15. c. All of the data have the same value.

16. c. The lowest data value is the median.

17. 0.279

18. b. No, I expect to come out behind in money.

19. X = the number of patients calling in claiming to have the flu, who actually have the flu.
X = 0, 1, 2, …25

20. B (25, 0.04)

21. 0.0165

22. 1

23. c. quantitative discrete

24. all words used by Tom Clancy in his novels

Chapter 5

25.

  1. 24%
  2. 27%

26. qualitative

27. 0.36

28. 0.7636

29.

  1. No
  2. No

30. B (10, 0.76)

31. 0.9330

32.

  1. X = the number of questions posted to the statistics listserv per day.
  2. X = 0, 1, 2,…
  3. X ~ P (2)
  4. 0

33. $150

34. Matt

35.

  1. false
  2. true
  3. false
  4. false

36. 16

37. first quartile: 2
second quartile: 2
third quartile: 3

38. 0.5

39. 7 15

40. 2 15

Chapter 6

41.

  1. true
  2. true
  3. False – the median and the mean are the same for this symmetric distribution.
  4. true

42.

  1. 8
  2. 8
  3. P ( x < k ) = 0.65 = ( k – 3) ( 1 10 ) . k = 9.5

43.

  1. False – 3 4 of the data are at most five.
  2. True – each quartile has 25% of the data.
  3. False – that is unknown.
  4. False – 50% of the data are four or less.

44. d. G and H are independent events.

45.

  1. False – J and K are independent so they are not mutually exclusive which would imply dependency (meaning P ( J AND K ) is not 0).
  2. False – see answer c.
  3. True – P ( J OR K ) = P ( J ) + P ( K ) – P ( J AND K ) = P ( J ) + P ( K ) – P ( J ) P ( K ) = 0.3 + 0.6 – (0.3)(0.6) = 0.72. Note the P ( J AND K ) = P ( J ) P ( K ) because J and K are independent.
  4. False – J and K are independent so P ( J ) = P ( J | K )

46. a. P (5)

Chapter 7

47. a. U (0, 4)

48. b. 2 hour

49. a. 1 4

50.

  1. 0.7165
  2. 4.16
  3. 0

51. c. 5 years

52. c. exponential

53. 0.63

54. B (14, 0.20)

55. B (14, 0.20)

Chapter 8

56. c. the mean amount of weight lost by 15 people on the special weight loss diet.

57. 0.9951

58. 12.99

59. c. 1 2

60. b. 0.60

61. c. N (60, 5.477)

62. 0.9990

63. a. eight days

64. c. 0.7500

65. a. 80%

66. b. 35%

67. b. no

68. b. quantitative continuous

69. c. 150

70. d. 0.06

71. c. 0.44

72. b. 0

Chapter 9

73. d. Matt is shorter than the average 14 year old boy.

74. Answers will vary.

75.

x Relative Frequency Cumulative Relative Frequency
1 0.3 0.3
2 0.2 0.2
4 0.4 0.4
5 0.1 0.1

76.

  1. 2.8
  2. 1.48
  3. 90%

77. M = 3; Q 1 = 1; Q 3 = 4

78. 1 and 4

79. d. 8 70

80. c. 40 70

81. a. 9 19

82. b. false

83. b. false

84. b. false

85.

  1. X = the number of pies Lee bakes every day.
  2. P (20)
  3. 0.1122

86. CI: (5.25, 8.48)

87.

  1. uniform
  2. exponential
  3. normal

Chapter 10

88. 77 100

89. 12 42

90.

  1. false
  2. false
  3. true
  4. false

91. N (180, 16.43)

92. a. The distribution for X ¯ is still uniform with the same mean and standard deviation as the distribution for X .

93. c. The distribution for X is normal with a larger mean and a larger standard deviation than the distribution for X .

94. N ( 2 ,   0.25 16 )

95. Answers will vary.

96. 0.5000

97. 7.6

98. 5

99. 0.9431

Chapter 11

100. 7.5

101. 0.0122

102. N (7, 0.63)

103. 0.9911

104. b. Exponential

105.

  1. true
  2. false
  3. false

106. Answers will vary.

107. Student’s t with df = 15

108. (560.07, 719.93)

109. quantitative continuous data

110. quantitative discrete data

111.

  1. X = the number of patients with a shotgun wound the emergency room gets per 28 days
  2. P (4)
  3. 0.0183

112. greater than

113. No; P ( x = 8) = 0.0348

114. You will lose $5.

115. Becca

116. 14

117. Sample mean = 3.2
Sample standard deviation = 1.85
Median = 3
Q 1 = 2
Q 3 = 5
IQR = 3

118. d. z = –1.19
e. 0.1171
f. Do not reject the null hypothesis.

119. We conclude that the patient does have the HIV virus when, in fact, the patient does not.

120. c. z = 2.21; p = 0.0136
d. Reject the null hypothesis.
e. We conclude that the proportion of Californian professionals that wear jeans to work is greater than the proportion of non-Californian professionals when, in fact, it is not greater.
f. We cannot conclude that the proportion of Californian professionals that wear jeans to work is greater than the proportion of non-Californian professionals when, in fact, it is greater.

121. c. dependent means

122. t 5

Chapter 12

123. (0.0424, 0.0770)

124. 2,401

125. Check student's solution.

126. 0.6321

127. $360

128. N ( 72 ,   72 5 )

Chapter 13

129. 0.02

130. 0.40

131. 100 140

132. 10 60

133. p -value = 0; Reject the null hypothesis; conclude that they are dependent events

134. 8.4

135. B (14, 0.60)

136. d. Binomial

137. 0.3669

138. p -value = 0.0006; reject the null hypothesis; conclude that the averages are not equal

139. p -value = 0; reject the null hypothesis; conclude that the proportion of males is higher

140. Minimize α and β

141.

  1. No
  2. Yes, P ( M AND 30+) = 0

142. 12 38

143. No; p -value = 0

144. a. uniform

References

Data from the San Jose Mercury News .

Baran, Daya. “20 Percent of Americans Have Never Used Email.” Webguild.org, 2010. Available online at: http://www.webguild.org/20080519/20-percent-of-americans-have-never-used-email (accessed October 17, 2013).

Data from Parade Magazine .

Questions & Answers

what is biology
Hajah Reply
the study of living organisms and their interactions with one another and their environments
AI-Robot
what is biology
Victoria Reply
HOW CAN MAN ORGAN FUNCTION
Alfred Reply
the diagram of the digestive system
Assiatu Reply
allimentary cannel
Ogenrwot
How does twins formed
William Reply
They formed in two ways first when one sperm and one egg are splited by mitosis or two sperm and two eggs join together
Oluwatobi
what is genetics
Josephine Reply
Genetics is the study of heredity
Misack
how does twins formed?
Misack
What is manual
Hassan Reply
discuss biological phenomenon and provide pieces of evidence to show that it was responsible for the formation of eukaryotic organelles
Joseph Reply
what is biology
Yousuf Reply
the study of living organisms and their interactions with one another and their environment.
Wine
discuss the biological phenomenon and provide pieces of evidence to show that it was responsible for the formation of eukaryotic organelles in an essay form
Joseph Reply
what is the blood cells
Shaker Reply
list any five characteristics of the blood cells
Shaker
lack electricity and its more savely than electronic microscope because its naturally by using of light
Abdullahi Reply
advantage of electronic microscope is easily and clearly while disadvantage is dangerous because its electronic. advantage of light microscope is savely and naturally by sun while disadvantage is not easily,means its not sharp and not clear
Abdullahi
cell theory state that every organisms composed of one or more cell,cell is the basic unit of life
Abdullahi
is like gone fail us
DENG
cells is the basic structure and functions of all living things
Ramadan
What is classification
ISCONT Reply
is organisms that are similar into groups called tara
Yamosa
in what situation (s) would be the use of a scanning electron microscope be ideal and why?
Kenna Reply
A scanning electron microscope (SEM) is ideal for situations requiring high-resolution imaging of surfaces. It is commonly used in materials science, biology, and geology to examine the topography and composition of samples at a nanoscale level. SEM is particularly useful for studying fine details,
Hilary
cell is the building block of life.
Condoleezza Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Introductory statistics. OpenStax CNX. May 06, 2016 Download for free at http://legacy.cnx.org/content/col11562/1.18
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Introductory statistics' conversation and receive update notifications?

Ask