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This module describes how to calculate the F Ratio and F Distribution based on the hypothesis test for the One-Way ANOVA.

The distribution used for the hypothesis test is a new one. It is called the F distribution, named after Sir Ronald Fisher, an English statistician. The F statistic is a ratio (a fraction). There are two sets of degrees of freedom; one for the numerator and one forthe denominator.

For example, if F follows an F distribution and the degrees of freedom for the numerator are 4 and the degrees of freedom for the denominator are 10, then F ~ F 4 , 10 .

The F distribution is derived from the Student's-t distribution. One-Way ANOVA expands the t -test for comparing more than two groups. The scope of that derivation is beyond the level of this course.

To calculate the F ratio, two estimates of the variance are made.

  1. Variance between samples: An estimate of σ 2 that is the variance of the sample means multiplied by n (when there is equal n). If the samples are different sizes, the variance between samples is weighted toaccount for the different sample sizes. The variance is also called variation due to treatment or explainedvariation.
  2. Variance within samples: An estimate of σ 2 that is the average of the sample variances (also known as a pooled variance). When the sample sizes are different, thevariance within samples is weighted. The variance is also called the variation due to error or unexplained variation.
  • SS between = the sum of squares that represents the variation among the different samples.
  • SS within = the sum of squares that represents the variation within samples that is due to chance.

To find a "sum of squares" means to add together squared quantities which, in some cases, may be weighted. We used sum of squares to calculate the sample variance andthe sample standard deviation in Descriptive Statistics .

MS means "mean square." MS between is the variance between groups and MS within is the variance within groups.

    Calculation of sum of squares and mean square

  • k size 12{k} {} = the number of different groups
  • n j size 12{n rSub { size 8{j} } } {} = the size of the jth size 12{ ital "jth"} {} group
  • s j size 12{s rSub { size 8{j} } } {} = the sum of the values in the jth size 12{ ital "jth"} {} group
  • n size 12{n} {} = total number of all the values combined. (total sample size: n j size 12{ Sum {n rSub { size 8{j} } } } {} )
  • x = one value: x = s j size 12{ Sum {x} = Sum {s rSub { size 8{j} } } } {}
  • Sum of squares of all values from every group combined: x 2 size 12{ Sum {x rSup { size 8{2} } } ={}} {}
  • Between group variability: SS total = x 2 x 2 n size 12{ ital "SS" rSub { size 8{ ital "total"} } = Sum {x rSup { size 8{2} } } - { { left ( Sum {x} right ) rSup { size 8{2} } } over {n} } } {}
  • Total sum of squares: x 2 ( x ) 2 n size 12{ Sum {x rSup { size 8{2} } } - { { \( Sum {x} \) rSup { size 8{2} } } over {n} } } {}
  • Explained variation- sum of squares representing variation among the different samples SS between = [ ( sj ) 2 n j ] ( s j ) 2 n size 12{ ital "SS" rSub { size 8{ ital "between"} } = Sum { \[ { { \( ital "sj" \) rSup { size 8{2} } } over {n rSub { size 8{j} } } } \] } - { { \( Sum {s rSub { size 8{j} } \) rSup { size 8{2} } } } over {n} } } {}
  • Unexplained variation- sum of squares representing variation within samples due to chance: SS within = SS total SS between size 12{ ital "SS" rSub { size 8{ ital "within"} } = ital "SS" rSub { size 8{ ital "total"} } - ital "SS" rSub { size 8{ ital "between"} } } {}
  • df's for different groups (df's for the numerator): df between = k 1 size 12{ ital "df" rSub { size 8{ ital "between"} } =k - 1} {}
  • Equation for errors within samples (df's for the denominator): df within = n k size 12{ ital "df" rSub { size 8{ ital "within"} } = n - k} {}
  • Mean square (variance estimate) explained by the different groups: MS between = SS between df between size 12{ ital "MS" rSub { size 8{ ital "between"} } = { { ital "SS" rSub { size 8{ ital "between"} } } over { ital "df" rSub { size 8{ ital "between"} } } } } {}
  • Mean square (variance estimate) that is due to chance (unexplained): MS within = SS within df within size 12{ ital "MS" rSub { size 8{ ital "within"} } = { { ital "SS" rSub { size 8{ ital "within"} } } over { ital "df" rSub { size 8{ ital "within"} } } } } {}

MS between and MS within can be written as follows:

  • MS between = SS between df between = SS between k 1
  • MS within = SS within df within = SS within n k

The One-Way ANOVA test depends on the fact that MS between can be influenced by population differences among means of the several groups. Since MS within compares values of each group to its own group mean, the fact that group means might be different doesnot affect MS within .

The null hypothesis says that all groups are samples from populations having the same normal distribution. The alternate hypothesis says that at least two of the samplegroups come from populations with different normal distributions. If the null hypothesis is true, MS between and MS within should both estimate the same value.

The null hypothesis says that all the group population means are equal. The hypothesis of equal means implies that the populations have the same normal distribution because it is assumed that the populations are normal and that they have equal variances.

F-ratio or f statistic

F = MS between MS within

If MS between and MS within estimate the same value (following the belief that H o is true), then the F-ratio should be approximately equal to 1. Mostly just sampling errorswould contribute to variations away from 1. As it turns out, MS between consists of the population variance plus a variance produced from the differences between thesamples. MS within is an estimate of the population variance. Since variances are always positive, if the null hypothesis is false, MS between will generally be larger than MS within . Then the F-ratio will be larger than 1.However, if the population effect size is small it is not unlikely that MS within will be larger in a give sample.

The above calculations were done with groups of different sizes. If the groups are the same size, the calculations simplify somewhat and the F ratio can be written as:

F-ratio formula when the groups are the same size

F = n s x _ 2 s 2 pooled

    Where ...

  • n = size 12{n={}} {} the sample size
  • df numerator = k 1 size 12{ ital "df" rSub { size 8{ ital "numerator"} } =k - 1} {}
  • df denominator = n k size 12{ ital "df" rSub { size 8{ ital "denominator"={}} } k \( n - 1 \) =N - k} {}
  • s 2 pooled = the mean of the sample variances (pooled variance)
  • s x 2 = the variance of the sample means

The data is typically put into a table for easy viewing. One-Way ANOVA results are often displayed in this manner by computer software.

Source of Variation Sum of Squares (SS) Degrees of Freedom (df) Mean Square (MS) F
Factor
(Between)
SS(Factor) k - 1 MS(Factor) = SS(Factor)/(k-1) F = MS(Factor)/MS(Error)
Error
(Within)
SS(Error) n - k MS(Error) = SS(Error)/(n-k)
Total SS(Total) n - 1

Three different diet plans are to be tested for mean weight loss. The entries in the table are the weight losses for the different plans. The One-Way ANOVA table is shown below.

Plan 1 Plan 2 Plan 3
5 3.5 8
4.5 7 4
4 3.5
3 4.5

One-Way ANOVA Table: The formulas for SS(Total), SS(Factor) = SS(Between) and SS(Error) = SS(Within) are shown above. This same information is provided by the TI calculator hypothesis test function ANOVA in STAT TESTS (syntax is ANOVA(L1, L2, L3) where L1, L2, L3 have the data from Plan 1, Plan 2, Plan 3 respectively).

Source of Variation Sum of Squares (SS) Degrees of Freedom (df) Mean Square (MS) F
Factor
(Between)
SS(Factor)
= SS(Between)
=2.2458
k - 1
= 3 groups - 1
= 2
MS(Factor)
= SS(Factor)/(k-1)
= 2.2458/2
= 1.1229
F =
MS(Factor)/MS(Error)
= 1.1229/2.9792
= 0.3769
Error
(Within)
SS(Error)
= SS(Within)
= 20.8542
n - k
= 10 total data - 3 groups
= 7
MS(Error)
= SS(Error)/(n-k)
= 20.8542/7
= 2.9792
Total SS(Total)
= 2.9792 + 20.8542
=23.1
n - 1
= 10 total data - 1
= 9

Got questions? Get instant answers now!

The One-Way ANOVA hypothesis test is always right-tailed because larger F-values are way out in the right tail of the F-distribution curve and tend to make us reject H o .

Notation

The notation for the F distribution is F ~ F df(num) , df(denom)

where df(num) = df between and df(denom) = df within

The mean for the F distribution is μ = df(num) df(denom) 1

Questions & Answers

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Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
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Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
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Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
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-42m²+60m-18
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-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
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The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
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Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
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12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
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Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
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Source:  OpenStax, Collaborative statistics. OpenStax CNX. Jul 03, 2012 Download for free at http://cnx.org/content/col10522/1.40
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