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- Linear functions
- Graphs of linear functions
Key concepts
- Linear functions may be graphed by plotting points or by using the
y -intercept and slope. See
[link] and
[link] .
- Graphs of linear functions may be transformed by using shifts up, down, left, or right, as well as through stretches, compressions, and reflections. See
[link] .
- The
y -intercept and slope of a line may be used to write the equation of a line.
- The
x -intercept is the point at which the graph of a linear function crosses the
x -axis. See
[link] and
[link] .
- Horizontal lines are written in the form,
See
[link] .
- Vertical lines are written in the form,
See
[link] .
- Parallel lines have the same slope.
- Perpendicular lines have negative reciprocal slopes, assuming neither is vertical. See
[link] .
- A line parallel to another line, passing through a given point, may be found by substituting the slope value of the line and the
x - and
y -values of the given point into the equation,
and using the
that results. Similarly, the point-slope form of an equation can also be used. See
[link]
.
- A line perpendicular to another line, passing through a given point, may be found in the same manner, with the exception of using the negative reciprocal slope. See
[link] and
[link] .
- A system of linear equations may be solved setting the two equations equal to one another and solving for
The
y -value may be found by evaluating either one of the original equations using this
x -value.
- A system of linear equations may also be solved by finding the point of intersection on a graph. See
[link] and
[link] .
Section exercises
Verbal
If the graphs of two linear functions are parallel, describe the relationship between the slopes and the
y -intercepts.
The slopes are equal;
y -intercepts are not equal.
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If a horizontal line has the equation
and a vertical line has the equation
what is the point of intersection? Explain why what you found is the point of intersection.
The point of intersection is
This is because for the horizontal line, all of the
coordinates are
and for the vertical line, all of the
coordinates are
The point of intersection will have these two characteristics.
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Explain how to find a line perpendicular to a linear function that passes through a given point.
First, find the slope of the linear function. Then take the negative reciprocal of the slope; this is the slope of the perpendicular line. Substitute the slope of the perpendicular line and the coordinate of the given point into the equation
and solve for
Then write the equation of the line in the form
by substituting in
and
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Algebraic
For the following exercises, determine whether the lines given by the equations below are parallel, perpendicular, or neither parallel nor perpendicular:
Questions & Answers
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Step 1: Find the mean. To find the mean, add up all the scores, then divide them by the number of scores. ...
Step 2: Find each score's deviation from the mean. ...
Step 3: Square each deviation from the mean. ...
Step 4: Find the sum of squares. ...
Step 5: Divide the sum of squares by n – 1 or N.
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diveving the sum if all values
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Bhartdarshan' is an internet-based travel agency wherein customer can see videos of the cities they plant to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400
a. what is the probability of getting more than 12,000 hits?
b. what is the probability of getting fewer than 9,000 hits?
Bhartdarshan'is an internet-based travel agency wherein customer can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400.
a. What is the probability of getting more than 12,000 hits
Akshay
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Bright
a= 0.20233
b=0.3384
Sufiyan
How do I interpret level of significance?
It depends on your business problem or in Machine Learning you could use ROC- AUC cruve to decide the threshold value
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how skewness and kurtosis are used in statistics
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Source:
OpenStax, Precalculus. OpenStax CNX. Jan 19, 2016 Download for free at https://legacy.cnx.org/content/col11667/1.6
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