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Show that cot θ csc θ = cos θ .

cot θ csc θ = cos θ sin θ 1 sin θ         = cos θ sin θ sin θ 1         = cos θ
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Creating and verifying an identity

Create an identity for the expression 2 tan θ sec θ by rewriting strictly in terms of sine.

There are a number of ways to begin, but here we will use the quotient and reciprocal identities to rewrite the expression:

2 tan θ sec θ = 2 ( sin θ cos θ ) ( 1 cos θ )                  = 2 sin θ cos 2 θ                  = 2 sin θ 1 sin 2 θ Substitute  1 sin 2 θ  for  cos 2 θ

Thus,

2 tan θ sec θ = 2 sin θ 1 sin 2 θ
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Verifying an identity using algebra and even/odd identities

Verify the identity:

sin 2 ( θ ) cos 2 ( θ ) sin ( θ ) cos ( θ ) = cos θ sin θ

Let’s start with the left side and simplify:

sin 2 ( θ ) cos 2 ( θ ) sin ( θ ) cos ( θ ) = [ sin ( θ ) ] 2 [ cos ( θ ) ] 2 sin ( θ ) cos ( θ )                                       = (− sin θ ) 2 ( cos θ ) 2 sin θ cos θ sin ( x ) = sin x and cos ( x ) = cos x                                       = ( sin θ ) 2 ( cos θ ) 2 sin θ cos θ Difference of squares                                       = ( sin θ cos θ ) ( sin θ + cos θ ) ( sin θ + cos θ )                                       = ( sin θ cos θ ) ( sin θ + cos θ ) ( sin θ + cos θ )                                       = cos θ sin θ
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Verify the identity sin 2 θ 1 tan θ sin θ tan θ = sin θ + 1 tan θ .

sin 2 θ 1 tan θ sin θ tan θ = ( sin θ + 1 ) ( sin θ 1 ) tan θ ( sin θ 1 ) = sin θ + 1 tan θ

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Verifying an identity involving cosines and cotangents

Verify the identity: ( 1 cos 2 x ) ( 1 + cot 2 x ) = 1.

We will work on the left side of the equation.

( 1 cos 2 x ) ( 1 + cot 2 x ) = ( 1 cos 2 x ) ( 1 + cos 2 x sin 2 x )                                       = ( 1 cos 2 x ) ( sin 2 x sin 2 x + cos 2 x sin 2 x )   Find the common denominator .                                       = ( 1 cos 2 x ) ( sin 2 x + cos 2 x sin 2 x )                                       = ( sin 2 x ) ( 1 sin 2 x )                                       = 1
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Using algebra to simplify trigonometric expressions

We have seen that algebra is very important in verifying trigonometric identities, but it is just as critical in simplifying trigonometric expressions before solving. Being familiar with the basic properties and formulas of algebra, such as the difference of squares formula, the perfect square formula, or substitution, will simplify the work involved with trigonometric expressions and equations.

For example, the equation ( sin x + 1 ) ( sin x 1 ) = 0 resembles the equation ( x + 1 ) ( x 1 ) = 0 , which uses the factored form of the difference of squares. Using algebra makes finding a solution straightforward and familiar. We can set each factor equal to zero and solve. This is one example of recognizing algebraic patterns in trigonometric expressions or equations.

Another example is the difference of squares formula, a 2 b 2 = ( a b ) ( a + b ) , which is widely used in many areas other than mathematics, such as engineering, architecture, and physics. We can also create our own identities by continually expanding an expression and making the appropriate substitutions. Using algebraic properties and formulas makes many trigonometric equations easier to understand and solve.

Writing the trigonometric expression as an algebraic expression

Write the following trigonometric expression as an algebraic expression: 2 cos 2 θ + cos θ 1.

Notice that the pattern displayed has the same form as a standard quadratic expression, a x 2 + b x + c . Letting cos θ = x , we can rewrite the expression as follows:

2 x 2 + x 1

This expression can be factored as ( 2 x 1 ) ( x + 1 ) . If it were set equal to zero and we wanted to solve the equation, we would use the zero factor property and solve each factor for x . At this point, we would replace x with cos θ and solve for θ .

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Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
Haryormhidey Reply
how many start and codon
Esrael Reply
what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
Nassze Reply
how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, Precalculus. OpenStax CNX. Jan 19, 2016 Download for free at https://legacy.cnx.org/content/col11667/1.6
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