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Rewriting a polar equation in cartesian form

Rewrite the polar equation r = 3 1 2 cos θ as a Cartesian equation.

The goal is to eliminate θ and r , and introduce x and y . We clear the fraction, and then use substitution. In order to replace r with x and y , we must use the expression x 2 + y 2 = r 2 .

                    r = 3 1 2 cos θ r ( 1 2 cos θ ) = 3 r ( 1 2 ( x r ) ) = 3 Use  cos θ = x r  to eliminate  θ .           r 2 x = 3                     r = 3 + 2 x Isolate  r .                   r 2 = ( 3 + 2 x ) 2 Square both sides .          x 2 + y 2 = ( 3 + 2 x ) 2 Use  x 2 + y 2 = r 2 .

The Cartesian equation is x 2 + y 2 = ( 3 + 2 x ) 2 . However, to graph it, especially using a graphing calculator or computer program, we want to isolate y .

x 2 + y 2 = ( 3 + 2 x ) 2          y 2 = ( 3 + 2 x ) 2 x 2            y = ± ( 3 + 2 x ) 2 x 2

When our entire equation has been changed from r and θ to x and y , we can stop, unless asked to solve for y or simplify. See [link] .

Plots of the equations stated above - the plots are the same in both rectangular and polar coordinates. They are hyperbolas.

The “hour-glass” shape of the graph is called a hyperbola . Hyperbolas have many interesting geometric features and applications, which we will investigate further in Analytic Geometry .

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Rewrite the polar equation r = 2 sin θ in Cartesian form.

x 2 + y 2 = 2 y or, in the standard form for a circle, x 2 + ( y 1 ) 2 = 1

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Rewriting a polar equation in cartesian form

Rewrite the polar equation r = sin ( 2 θ ) in Cartesian form.

                  r = sin ( 2 θ ) Use the double angle identity for sine .                   r = 2 sin θ cos θ Use  cos θ = x r  and  sin θ = y r .                   r = 2 ( x r ) ( y r ) Simplify .                   r = 2 x y r 2  Multiply both sides by  r 2 .                 r 3 = 2 x y ( x 2 + y 2 ) 3 = 2 x y As x 2 + y 2 = r 2 , r = x 2 + y 2 .

This equation can also be written as

( x 2 + y 2 ) 3 2 = 2 x y or x 2 + y 2 = ( 2 x y ) 2 3
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Access these online resources for additional instruction and practice with polar coordinates.

Key equations

Conversion formulas cos θ = x r x = r cos θ sin θ = y r y = r sin θ r 2 = x 2 + y 2 tan θ = y x

Key concepts

  • The polar grid is represented as a series of concentric circles radiating out from the pole, or origin.
  • To plot a point in the form ( r , θ ) , θ > 0 , move in a counterclockwise direction from the polar axis by an angle of θ , and then extend a directed line segment from the pole the length of r in the direction of θ . If θ is negative, move in a clockwise direction, and extend a directed line segment the length of r in the direction of θ . See [link] .
  • If r is negative, extend the directed line segment in the opposite direction of θ . See [link] .
  • To convert from polar coordinates to rectangular coordinates, use the formulas x = r cos θ and y = r sin θ . See [link] and [link] .
  • To convert from rectangular coordinates to polar coordinates, use one or more of the formulas: cos θ = x r , sin θ = y r , tan θ = y x , and r = x 2 + y 2 . See [link] .
  • Transforming equations between polar and rectangular forms means making the appropriate substitutions based on the available formulas, together with algebraic manipulations. See [link] , [link] , and [link] .
  • Using the appropriate substitutions makes it possible to rewrite a polar equation as a rectangular equation, and then graph it in the rectangular plane. See [link] , [link] , and [link] .

Section exercises

Verbal

How are polar coordinates different from rectangular coordinates?

For polar coordinates, the point in the plane depends on the angle from the positive x- axis and distance from the origin, while in Cartesian coordinates, the point represents the horizontal and vertical distances from the origin. For each point in the coordinate plane, there is one representation, but for each point in the polar plane, there are infinite representations.

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Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
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what is the change in momentum of a body?
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Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
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A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
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8m/s²
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What is Thermodynamics
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velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
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A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
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which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
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I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
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Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
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field is a region of space under the influence of some physical properties
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determine the slope giving that 3y+ 2x-14=0
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Another formula for Acceleration
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a=v/t. a=f/m a
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Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
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What is specific heat capacity
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Source:  OpenStax, Precalculus. OpenStax CNX. Jan 19, 2016 Download for free at https://legacy.cnx.org/content/col11667/1.6
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