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f ( x ) = { 5 ,    x 0 3 ,    x = 0    a = 0

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f ( x ) = { 1 2 x , x 2 3 , x = 2    a = 2

lim x 2 f ( x ) does not exist.

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f ( x ) = { 1 x + 6 , x = 6 x 2 , x 6    a = 6

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f ( x ) = { 3 + x , x < 1 x , x = 1 x 2 , x > 1      a = 1

lim x 1 f ( x ) = 4 ; lim x 1 + f ( x ) = 1 . Therefore, lim x 1 f ( x ) does not exist.

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f ( x ) = { 3 x , x < 1 x , x = 1 2 x 2 , x > 1      a = 1

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f ( x ) = { 3 + 2 x , x < 1 x , x = 1 x 2 , x > 1      a = 1

lim x 1 f ( x ) = 5 lim x 1 + f ( x ) = 1 . Thus lim x 1 f ( x ) does not exist.

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f ( x ) = { x 2 , x < 2 2 x + 1 , x = 2 x 3 , x > 2      a = 2

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f ( x ) = { x 2 9 x + 3 , x < 3 x 9 , x = 3 1 x , x > 3      a = 3

lim x 3 f ( x ) = 6 , lim x 3 + f ( x ) = 1 3

Therefore, lim x 3 f ( x ) does not exist.

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f ( x ) = { x 2 9 x + 3 , x < 3 x 9 , x = 3 6 , x > 3      a = 3

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f ( x ) = x 2 4 x 2 ,    a = 2

f ( 2 ) is not defined.

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f ( x ) = 25 x 2 x 2 10 x + 25 ,    a = 5

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f ( x ) = x 3 9 x x 2 + 11 x + 24 ,    a = 3

f ( 3 ) is not defined.

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f ( x ) = x 3 27 x 2 3 x ,    a = 3

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f ( x ) = x | x | ,    a = 0

f ( 0 ) is not defined.

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f ( x ) = 2 | x + 2 | x + 2 ,    a = 2

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For the following exercises, determine whether or not the given function f is continuous everywhere. If it is continuous everywhere it is defined, state for what range it is continuous. If it is discontinuous, state where it is discontinuous.

f ( x ) = x 3 2 x 15

Continuous on ( , )

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f ( x ) = x 2 2 x 15 x 5

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f ( x ) = 2 3 x + 4

Continuous on ( , )

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f ( x ) = −sin ( 3 x )

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f ( x ) = | x 2 | x 2 2 x

Discontinuous at x = 0 and x = 2

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f ( x ) = 2 x + 5 x

Discontinuous at x = 0

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f ( x ) = ln   x 2

Continuous on ( 0 , )

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f ( x ) = x 4

Continuous on [ 4 , )

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f ( x ) = sec ( x ) 3 .

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f ( x ) = x 2 + sin ( x )

Continuous on ( , ) .

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Determine the values of b and c such that the following function is continuous on the entire real number line.

f ( x ) = { x + 1 , 1 < x < 3 x 2 + b x + c , | x 2 | 1 }

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Graphical

For the following exercises, refer to [link] . Each square represents one square unit. For each value of a , determine which of the three conditions of continuity are satisfied at x = a and which are not.

Graph of a piecewise function where at x = -3 the line is disconnected, at x = 2 there is a removable discontinuity, and at x = 4 there is a removable discontinuity and f(4) exists.

x = 3

1, but not 2 or 3

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x = 4

1 and 2, but not 3

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For the following exercises, use a graphing utility to graph the function f ( x ) = sin ( 12 π x ) as in [link] . Set the x -axis a short distance before and after 0 to illustrate the point of discontinuity.

Graph of the sinusodial function with a viewing window of [-10, 10] by [-1, 1].

Which conditions for continuity fail at the point of discontinuity?

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Evaluate f ( 0 ) .

f ( 0 ) is undefined.

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Solve for x if f ( x ) = 0.

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What is the domain of f ( x ) ?

( , 0 ) ( 0 , )

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For the following exercises, consider the function shown in [link] .

Graph of a piecewise function where at x = -1 the line is disconnected and at x = 1 there is a removable discontinuity.

At what x -coordinates is the function discontinuous?

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What condition of continuity is violated at these points?

At x = 1 , the limit does not exist. At x = 1 , f ( 1 ) does not exist.

At x = 2 , there appears to be a vertical asymptote, and the limit does not exist.

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Consider the function shown in [link] . At what x -coordinates is the function discontinuous? What condition(s) of continuity were violated?

Graph of a piecewise function where at x = -1 the line is disconnected and where at x = 1 and x = 2 there are a removable discontinuities.
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Construct a function that passes through the origin with a constant slope of 1, with removable discontinuities at x = 7 and x = 1.

x 3 + 6 x 2 7 x ( x + 7 ) ( x 1 )

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The function f ( x ) = x 3 1 x 1 is graphed in [link] . It appears to be continuous on the interval [ 3 , 3 ] , but there is an x -value on that interval at which the function is discontinuous. Determine the value of x at which the function is discontinuous, and explain the pitfall of utilizing technology when considering continuity of a function by examining its graph.

Graph of the function f(x) = (x^3 - 1)/(x-1).
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Find the limit lim x 1 f ( x ) and determine if the following function is continuous at x = 1 :

f x = { x 2 + 4 x 1 2 x = 1

The function is discontinuous at x = 1 because the limit as x approaches 1 is 5 and f ( 1 ) = 2.

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The graph of f ( x ) = sin ( 2 x ) x is shown in [link] . Is the function f ( x ) continuous at x = 0 ? Why or why not?

Graph of the function f(x) = sin(2x)/x with a viewing window of [-4.5, 4.5] by [-1, 2.5]
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Questions & Answers

what does preconceived mean
sammie Reply
physiological Psychology
Nwosu Reply
How can I develope my cognitive domain
Amanyire Reply
why is communication effective
Dakolo Reply
Communication is effective because it allows individuals to share ideas, thoughts, and information with others.
effective communication can lead to improved outcomes in various settings, including personal relationships, business environments, and educational settings. By communicating effectively, individuals can negotiate effectively, solve problems collaboratively, and work towards common goals.
it starts up serve and return practice/assessments.it helps find voice talking therapy also assessments through relaxed conversation.
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Every time someone flushes a toilet in the apartment building, the person begins to jumb back automatically after hearing the flush, before the water temperature changes. Identify the types of learning, if it is classical conditioning identify the NS, UCS, CS and CR. If it is operant conditioning, identify the type of consequence positive reinforcement, negative reinforcement or punishment
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Wekolamo
because it helps many people around the world to understand how to interact with other people and understand them well, for example at work (job).
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ARC
A child is a member of community not society elucidate ?
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Isn't practices worldwide, be it psychology, be it science. isn't much just a false belief of control over something the mind cannot truly comprehend?
Simon Reply
compare and contrast skinner's perspective on personality development on freud
namakula Reply
Skinner skipped the whole unconscious phenomenon and rather emphasized on classical conditioning
war
explain how nature and nurture affect the development and later the productivity of an individual.
Amesalu Reply
nature is an hereditary factor while nurture is an environmental factor which constitute an individual personality. so if an individual's parent has a deviant behavior and was also brought up in an deviant environment, observation of the behavior and the inborn trait we make the individual deviant.
Samuel
I am taking this course because I am hoping that I could somehow learn more about my chosen field of interest and due to the fact that being a PsyD really ignites my passion as an individual the more I hope to learn about developing and literally explore the complexity of my critical thinking skills
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Jonathan
and having a good philosophy of the world is like a sandwich and a peanut butter 👍
Jonathan
generally amnesi how long yrs memory loss
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interpersonal relationships
Abdulfatai Reply
What would be the best educational aid(s) for gifted kids/savants?
Heidi Reply
treat them normal, if they want help then give them. that will make everyone happy
Saurabh
What are the treatment for autism?
Magret Reply
hello. autism is a umbrella term. autistic kids have different disorder overlapping. for example. a kid may show symptoms of ADHD and also learning disabilities. before treatment please make sure the kid doesn't have physical disabilities like hearing..vision..speech problem. sometimes these
Jharna
continue.. sometimes due to these physical problems..the diagnosis may be misdiagnosed. treatment for autism. well it depends on the severity. since autistic kids have problems in communicating and adopting to the environment.. it's best to expose the child in situations where the child
Jharna
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Jharna
results you'll get.. please consult a therapist to know what suits best on your child. and last as a parent. I know sometimes it's overwhelming to guide a special kid. but trust the process and be strong and patient as a parent.
Jharna
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Source:  OpenStax, Precalculus. OpenStax CNX. Jan 19, 2016 Download for free at https://legacy.cnx.org/content/col11667/1.6
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