# 8.4 Rotation of axes  (Page 2/8)

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## Identifying a conic from its general form

Identify the graph of each of the following nondegenerate conic sections.

1. $4{x}^{2}-9{y}^{2}+36x+36y-125=0$
2. $9{y}^{2}+16x+36y-10=0$
3. $3{x}^{2}+3{y}^{2}-2x-6y-4=0$
4. $-25{x}^{2}-4{y}^{2}+100x+16y+20=0$
1. Rewriting the general form, we have

$A=4\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}C=-9,$ so we observe that $\text{\hspace{0.17em}}A\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}C\text{\hspace{0.17em}}$ have opposite signs. The graph of this equation is a hyperbola.

2. Rewriting the general form, we have

$A=0\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}C=9.\text{\hspace{0.17em}}$ We can determine that the equation is a parabola, since $\text{\hspace{0.17em}}A\text{\hspace{0.17em}}$ is zero.

3. Rewriting the general form, we have

$A=3\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}C=3.\text{\hspace{0.17em}}$ Because $\text{\hspace{0.17em}}A=C,$ the graph of this equation is a circle.

4. Rewriting the general form, we have

$A=-25\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}C=-4.\text{\hspace{0.17em}}$ Because $\text{\hspace{0.17em}}AC>0\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}A\ne C,$ the graph of this equation is an ellipse.

Identify the graph of each of the following nondegenerate conic sections.

1. $16{y}^{2}-{x}^{2}+x-4y-9=0$
2. $16{x}^{2}+4{y}^{2}+16x+49y-81=0$
1. hyperbola
2. ellipse

## Finding a new representation of the given equation after rotating through a given angle

Until now, we have looked at equations of conic sections without an $\text{\hspace{0.17em}}xy\text{\hspace{0.17em}}$ term, which aligns the graphs with the x - and y -axes. When we add an $\text{\hspace{0.17em}}xy\text{\hspace{0.17em}}$ term, we are rotating the conic about the origin. If the x - and y -axes are rotated through an angle, say $\text{\hspace{0.17em}}\theta ,$ then every point on the plane may be thought of as having two representations: $\text{\hspace{0.17em}}\left(x,y\right)\text{\hspace{0.17em}}$ on the Cartesian plane with the original x -axis and y -axis, and $\text{\hspace{0.17em}}\left({x}^{\prime },{y}^{\prime }\right)\text{\hspace{0.17em}}$ on the new plane defined by the new, rotated axes, called the x' -axis and y' -axis. See [link] .

We will find the relationships between $\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ on the Cartesian plane with $\text{\hspace{0.17em}}{x}^{\prime }\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}{y}^{\prime }\text{\hspace{0.17em}}$ on the new rotated plane. See [link] .

The original coordinate x - and y -axes have unit vectors $\text{\hspace{0.17em}}i\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}j\text{\hspace{0.17em}}.$ The rotated coordinate axes have unit vectors $\text{\hspace{0.17em}}{i}^{\prime }\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}{j}^{\prime }.$ The angle $\text{\hspace{0.17em}}\theta \text{\hspace{0.17em}}$ is known as the angle of rotation    . See [link] . We may write the new unit vectors in terms of the original ones.

Consider a vector $\text{\hspace{0.17em}}u\text{\hspace{0.17em}}$ in the new coordinate plane. It may be represented in terms of its coordinate axes.

Because $\text{\hspace{0.17em}}u={x}^{\prime }{i}^{\prime }+{y}^{\prime }{j}^{\prime },$ we have representations of $\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ in terms of the new coordinate system.

## Equations of rotation

If a point $\text{\hspace{0.17em}}\left(x,y\right)\text{\hspace{0.17em}}$ on the Cartesian plane is represented on a new coordinate plane where the axes of rotation are formed by rotating an angle $\text{\hspace{0.17em}}\theta \text{\hspace{0.17em}}$ from the positive x -axis, then the coordinates of the point with respect to the new axes are $\text{\hspace{0.17em}}\left({x}^{\prime },{y}^{\prime }\right).\text{\hspace{0.17em}}$ We can use the following equations of rotation to define the relationship between $\text{\hspace{0.17em}}\left(x,y\right)\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}\left({x}^{\prime },{y}^{\prime }\right):$

and

Given the equation of a conic, find a new representation after rotating through an angle.

1. Find $\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ where and
2. Substitute the expression for $\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ into in the given equation, then simplify.
3. Write the equations with $\text{\hspace{0.17em}}{x}^{\prime }\text{\hspace{0.17em}}$ and $\text{\hspace{0.17em}}{y}^{\prime }\text{\hspace{0.17em}}$ in standard form.

given eccentricity and a point find the equiation
12, 17, 22.... 25th term
12, 17, 22.... 25th term
Akash
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find the 15th term of the geometric sequince whose first is 18 and last term of 387
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
hmm well what is the answer
Abhi
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20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
hmm
Abhi
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Abhi
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salma
Commplementary angles
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salma
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a perfect square v²+2v+_
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algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
rolling four fair dice and getting an even number an all four dice