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*No entry if less than 0.001 (trace amount).
**Stable if half-life>10 seconds.
Common isotopes
Element Symbol Mass Number Mass (Atomic Mass Units) Percent Abundance* Half-life**
Hydrogen H 1 1.0078 99.99 stable
2 H or D 2 2.0141 0.01 stable
3 H 3 3.0160 12.32 y
Carbon 12 C 12 12.0000 98.91 stable
13 C 13 13.0034 1.1 stable
14 C 14 14.0032 5730 y
Nitrogen 14 N 14 14.0031 99.6 stable
15 N 15 15.0001 0.4 stable
16 N 16 16.0061 7.13 s
Oxygen 16 O 16 15.9949 99.76 stable
17 O 17 16.9991 0.04 stable
18 O 18 17.9992 0.20 stable
19 O 19 19.0035 26.46 s

Why do neutrons outnumber protons in heavier nuclei ( [link] )? The answer to this question requires an understanding of forces inside the nucleus. Two types of forces exist: (1) the long-range electrostatic (Coulomb) force that makes the positively charged protons repel one another; and (2) the short-range strong nuclear force    that makes all nucleons in the nucleus attract one another. You may also have heard of a “weak” nuclear force. This force is responsible for some nuclear decays, but as the name implies, it does not play a role in stabilizing the nucleus against the strong Coulomb repulsion it experiences. We discuss strong nuclear force in more detail in the next chapter when we cover particle physics. Nuclear stability occurs when the attractive forces between nucleons compensate for the repulsive, long-range electrostatic forces between all protons in the nucleus. For heavy nuclei ( Z > 15 ) , excess neutrons are necessary to keep the electrostatic interactions from breaking the nucleus apart, as shown in [link] .

Figure a shows a cluster of small red and blue circles. There is a blue proton in the center, surrounded by red neutrons. There are more protons at the periphery, which have arrows pointing outwards. Figure b shows the same cluster. Arrows show both protons and neutrons being attracted towards an adjacent neutron.
(a) The electrostatic force is repulsive and has long range. The arrows represent outward forces on protons (in blue) at the nuclear surface by a proton (also in blue) at the center. (b) The strong nuclear force acts between neighboring nucleons. The arrows represent attractive forces exerted by a neutron (in red) on its nearest neighbors.

Because of the existence of stable isotopes, we must take special care when quoting the mass of an element. For example, Copper (Cu) has two stable isotopes:

29 63 C u ( 62.929595 g/mol ) with an abundance of 69.09 %
29 65 C u ( 64.927786 g/mol ) with an abundance of 30.91 %

Given these two “versions” of Cu, what is the mass of this element? The atomic mass    of an element is defined as the weighted average of the masses of its isotopes. Thus, the atomic mass of Cu is m Cu = ( 62.929595 ) ( 0.6909 ) + ( 64.927786 ) ( 0.3091 ) = 63.55 g/mol . The mass of an individual nucleus is often expressed in atomic mass unit     s (u), where u = 1.66054 × 10 −27 kg . (An atomic mass unit is defined as 1/12th the mass of a 12 C nucleus.) In atomic mass units, the mass of a helium nucleus ( A = 4 ) is approximately 4 u. A helium nucleus is also called an alpha ( α ) particle.

Nuclear size

The simplest model of the nucleus is a densely packed sphere of nucleons. The volume V of the nucleus is therefore proportional to the number of nucleons A , expressed by

V = 4 3 π r 3 = k A ,

where r is the radius of a nucleus    and k is a constant with units of volume. Solving for r , we have

r = r 0 A 1 / 3

where r 0 is a constant. For hydrogen ( A = 1 ), r 0 corresponds to the radius of a single proton. Scattering experiments support this general relationship for a wide range of nuclei, and they imply that neutrons have approximately the same radius as protons. The experimentally measured value for r 0 is approximately 1.2 femtometer (recall that 1 fm = 10 −15 m ).

The iron nucleus

Find the radius ( r ) and approximate density ( ρ ) of a Fe-56 nucleus. Assume the mass of the Fe-56 nucleus is approximately 56 u.

Strategy

(a) Finding the radius of 56 Fe is a straightforward application of r = r 0 A 1 / 3 , given A = 56 . (b) To find the approximate density of this nucleus, assume the nucleus is spherical. Calculate its volume using the radius found in part (a), and then find its density from ρ = m / V .

Solution

  1. The radius of a nucleus is given by
    r = r 0 A 1 / 3 .

    Substituting the values for r 0 and A yields
    r = ( 1.2 fm ) ( 56 ) 1 / 3 = ( 1.2 fm ) ( 3.83 ) = 4.6 fm .
  2. Density is defined to be ρ = m / V , which for a sphere of radius r is
    ρ = m V = m ( 4 / 3 ) π r 3 .

    Substituting known values gives
    ρ = 56 u ( 1.33 ) ( 3.14 ) ( 4.6 fm ) 3 = 0.138 u/fm 3 .

    Converting to units of kg / m 3 , we find
    ρ = ( 0.138 u/fm 3 ) ( 1.66 × 10 −27 kg/u ) ( 1 fm 10 −15 m ) = 2.3 × 10 17 kg/m 3 .

Significance

  1. The radius of the Fe-56 nucleus is found to be approximately 5 fm, so its diameter is about 10 fm, or 10 −14 m . In previous discussions of Rutherford’s scattering experiments, a light nucleus was estimated to be 10 −15 m in diameter. Therefore, the result shown for a mid-sized nucleus is reasonable.
  2. The density found here may seem incredible. However, it is consistent with earlier comments about the nucleus containing nearly all of the mass of the atom in a tiny region of space. One cubic meter of nuclear matter has the same mass as a cube of water 61 km on each side.
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Check Your Understanding Nucleus X is two times larger than nucleus Y. What is the ratio of their atomic masses?

eight

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Summary

  • The atomic nucleus is composed of protons and neutrons.
  • The number of protons in the nucleus is given by the atomic number, Z . The number of neutrons in the nucleus is the neutron number, N . The number of nucleons is mass number, A .
  • Atomic nuclei with the same atomic number, Z , but different neutron numbers, N , are isotopes of the same element.
  • The atomic mass of an element is the weighted average of the masses of its isotopes.

Conceptual questions

Define and make clear distinctions between the terms neutron, nucleon, nucleus, and nuclide.

The nucleus of an atom is made of one or more nucleons. A nucleon refers to either a proton or neutron. A nuclide is a stable nucleus.

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What are isotopes? Why do isotopes of the same atom share the same chemical properties?

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Problems

Find the atomic numbers, mass numbers, and neutron numbers for (a) 29 58 C u , (b) 11 24 N a , (c) 84 210 P o , (d) 20 45 C a , and (e) 82 206 P b .

Use the rule A = Z + N .

Atomic Number ( Z ) Neutron Number ( N ) Mass Number ( A )
(a) 29 29 58
(b) 11 13 24
(c) 84 126 210
(d) 20 25 45
(e) 82 124 206
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Silver has two stable isotopes. The nucleus, 47 107 A g , has atomic mass 106.905095 g/mol with an abundance of 51.83 % ; whereas 47 109 A g has atomic mass 108.904754 g/mol with an abundance of 48.17 % . Find the atomic mass of the element silver.

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The mass ( M ) and the radius ( r ) of a nucleus can be expressed in terms of the mass number, A . (a) Show that the density of a nucleus is independent of A . (b) Calculate the density of a gold (Au) nucleus. Compare your answer to that for iron (Fe).

a. r = r 0 A 1 / 3 , ρ = 3 u 4 π r 0 3 ;
b. ρ = 2.3 × 10 17 kg/m 3

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A particle has a mass equal to 10 u. If this mass is converted completely into energy, how much energy is released? Express your answer in mega-electron volts (MeV). (Recall that 1 eV = 1.6 × 10 −19 J .)

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Find the length of a side of a cube having a mass of 1.0 kg and the density of nuclear matter.

side length = 1.6 μm

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The detail that you can observe using a probe is limited by its wavelength. Calculate the energy of a particle that has a wavelength of 1 × 10 −16 m , small enough to detect details about one-tenth the size of a nucleon.

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Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
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