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Fermi energies for selected materials are listed in the following table.

Conduction electron densities and fermi energies for some metals
Element Conduction Band Electron Density ( 10 28 m −3 ) Free-Electron Model Fermi Energy ( eV )
Al 18.1 11.7
Ba 3.15 3.64
Cu 8.47 7.00
Au 5.90 5.53
Fe 17.0 11.1
Ag 5.86 5.49

Note also that only the graph in part (c) of the figure, which answers the question, “How many particles are found in the energy range?” is checked by experiment. The Fermi temperature    or effective “temperature” of an electron at the Fermi energy is

T F = E F k B .

Fermi energy of silver

Metallic silver is an excellent conductor. It has 5.86 × 10 28 conduction electrons per cubic meter. (a) Calculate its Fermi energy. (b) Compare this energy to the thermal energy k B T of the electrons at a room temperature of 300 K.

Solution

  1. From [link] , the Fermi energy is
    E F = h 2 2 m e ( 3 π 2 n e ) 2 / 3 = ( 1.05 × 10 −34 J · s ) 2 2 ( 9.11 × 10 −31 kg ) × [ ( 3 π 2 ( 5.86 × 10 28 m −3 ) ] 2 / 3 = 8.79 × 10 −19 J = 5.49 eV .

    This is a typical value of the Fermi energy for metals, as can be seen from [link] .
  2. We can associate a Fermi temperature T F with the Fermi energy by writing k B T F = E F . We then find for the Fermi temperature
    T F = 8.79 × 10 −19 J 1.38 × 10 −23 J/K = 6.37 × 10 4 K ,

    which is much higher than room temperature and also the typical melting point ( 10 3 K ) of a metal. The ratio of the Fermi energy of silver to the room-temperature thermal energy is
    E F k B T = T F T 210 .
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To visualize how the quantum states are filled, we might imagine pouring water slowly into a glass, such as that of [link] . The first drops of water (the electrons) occupy the bottom of the glass (the states with lowest energy). As the level rises, states of higher and higher energy are occupied. Furthermore, since the glass has a wide opening and a narrow stem, more water occupies the top of the glass than the bottom. This reflects the fact that the density of states g ( E ) is proportional to E 1 / 2 , so there is a relatively large number of higher energy electrons in a free electron gas. Finally, the level to which the glass is filled corresponds to the Fermi energy.

Photograph of a martini glass half filled with water. The water is labeled electron gas and the water line is labeled Fermi energy E subscript F.
An analogy of how electrons fill energy states in a metal. As electrons fill energy states, lowest to highest, the number of available states increases. The highest energy state (corresponding to the water line) is the Fermi energy. (credit: modification of work by “Didriks”/Flickr)

Suppose that at T = 0 K , the number of conduction electrons per unit volume in our sample is n e . Since each field state has one electron, the number of filled states per unit volume is the same as the number of electrons per unit volume.

Summary

  • Metals conduct electricity, and electricity is composed of large numbers of randomly colliding and approximately free electrons.
  • The allowed energy states of an electron are quantized. This quantization appears in the form of very large electron energies, even at T = 0 K .
  • The allowed energies of free electrons in a metal depend on electron mass and on the electron number density of the metal.
  • The density of states of an electron in a metal increases with energy, because there are more ways for an electron to fill a high-energy state than a low-energy state.
  • Pauli’s exclusion principle states that only two electrons (spin up and spin down) can occupy the same energy level. Therefore, in filling these energy levels (lowest to highest at T = 0 K ) , the last and largest energy level to be occupied is called the Fermi energy.

Conceptual questions

Why does the Fermi energy ( E F ) increase with the number of electrons in a metal?

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If the electron number density ( N/V ) of a metal increases by a factor 8, what happens to the Fermi energy ( E F ) ?

increases by a factor of 8 2 3 = 4

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Why does the horizontal line in the graph in [link] suddenly stop at the Fermi energy?

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Why does the graph in [link] increase gradually from the origin?

For larger energies, the number of accessible states increases.

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Why are the sharp transitions at the Fermi energy “smoothed out” by increasing the temperature?

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Problems

What is the difference in energy between the n x = n y = n z = 4 state and the state with the next higher energy? What is the percentage change in the energy between the n x = n y = n z = 4 state and the state with the next higher energy? (b) Compare these with the difference in energy and the percentage change in the energy between the n x = n y = n z = 400 state and the state with the next higher energy.

a. 4 % ; b. 4.2 × 10 −4 % ; for very large values of the quantum numbers, the spacing between adjacent energy levels is very small (“in the continuum”). This is consistent with the expectation that for large quantum numbers, quantum and classical mechanics give approximately the same predictions.

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An electron is confined to a metal cube of l = 0.8 cm on each side. Determine the density of states at (a) E = 0.80 eV ; (b) E = 2.2 eV ; and (c) E = 5.0 eV .

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What value of energy corresponds to a density of states of 1.10 × 10 24 eV −1 ?

10.0 eV

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Compare the density of states at 2.5 eV and 0.25 eV.

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Consider a cube of copper with edges 1.50 mm long. Estimate the number of electron quantum states in this cube whose energies are in the range 3.75 to 3.77 eV.

4.55 × 10 9

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If there is one free electron per atom of copper, what is the electron number density of this metal?

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Determine the Fermi energy and temperature for copper at T = 0 K .

Fermi energy, E F = 7.03 eV , Temperature, T F = 8.2 × 10 4 K

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Practice Key Terms 6

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Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
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