<< Chapter < Page Chapter >> Page >

The magnification of the microscope is the product of the linear magnification m obj by the objective and the angular magnification M eye by the eyepiece. These are given by

m obj = d i obj d o obj d i obj f obj (linear magnification by objective) M eye = 1 + 25 cm f eye (angular magnification by eyepiece)

Here, f obj and f eye are the focal lengths of the objective and the eyepiece, respectively. We assume that the final image is formed at the near point of the eye, providing the largest magnification. Note that the angular magnification of the eyepiece is the same as obtained earlier for the simple magnifying glass. This should not be surprising, because the eyepiece is essentially a magnifying glass, and the same physics applies here. The net magnification     M net of the compound microscope is the product of the linear magnification of the objective and the angular magnification of the eyepiece:

M net = m obj M eye = d i obj ( f eye + 25 cm ) f obj f eye .

Microscope magnification

Calculate the magnification of an object placed 6.20 mm from a compound microscope that has a 6.00 mm-focal length objective and a 50.0 mm-focal length eyepiece. The objective and eyepiece are separated by 23.0 cm.

Strategy

This situation is similar to that shown in [link] . To find the overall magnification, we must know the linear magnification of the objective and the angular magnification of the eyepiece. We can use [link] , but we need to use the thin-lens equation to find the image distance d i obj of the objective.

Solution

Solving the thin-lens equation for d i obj gives

d i obj = ( 1 f obj 1 d o obj ) −1 = ( 1 6.00 mm 1 6.20 mm ) −1 = 186 mm = 18.6 cm

Inserting this result into [link] along with the known values f obj = 6.20 mm = 0.620 cm and f eye = 50.0 mm = 5.00 cm gives

M net = d i obj ( f eye + 25 cm ) f obj f eye = ( 18.6 cm ) ( 5.00 cm + 25 cm ) ( 0.620 cm ) ( 5.00 cm ) = −180

Significance

Both the objective and the eyepiece contribute to the overall magnification, which is large and negative, consistent with [link] , where the image is seen to be large and inverted. In this case, the image is virtual and inverted, which cannot happen for a single element (see [link] ).

Got questions? Get instant answers now!
Figure shows from left to right: an object with height h, a bi-convex lens labeled objective lens at a distance d subscript o from the object, an inverted image with height h subscript i labeled first image at a distance d subscript i from the objective lens, a bi-convex lens labeled eyepiece at a distance d subscript o prime from the first image and finally the eye of the observer. Rays originate from the top of the object and pass through the objective lens to converge at the top of the inverted image. They travel further and enter the eyepiece, from where they deviate to reach the eye. The back extensions of the deviated rays converge at the tip of a much larger inverted image to the far left of the figure. The height of this image is h subscript i prime and its distance from the eyepiece is d subscript i prime.
A compound microscope with the image created at infinity.

We now calculate the magnifying power of a microscope when the image is at infinity, as shown in [link] , because this makes for the most relaxed viewing. The magnifying power of the microscope is the product of linear magnification m obj of the objective and the angular magnification M eye of the eyepiece. We know that m obj = d i obj / d o obj and from the thin-lens equation we obtain

m obj = d i obj d o obj = 1 d i obj f obj = f obj d i obj f obj .

If the final image is at infinity, then the image created by the objective must be located at the focal point of the eyepiece. This may be seen by considering the thin-lens equation with d i = or by recalling that rays that pass through the focal point exit the lens parallel to each other, which is equivalent to focusing at infinity. For many microscopes, the distance between the image-side focal point of the objective and the object-side focal point of the eyepiece is standardized at L = 16 cm . This distance is called the tube length of the microscope. From [link] , we see that L = f obj d i obj . Inserting this into [link] gives

Practice Key Terms 6

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'University physics volume 3' conversation and receive update notifications?

Ask