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By the end of this section, you will be able to:
  • Explain how parallel wires carrying currents can attract or repel each other
  • Define the ampere and describe how it is related to current-carrying wires
  • Calculate the force of attraction or repulsion between two current-carrying wires

You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary currents. But you might not expect that the force between wires is used to define the ampere. It might also surprise you to learn that this force has something to do with why large circuit breakers burn up when they attempt to interrupt large currents.

The force between two long, straight, and parallel conductors separated by a distance r can be found by applying what we have developed in the preceding sections. [link] shows the wires, their currents, the field created by one wire, and the consequent force the other wire experiences from the created field. Let us consider the field produced by wire 1 and the force it exerts on wire 2 (call the force F 2 ). The field due to I 1 at a distance r is

B 1 = μ 0 I 1 2 π r
Figure A shows two long, straight, and parallel conductors separated by a distance r. The magnetic field produced by one of the conductors is perpendicular to the direction of the flow of the current. Figure b is the top view. It shows that vector F2 is directed from one of the conductors to another. Vector B1 lies at the same plane as the magnetic field and is perpendicular to F2.
(a) The magnetic field produced by a long straight conductor is perpendicular to a parallel conductor, as indicated by right-hand rule (RHR)-2. (b) A view from above of the two wires shown in (a), with one magnetic field line shown for wire 1. RHR-1 shows that the force between the parallel conductors is attractive when the currents are in the same direction. A similar analysis shows that the force is repulsive between currents in opposite directions.

This field is uniform from the wire 1 and perpendicular to it, so the force F 2 it exerts on a length l of wire 2 is given by F = I l B sin θ with sin θ = 1 :

F 2 = I 2 l B 1 .

The forces on the wires are equal in magnitude, so we just write F for the magnitude of F 2 . (Note that F 1 = F 2 . ) Since the wires are very long, it is convenient to think in terms of F/l , the force per unit length. Substituting the expression for B 1 into [link] and rearranging terms gives

F l = μ 0 I 1 I 2 2 π r .

The ratio F/l is the force per unit length between two parallel currents I 1 and I 2 separated by a distance r . The force is attractive if the currents are in the same direction and repulsive if they are in opposite directions.

This force is responsible for the pinch effect in electric arcs and other plasmas. The force exists whether the currents are in wires or not. It is only apparent if the overall charge density is zero; otherwise, the Coulomb repulsion overwhelms the magnetic attraction. In an electric arc, where charges are moving parallel to one another, an attractive force squeezes currents into a smaller tube. In large circuit breakers, such as those used in neighborhood power distribution systems, the pinch effect can concentrate an arc between plates of a switch trying to break a large current, burn holes, and even ignite the equipment. Another example of the pinch effect is found in the solar plasma, where jets of ionized material, such as solar flares, are shaped by magnetic forces.

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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