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P = d Q d T = k A ( T h T c ) d

where P is the power or rate of heat transfer in watts or in kilocalories per second, A and d are its surface area and thickness, as shown in [link] , T h T c is the temperature difference across the slab, and k is the thermal conductivity    of the material. [link] gives representative values of thermal conductivity.

More generally, we can write

P = k A d T d x ,

where x is the coordinate in the direction of heat flow. Since in [link] , the power and area are constant, dT / dx is constant, and the temperature decreases linearly from T h to T c .

Values are given for temperatures near 0 ° C .
Thermal conductivities of common substances
Substance Thermal Conductivity k ( W / m · °C )
Diamond 2000
Silver 420
Copper 390
Gold 318
Aluminum 220
Steel iron 80
Steel (stainless) 14
Ice 2.2
Glass (average) 0.84
Concrete brick 0.84
Water 0.6
Fatty tissue (without blood) 0.2
Asbestos 0.16
Plasterboard 0.16
Wood 0.08–0.16
Snow (dry) 0.10
Cork 0.042
Glass wool 0.042
Wool 0.04
Down feathers 0.025
Air 0.023
Polystyrene foam 0.010

Calculating heat transfer through conduction

A polystyrene foam icebox has a total area of 0.950 m 2 and walls with an average thickness of 2.50 cm. The box contains ice, water, and canned beverages at 0 ° C . The inside of the box is kept cold by melting ice. How much ice melts in one day if the icebox is kept in the trunk of a car at 35.0 ºC ?

Strategy

This question involves both heat for a phase change (melting of ice) and the transfer of heat by conduction. To find the amount of ice melted, we must find the net heat transferred. This value can be obtained by calculating the rate of heat transfer by conduction and multiplying by time.

Solution

First we identify the knowns.

k = 0.010 W/m · ° C for polystyrene foam; A = 0.950 m 2 ; d = 2.50 cm = 0.0250 m; ; T c = 0 ° C; T h = 35.0 ° C ; t = 1 day = 24 hours - 84,400 s.

Then we identify the unknowns. We need to solve for the mass of the ice, m . We also need to solve for the net heat transferred to melt the ice, Q . The rate of heat transfer by conduction is given by

P = d Q d T = k A ( T h T c ) d .

The heat used to melt the ice is Q = m L f .We insert the known values:

P = ( 0.010 W/m · ° C ) ( 0.950 m 2 ) ( 35.0 ° C 0 ° C ) 0.0250 m = 13.3 W .

Multiplying the rate of heat transfer by the time ( 1 day = 86,400 s ), we obtain

Q = P t = ( 13.3 W ) ( 86.400 s ) = 1.15 × 10 6 J .

We set this equal to the heat transferred to melt the ice, Q = m L f , and solve for the mass m :

m = Q L f = 1.15 × 10 6 J 334 × 10 3 J/kg = 3.44 kg .

Significance

The result of 3.44 kg, or about 7.6 lb, seems about right, based on experience. You might expect to use about a 4 kg (7–10 lb) bag of ice per day. A little extra ice is required if you add any warm food or beverages.

[link] shows that polystyrene foam is a very poor conductor and thus a good insulator. Other good insulators include fiberglass, wool, and goosedown feathers. Like polystyrene foam, these all contain many small pockets of air, taking advantage of air’s poor thermal conductivity.

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In developing insulation , the smaller the conductivity k and the larger the thickness d , the better. Thus, the ratio d/k , called the R factor , is large for a good insulator. The rate of conductive heat transfer is inversely proportional to R . R factors are most commonly quoted for household insulation, refrigerators, and the like. Unfortunately, in the United States, R is still in non-metric units of ft 2 · °F · h/Btu , although the unit usually goes unstated [1 British thermal unit (Btu) is the amount of energy needed to change the temperature of 1.0 lb of water by 1.0 ° F , which is 1055.1 J]. A couple of representative values are an R factor of 11 for 3.5-inch-thick fiberglass batts (pieces) of insulation and an R factor of 19 for 6.5-inch-thick fiberglass batts ( [link] ). In the US, walls are usually insulated with 3.5-inch batts, whereas ceilings are usually insulated with 6.5-inch batts. In cold climates, thicker batts may be used.

Practice Key Terms 9

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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