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Physics in action: impulse

A very important application of impulse is improving safety and reducing injuries. In many cases, an object needs to be brought to rest from a certain initial velocity. This means there is a certain specified change in momentum. If the time during which the momentum changes can be increased then the force that must be applied will be less and so it will cause less damage. This is the principle behind arrestor beds for trucks, airbags, and bending your knees when you jump off a chair and land on the ground.

Air-bags in motor vehicles

Air bags are used in motor vehicles because they are able to reduce the effect of the force experienced by a person during an accident. Air bags extend the time required to stop the momentum of the driver and passenger. During a collision, the motion of the driver and passenger carries them towards the windshield. If they are stopped by a collision with the windshield, it would result in a large force exerted over a short time in order to bring them to a stop. If instead of hitting the windshield, the driver and passenger hit an air bag, then the time of the impact is increased. Increasing the time of the impact results in a decrease in the force.

Padding as protection during sports

The same principle explains why wicket keepers in cricket use padded gloves or why there are padded mats in gymnastics. In cricket, when the wicket keeper catches the ball, the padding is slightly compressible, thus reducing the effect of the force on the wicket keepers hands. Similarly, if a gymnast falls, the padding compresses and reduces the effect of the force on the gymnast's body.

Arrestor beds for trucks

An arrestor bed is a patch of ground that is softer than the road. Trucks use these when they have to make an emergency stop. When a trucks reaches an arrestor bed the time interval over which the momentum is changed is increased. This decreases the force and causes the truck to slow down.

Follow-through in sports

In sports where rackets and bats are used, like tennis, cricket, squash, badminton and baseball, the hitter is often encouraged to follow-through when striking the ball. High speed films of the collisions between bats/rackets and balls have shown that following through increases the time over which the collision between the racket/bat and ball occurs. This increase in the time of the collision causes an increase in the velocity change of the ball. This means that a hitter can cause the ball to leave the racket/bat faster by following through. In these sports, returning the ball with a higher velocity often increases the chances of success.

Crumple zones in cars

Another safety application of trying to reduce the force experienced is in crumple zones in cars. When two cars have a collision, two things can happen:

  1. the cars bounce off each other, or
  2. the cars crumple together.

Which situation is more dangerous for the occupants of the cars? When cars bounce off each other, or rebound, there is a larger change in momentum and therefore a larger impulse. A larger impulse means that a greater force is experienced by the occupants of the cars. When cars crumple together, there is a smaller change in momentum and therefore a smaller impulse. The smaller impulse means that the occupants of the cars experience a smaller force. Car manufacturers use this idea and design crumple zones into cars, such that the car has a greater chance of crumpling than rebounding in a collision. Also, when the car crumples, the change in the car's momentum happens over a longer time. Both these effects result in a smaller force on the occupants of the car, thereby increasing their chances of survival.

Egg throw

This activity demonstrates the effect of impulse and how it is used to improve safety. Have two learners hold up a bed sheet or large piece of fabric. Then toss an egg at the sheet. The egg should not break, because the collision between the egg and the bed sheet lasts over an extended period of time since the bed sheet has some give in it. By increasing the time of the collision, the force of the impact is minimized. Take care to aim at the sheet, because if you miss the sheet, you will definitely break the egg and have to clean up the mess!


  1. A canon, mass 500 kg, fires a shell, mass 1 kg, horizontally to the right at 500 m · s - 1 . What is the magnitude and direction of the initial recoil velocity of the canon?
  2. A trolley of mass 1 kg is moving with a speed of 3 m · s - 1 . A block of wood, mass 0,5 kg, is dropped vertically into the trolley. Immediately after the collision, the speed of the trolley and block is 2 m · s - 1 . By way of calculation, show whether momentum is conserved in the collision.
  3. A 7200 kg empty railway truck is stationary. A fertilizer firm loads 10800 kg fertilizer into the truck. A second, identical, empty truck is moving at 10 m · s - 1 when it collides with the loaded truck.
    1. If the empty truck stops completely immediately after the collision, use a conservation law to calculate the velocity of the loaded truck immediately after the collision.
    2. Calculate the distance that the loaded truck moves after collision, if a constant frictional force of 24 kN acts on the truck.
  4. A child drops a squash ball of mass 0,05 kg. The ball strikes the ground with a velocity of 4 m · s - 1 and rebounds with a velocity of 3 m · s - 1 . Does the law of conservation of momentum apply to this situation? Explain.
  5. A bullet of mass 50 g travelling horizontally at 600 m · s - 1 strikes a stationary wooden block of mass 2 kg resting on a smooth horizontal surface. The bullet gets stuck in the block.
    1. Name and state the principle which can be applied to find the speed of the block-and-bullet system after the bullet entered the block.
    2. Calculate the speed of the bullet-and-block system immediately after impact.
    3. If the time of impact was 5 x 10 - 4 seconds, calculate the force that the bullet exerts on the block during impact.

Questions & Answers

which gas is ideal gas
how to calculate emf when you are given two circuits with different external resistance, current but no internal resistance?
Andiswa Reply
you have to find the current of whole both circuits nd add em...
calculate the distance between two charge +4nc and -3nc if electrostatic is 0.005N
Malaza Reply
use the coulombs law equation where there is F u substite by 0.005 then u cross multiple
what is atomic
motheo Reply
what is charge
how to calculate the distance between Q1 and point P if you are given distance between point P and Q2
Lwando Reply
how do we calculate the magnitude of the force between two objects
Ntombi Reply
we use Newtons law ...fnet=ma
how do you calculate the enery change in enthalpy reaction, can someone explain it to me guys
Buyie Reply
∆H(enthalpy change)= Hproducts- Hreactants.... use this formula, H stands for enthalpy which is regarded as energy
atomic model john dalton
Alliieyza Reply
Hlw,, I want to join.
what is a normal force
tumelo Reply
normal force is the line that is perpendicular to the surface
normal force is the force exerted to an object by the surface , perpendicular to the surface
I want to join
better explanation of FARADAY'S LAW OF INDUCTION
what is the formular of energy
Wilka Reply
doesnt it like depend on the type of energy
what does (1s2 2s2 and 2p6) mean?
Ryan Reply
That is Albau Diagram I guess!! it represent number of electrons in each energy orbit!! the numbers 1s, 2s&2p, 3s and so on represent energy orbit and then the other numbers after s & p represent number of electrons
That is SP notation
What are the differences between pd and emf?
Santosh Reply
How to calculate magnitude of Friction force
Tanaka Reply
in Newton
in newton
Onother Question?
yes bruh
First of all in wat Grade ae u..?
grde 11
Oka nd hw is the properties of a substance afected by the intermoleculaer forces...
hi guys I m in grade 11 I need help with electrostatics
what is newton
Ndamulelo Reply
look for the x components n y components then after y add the x components separate n y separate then u use the Pythagoras theorem 2 find the resultand
Abigail Reply
Thank you very much
how do I find 🔍 the critical angle
angle of incident and angle of reflection must always approach normal line thats where u will see 90° which is critical point

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Source:  OpenStax, Siyavula textbooks: grade 11 physical science. OpenStax CNX. Jul 29, 2011 Download for free at http://cnx.org/content/col11241/1.2
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