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Problems&Exercises

Sketch the electric field lines in the vicinity of the conductor in [link] given the field was originally uniform and parallel to the object's long axis. Is the resulting field small near the long side of the object?

A oblong-shaped conductor.
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Sketch the electric field lines in the vicinity of the conductor in [link] given the field was originally uniform and parallel to the object's long axis. Is the resulting field small near the long side of the object?

A oblong-shaped conductor.
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Sketch the electric field between the two conducting plates shown in [link] , given the top plate is positive and an equal amount of negative charge is on the bottom plate. Be certain to indicate the distribution of charge on the plates.

Two plates are shown; one is in horizontal direction and other is above the first plate with some inclination.
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Sketch the electric field lines in the vicinity of the charged insulator in [link] noting its nonuniform charge distribution.

A positively charged rod with a concentration of positive charges near the top and a few in the middle.
A charged insulating rod such as might be used in a classroom demonstration.
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What is the force on the charge located at x = 8.00 cm in [link] (a) given that q = 1 . 00 μC size 12{q=1 "." "00"μC"} {} ?

Three point charges are shown on the scaling line. First charge plus q is at three point zero, second charge minus two q is at eight point zero, and third charge plus q is eleven point zero centimeters along the x axis. Four charges are placed on a scaling line. First is minus two q at one point zero, second is plus q at five point zero, third is plus three q is at eight point zero, and fourth is minus q placed at fourteen point zero centimeter along the x axis.
(a) Point charges located at 3.00, 8.00, and 11.0 cm along the x -axis. (b) Point charges located at 1.00, 5.00, 8.00, and 14.0 cm along the x -axis.
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(a) Find the total electric field at x = 1.00 cm in [link] (b) given that q = 5.00 nC . (b) Find the total electric field at x = 11.00 cm in [link] (b). (c) If the charges are allowed to move and eventually be brought to rest by friction, what will the final charge configuration be? (That is, will there be a single charge, double charge, etc., and what will its value(s) be?)

(a) E x = 1.00 cm = size 12{E rSub { size 8{x=1 "." "00" ital "cm"} } = - infinity } {}

(b) 2 . 12 × 10 5 N/C size 12{ {underline {2 "." "12" times "10" rSup { size 8{5} } " N/C" {underline {}} }} } {}

(c) one charge of + q

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(a) Find the electric field at x = 5.00 cm in [link] (a), given that q = 1.00 μC size 12{q=1 "." "00"μC"} {} . (b) At what position between 3.00 and 8.00 cm is the total electric field the same as that for –2 q alone? (c) Can the electric field be zero anywhere between 0.00 and 8.00 cm? (d) At very large positive or negative values of x , the electric field approaches zero in both (a) and (b). In which does it most rapidly approach zero and why? (e) At what position to the right of 11.0 cm is the total electric field zero, other than at infinity? (Hint: A graphing calculator can yield considerable insight in this problem.)

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(a) Find the total Coulomb force on a charge of 2.00 nC located at x = 4.00 cm in [link] (b), given that q = 1.00 μC size 12{q=1 "." "00"μC"} {} . (b) Find the x -position at which the electric field is zero in [link] (b).

(a) 0.252 N to the left

(b) x = 6.07 cm

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Using the symmetry of the arrangement, determine the direction of the force on q size 12{q} {} in the figure below, given that q a = q b =+ 7 . 50 μC size 12{q rSub { size 8{a} } =q rSub { size 8{b} } "=+"7 "." "50"μC"} {} and q c = q d = 7 . 50 μC size 12{q rSub { size 8{c} } =q rSub { size 8{d} } = - 7 "." "50"μC"} {} . (b) Calculate the magnitude of the force on the charge q size 12{q} {} , given that the square is 10.0 cm on a side and q = 2 . 00 μC size 12{q=2 "." "00"μC"} {} .

Four point charges, one is q a, second is q b, third is q c, and fourth is q d, lie on the corners of a square. q is located at its center.
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(a) Using the symmetry of the arrangement, determine the direction of the electric field at the center of the square in [link] , given that q a = q b = 1 . 00 μC size 12{q rSub { size 8{a} } =q rSub { size 8{b} } = - 1 "." "00"μC"} {} and q c = q d =+ 1 . 00 μC size 12{q rSub { size 8{c} } =q rSub { size 8{d} } "=+"1 "." "00"μC"} {} . (b) Calculate the magnitude of the electric field at the location of q size 12{q} {} , given that the square is 5.00 cm on a side.

(a)The electric field at the center of the square will be straight up, since q a size 12{q rSub { size 8{a} } } {} and q b size 12{q rSub { size 8{b} } } {} are positive and q c size 12{q rSub { size 8{c} } } {} and q d size 12{q rSub { size 8{d} } } {} are negative and all have the same magnitude.

(b) 2 . 04 × 10 7 N/C ( upward ) size 12{ {underline {2 "." "04" times "10" rSup { size 8{7} } " N/C" \( "upward" \) }} } {}

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Find the electric field at the location of q a size 12{q rSub { size 8{a} } } {} in [link] given that q b = q c = q d =+ 2 . 00 nC size 12{q rSub { size 8{b} } =q rSub { size 8{c} } =q rSub { size 8{d} } "=+"2 "." "00"nC"} {} , q = 1 . 00 nC size 12{q= - 1 "." "00"nC"} {} , and the square is 20.0 cm on a side.

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Find the total Coulomb force on the charge q in [link] , given that q = 1 . 00 μC size 12{q=1 "." "00"μC"} {} , q a = 2 . 00 μC size 12{q rSub { size 8{a} } =2 "." "00"μC"} {} , q b = 3 . 00 μC size 12{q rSub { size 8{b} } = - 3 "." "00"μC"} {} , q c = 4 . 00 μC size 12{q rSub { size 8{c} } = - 4 "." "00"μC"} {} , and q d =+ 1 . 00 μC size 12{q rSub { size 8{d} } "=+"1 "." "00"μC"} {} . The square is 50.0 cm on a side.

0 . 102 N , size 12{0 "." "102" N",} {} in the y size 12{ - y ital } {} {} {} {} direction

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(a) Find the electric field at the location of q a in [link] , given that q b = +10.00 μ C and q c = –5.00 μ C . (b) What is the force on q a , given that q a = +1.50 nC ?

Three point charges located at the corners of an equilateral triangle.
Point charges located at the corners of an equilateral triangle 25.0 cm on a side.
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(a) Find the electric field at the center of the triangular configuration of charges in [link] , given that q a =+ 2 . 50 nC size 12{q rSub { size 8{a} } "=+"2 "." "50"nC"} {} , q b = 8 . 00 nC size 12{q rSub { size 8{b} } = - 8 "." "00"nC"} {} , and q c =+ 1 . 50 nC size 12{q rSub { size 8{c} } "=+"1 "." "50"nC"} {} . (b) Is there any combination of charges, other than q a = q b = q c size 12{q rSub { size 8{a} } =q rSub { size 8{b} } =q rSub { size 8{c} } } {} , that will produce a zero strength electric field at the center of the triangular configuration?

(a) E = 4.36 × 10 3 N/C , 35.0º , below the horizontal.

(b) No

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Questions & Answers

Propose a force standard different from the example of a stretched spring discussed in the text. Your standard must be capable of producing the same force repeatedly.
Giovani Reply
What is meant by dielectric charge?
It's Reply
what happens to the size of charge if the dielectric is changed?
Brhanu Reply
omega= omega not +alpha t derivation
Provakar Reply
u have to derivate it respected to time ...and as w is the angular velocity uu will relace it with "thita × time""
Abrar
do to be peaceful with any body
Brhanu Reply
the angle subtended at the center of sphere of radius r in steradian is equal to 4 pi how?
Saeed Reply
if for diatonic gas Cv =5R/2 then gamma is equal to 7/5 how?
Saeed
define variable velocity
Ali Reply
displacement in easy way.
Mubashir Reply
binding energy per nucleon
Poonam Reply
why God created humanity
Manuel Reply
Because HE needs someone to dominate the earth (Gen. 1:26)
Olorunfemi
why god made humenity
Ali
Is the object in a conductor or an insulator? Justify your answer. whats the answer to this question? pls need help figure is given above
Jun Reply
ok we can say body is electrically neutral ...conductor this quality is given to most metalls who have free electron in orbital d ...but human doesn't have ...so we re made from insulator or dielectric material ... furthermore, the menirals in our body like k, Fe , cu , zn
Abrar
when we face electric shock these elements work as a conductor that's why we got this shock
Abrar
how do i calculate the pressure on the base of a deposit if the deposit is moving with a linear aceleration
ximena Reply
why electromagnetic induction is not used in room heater ?
Gopi Reply
room?
Abrar
What is position?
Amoah Reply
What is law of gravition
sushil Reply
Practice Key Terms 6

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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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