<< Chapter < Page Chapter >> Page >

If a galaxy is 500 Mly away from us, how fast do we expect it to be moving and in what direction?

Got questions? Get instant answers now!

On average, how far away are galaxies that are moving away from us at 2.0% of the speed of light?

0.30 Gly

Got questions? Get instant answers now!

Our solar system orbits the center of the Milky Way galaxy. Assuming a circular orbit 30,000 ly in radius and an orbital speed of 250 km/s, how many years does it take for one revolution? Note that this is approximate, assuming constant speed and circular orbit, but it is representative of the time for our system and local stars to make one revolution around the galaxy.

Got questions? Get instant answers now!

(a) What is the approximate speed relative to us of a galaxy near the edge of the known universe, some 10 Gly away? (b) What fraction of the speed of light is this? Note that we have observed galaxies moving away from us at greater than 0 . 9 c size 12{0 "." 9c} {} .

(a) 2 . 0 × 10 5 km/s size 12{2 "." 0 times "10" rSup { size 8{5} } `"km/s"} {}

(b) 0 . 67 c size 12{0 "." "67"c} {}

Got questions? Get instant answers now!

(a) Calculate the approximate age of the universe from the average value of the Hubble constant, H 0 = 20 km/s Mly size 12{H rSub { size 8{c} } ="20"`"km/s" cdot "Mly"} {} . To do this, calculate the time it would take to travel 1 Mly at a constant expansion rate of 20 km/s. (b) If deceleration is taken into account, would the actual age of the universe be greater or less than that found here? Explain.

Got questions? Get instant answers now!

Assuming a circular orbit for the Sun about the center of the Milky Way galaxy, calculate its orbital speed using the following information: The mass of the galaxy is equivalent to a single mass 1 . 5 × 10 11 size 12{1 "." 5 times "10" rSup { size 8{"11"} } } {} times that of the Sun (or 3 × 10 41 kg size 12{3 times "10" rSup { size 8{"41"} } `"kg"} {} ), located 30,000 ly away.

2 . 7 × 10 5 m/s size 12{2 "." 7 times "10" rSup { size 8{5} } `"m/s"} {}

Got questions? Get instant answers now!

(a) What is the approximate force of gravity on a 70-kg person due to the Andromeda galaxy, assuming its total mass is 10 13 size 12{"10" rSup { size 8{"13"} } } {} that of our Sun and acts like a single mass 2 Mly away? (b) What is the ratio of this force to the person’s weight? Note that Andromeda is the closest large galaxy.

Got questions? Get instant answers now!

Andromeda galaxy is the closest large galaxy and is visible to the naked eye. Estimate its brightness relative to the Sun, assuming it has luminosity 10 12 size 12{"10" rSup { size 8{"12"} } } {} times that of the Sun and lies 2 Mly away.

6 × 10 11 size 12{6 times "10" rSup { size 8{ - "11"} } } {} (an overestimate, since some of the light from Andromeda is blocked by gas and dust within that galaxy)

Got questions? Get instant answers now!

(a) A particle and its antiparticle are at rest relative to an observer and annihilate (completely destroying both masses), creating two γ size 12{γ} {} rays of equal energy. What is the characteristic γ size 12{γ} {} -ray energy you would look for if searching for evidence of proton-antiproton annihilation? (The fact that such radiation is rarely observed is evidence that there is very little antimatter in the universe.) (b) How does this compare with the 0.511-MeV energy associated with electron-positron annihilation?

Got questions? Get instant answers now!

The average particle energy needed to observe unification of forces is estimated to be 10 19 GeV . (a) What is the rest mass in kilograms of a particle that has a rest mass of 10 19 GeV/ c 2 size 12{"10""" lSup { size 8{"19"} } `"GeV/"c rSup { size 8{2} } } {} ? (b) How many times the mass of a hydrogen atom is this?

(a) 2 × 10 8 kg size 12{2 times "10" rSup { size 8{ - 8} } `"kg"} {}

(b) 1 × 10 19 size 12{1 times "10" rSup { size 8{"19"} } } {}

Got questions? Get instant answers now!

The peak intensity of the CMBR occurs at a wavelength of 1.1 mm. (a) What is the energy in eV of a 1.1-mm photon? (b) There are approximately 10 9 size 12{"10" rSup { size 8{9} } } {} photons for each massive particle in deep space. Calculate the energy of 10 9 size 12{"10" rSup { size 8{9} } } {} such photons. (c) If the average massive particle in space has a mass half that of a proton, what energy would be created by converting its mass to energy? (d) Does this imply that space is “matter dominated”? Explain briefly.

Got questions? Get instant answers now!

(a) What Hubble constant corresponds to an approximate age of the universe of 10 10 size 12{"10" rSup { size 8{"10"} } } {} y? To get an approximate value, assume the expansion rate is constant and calculate the speed at which two galaxies must move apart to be separated by 1 Mly (present average galactic separation) in a time of 10 10 size 12{"10" rSup { size 8{"10"} } } {} y. (b) Similarly, what Hubble constant corresponds to a universe approximately 2 × 10 10 size 12{2 times "10" rSup { size 8{"10"} } } {} -y old?

(a) 30 km/s Mly size 12{"30"`"km/s" cdot "Mly"} {}

(b) 15 km/s Mly size 12{"15"`"km/s" cdot "Mly"} {}

Got questions? Get instant answers now!

Show that the velocity of a star orbiting its galaxy in a circular orbit is inversely proportional to the square root of its orbital radius, assuming the mass of the stars inside its orbit acts like a single mass at the center of the galaxy. You may use an equation from a previous chapter to support your conclusion, but you must justify its use and define all terms used.

Got questions? Get instant answers now!

The core of a star collapses during a supernova, forming a neutron star. Angular momentum of the core is conserved, and so the neutron star spins rapidly. If the initial core radius is 5 . 0 × 10 5 km size 12{5 "." 0 times "10" rSup { size 8{5} } `"km"} {} and it collapses to 10.0 km, find the neutron star’s angular velocity in revolutions per second, given the core’s angular velocity was originally 1 revolution per 30.0 days.

960 rev/s

Got questions? Get instant answers now!

Using data from the previous problem, find the increase in rotational kinetic energy, given the core’s mass is 1.3 times that of our Sun. Where does this increase in kinetic energy come from?

Got questions? Get instant answers now!

Distances to the nearest stars (up to 500 ly away) can be measured by a technique called parallax, as shown in [link] . What are the angles θ 1 size 12{θ rSub { size 8{1} } } {} and θ 2 size 12{θ rSub { size 8{2} } } {} relative to the plane of the Earth’s orbit for a star 4.0 ly directly above the Sun?

89 . 999773º size 12{"89" "." "999773"°} {} (many digits are used to show the difference between 90º )

Got questions? Get instant answers now!

(a) Use the Heisenberg uncertainty principle to calculate the uncertainty in energy for a corresponding time interval of 10 43 s size 12{"10" rSup { size 8{ - "34"} } `s} {} . (b) Compare this energy with the 10 19 GeV size 12{"10" rSup { size 8{"19"} } `"GeV"} {} unification-of-forces energy and discuss why they are similar.

Got questions? Get instant answers now!

Construct Your Own Problem

Consider a star moving in a circular orbit at the edge of a galaxy. Construct a problem in which you calculate the mass of that galaxy in kg and in multiples of the solar mass based on the velocity of the star and its distance from the center of the galaxy.

The figure shows a conical shape with a star at the vertex, the Sun at the center of the circular base, and the Earth revolving around the Sun along the perimeter of the base. The star is 4 light years above the Earth-Sun plane. When the Earth is to the far left of the Sun, the angle between the line segment from the Earth to the Sun and the line segment from the Earth to the star is called theta one. When the Earth is in the diametrically opposite position (that is, the far right position) the angle between the same two lines is labeled theta two.
Distances to nearby stars are measured using triangulation, also called the parallax method. The angle of line of sight to the star is measured at intervals six months apart, and the distance is calculated by using the known diameter of the Earth’s orbit. This can be done for stars up to about 500 ly away.
Got questions? Get instant answers now!

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, College physics. OpenStax CNX. Jul 27, 2015 Download for free at http://legacy.cnx.org/content/col11406/1.9
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'College physics' conversation and receive update notifications?

Ask