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Errors propagate through mathematical operations.

In this module, we shall introduce some statistical analysis techniques to improve our understanding about error and enable reporting of error in the measurement of a quantity. There are basically three related approaches, which involves measurement of :

  • Absolute error
  • Relative error
  • Percentage error

Absolute error

The absolute error is the magnitude of error as determined from the difference of measured value from the mean value of the quantity. The important thing to note here is that absolute error is concerned with the magnitude of error – not the direction of error. For a particular n t h measurement,

| Δ x n | = | x m - x n |

where " x m " is the mean or average value of measurements and " x n " is the n t h instant of measurement.

In order to calculate few absolute values, we consider a set of measured data for the length of a given rod. Note that we are reporting measurements in centimeter.

x 1 = 47.7 c m , x 2 = 47.5 c m , x 3 = 47.8 c m , x 4 = 47.4 c m , x 5 = 47.7 c m

The means value of length is :

x m = 47.7 + 47.5 + 47.8 + 47.4 + 47.7 5 = 238.1 5 = 47.62

It is evident from the individual values that the least count of the scale (smallest division) is 0.001 m = 0.1 cm. For this reason, we limit mean value to the first decimal place. Hence, we round off the last but one digit as :

x m = 47.6 c m

This is the mean or true value of the length of the rod. Now, absolute error of each of the five measurements are :

| Δ x 1 | = | x m x 1 | = | 47.6 47.7 | = | 0.1 | = 0.1

| Δ x 2 | = | x m x 2 | = | 47.6 47.5 | = | 0.1 | = 0.1

| Δ x 3 | = | x m x 3 | = | 47.6 47.8 | = | 0.2 | = 0.2

| Δ x 4 | = | x m x 4 | = | 47.6 47.4 | = | 0.2 | = 0.2

| Δ x 5 | = | x m x 5 | = | 47.6 47.7 | = | - 0.1 | = 0.1

Mean absolute error

Earlier, it was stated that a quantity is measured with a range of error specified by half the least count. This is a generally accepted range of error. Here, we shall work to calculate the range of the error, based on the actual measurements and not go by any predefined range of error as that of generally accepted range of error. This means that we want to determine the range of error, which is based on the deviations in the reading from the mean value.

Absolute error associated with each measurement tells us how far the measurement can be off the mean value. The absolute errors so calculated, however, may be different. Now the question is : which of the absolute error be taken for our consideration? We take the average of the absolute error :

Δ x m = Δ x 1 + Δ x 2 + . + Δ x n n

Δ x m = Σ 0 n Δ x i n

The value of measurement, now, will be reported with the range of error as :

x = x m ± Δ x m

Extending this concept of defining range to the earlier example, we have :

Δ x m = 0.1 + 0.1 + 0.2 + 0.2 + 0.1 5 = 0.7 5 = 0.14 = 0.1 c m

We should note here that we have rounded the result to reflect that the error value has same precision as that of measured value. The value of measurement with the range of error, then, is :

x = 47.6 ± 0.1 c m

What we convey by writing in terms of the range of possible error. A plain reading of above expression is “the length of rod lies in between 47.5 cm and 47.7 cm”. For all practical purpose, we shall use the value of x = 47.6 cm with the caution in mind that this quantity involves an error of the magnitude of “0.1 cm” in either direction.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Source:  OpenStax, Physics for k-12. OpenStax CNX. Sep 07, 2009 Download for free at http://cnx.org/content/col10322/1.175
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