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Units of force

F net = m a size 12{F rSub { size 8{"net"} } =ma} {} is used to define the units of force in terms of the three basic units for mass, length, and time. The SI unit of force is called the newton (abbreviated N) and is the force needed to accelerate a 1-kg system at the rate of 1 m/s 2 size 12{1" m/s" rSup { size 8{2} } } {} . That is, since F net = m a size 12{F rSub { size 8{"net"} } =ma} {} ,

1 N = 1 kg m/s 2 size 12{"1 N "=" 1 kg" cdot "m/s^2"} {} .

While almost the entire world uses the newton for the unit of force, in the United States the most familiar unit of force is the pound (lb), where 1 N = 0.225 lb.

Weight and the gravitational force

When an object is dropped, it accelerates toward the center of Earth. Newton’s second law states that a net force on an object is responsible for its acceleration. If air resistance is negligible, the net force on a falling object is the gravitational force, commonly called its weight     w size 12{w} {} . Weight can be denoted as a vector w size 12{w} {} because it has a direction; down is, by definition, the direction of gravity, and hence weight is a downward force. The magnitude of weight is denoted as w size 12{w} {} . Galileo was instrumental in showing that, in the absence of air resistance, all objects fall with the same acceleration g size 12{g} {} . Using Galileo’s result and Newton’s second law, we can derive an equation for weight.

Consider an object with mass m size 12{m} {} falling downward toward Earth. It experiences only the downward force of gravity, which has magnitude w size 12{w} {} . Newton’s second law states that the magnitude of the net external force on an object is F net = ma size 12{F rSub { size 8{"net"} } = ital "ma"} {} .

Since the object experiences only the downward force of gravity, F net = w size 12{F rSub { size 8{"net"} } =w} {} . We know that the acceleration of an object due to gravity is g , or a = g size 12{a=g} {} . Substituting these into Newton’s second law gives

Weight

This is the equation for weight —the gravitational force on a mass m size 12{m} {} :

w = mg size 12{w= ital "mg"} {} .

Since g = 9.80 m/s 2 size 12{g=9 "." "80"" m/s" rSup { size 8{2} } } {} on Earth, the weight of a 1.0 kg object on Earth is 9.8 N, as we see:

w = mg = ( 1 . 0 kg ) ( 9.80 m/s 2 ) = 9.8 N size 12{w= ital "mg"= \( 1 "." "0 kg" \) \( 9 "." "80 m/s" rSup { size 8{2} } \) =9 "." 8" N"} {} .

Recall that g size 12{g} {} can take a positive or negative value, depending on the positive direction in the coordinate system. Be sure to take this into consideration when solving problems with weight.

When the net external force on an object is its weight, we say that it is in free-fall    . That is, the only force acting on the object is the force of gravity. In the real world, when objects fall downward toward Earth, they are never truly in free-fall because there is always some upward force from the air acting on the object.

The acceleration due to gravity g size 12{g} {} varies slightly over the surface of Earth, so that the weight of an object depends on location and is not an intrinsic property of the object. Weight varies dramatically if one leaves Earth’s surface. On the Moon, for example, the acceleration due to gravity is only 1.67 m/s 2 size 12{1 "." "67"" m/s" rSup { size 8{2} } } {} . A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N on the Moon.

The broadest definition of weight in this sense is that the weight of an object is the gravitational force on it from the nearest large body , such as Earth, the Moon, the Sun, and so on. This is the most common and useful definition of weight in physics. It differs dramatically, however, from the definition of weight used by NASA and the popular media in relation to space travel and exploration. When they speak of “weightlessness” and “microgravity,” they are really referring to the phenomenon we call “free-fall” in physics. We shall use the above definition of weight, and we will make careful distinctions between free-fall and actual weightlessness.

Questions & Answers

sound waves can be modeled as a change in pressure ,why is the change on in pressure used and not the actual pressure
Dotto Reply
what is the best
Kelly Reply
Water,air,fire
Maung
I am a university student of Myanmar.I am first year,first semester.I want to learn about physics.
Maung
two charges qA and qB are separated by a distance x. if we double the distance between the charges and triple the magnitude of the charge A, what happens to the magnitude of the force that charge A exerts on charge B. what happens to the magnitude of the force that charge B exerts on charge A
tanla Reply
how to get mcq and essay?
Owen Reply
what is force
Ibrahim Reply
force is a pull or push action on an object or a body.
joseph
what is a significant figure? and give example
Frederick
numerical chapter number 3
Sajid Reply
joined
Ibrahim
a reflected ray on a mirror makes an angle of 20degree with the incident ray when the mirror is rotated 15degree what angle will the incident ray now make with the reflected ray
Akinyemi Reply
what is simple harmonic motion
Solomon Reply
how vapour pressure of a liquid lost through convection
Yomzi Reply
Roofs are sometimes pushed off vertically during a tropical cyclone, and buildings sometimes explode outward when hit by a tornado. Use Bernoulli’s principle to explain these phenomena.
Aliraza Reply
Plz answer the question ☝️☝️
Aliraza
what's the basic si unit of acceleration
ELLOIN Reply
Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.
Fabian Reply
Insulators (nonmetals) have a higher BE than metals, and it is more difficult for photons to eject electrons from insulators. Discuss how this relates to the free charges in metals that make them good conductors.
Muhammad Reply
Is the photoelectric effect a direct consequence of the wave character of EM radiation or of the particle character of EM radiation? Explain briefly.
Muhammad
Determine the total force and the absolute pressure on the bottom of a swimming pool 28.0m by 8.5m whose uniform depth is 1 .8m.
Henny Reply
how solve this problem?
Foday
P(pressure)=density ×depth×acceleration due to gravity Force =P×Area(28.0x8.5)
Fomukom
for the answer to complete, the units need specified why
muqaddas Reply
That's just how the AP grades. Otherwise, you could be talking about m/s when the answer requires m/s^2. They need to know what you are referring to.
Kyle
Practice Key Terms 7

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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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