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Test prep for ap courses

Two particles with charges +2 q and + q are separated by a distance r . The +2 q particle has an electric field E at distance r and exerts a force F on the + q particle. Use this information to answer questions 31–32.

What is the electric field of the + q particle at the same distance and what force does it exert on the +2 q particle?

  1. E /2, F /2
  2. E , F /2
  3. E /2, F
  4. E , F

(c)

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When the + q particle is replaced by a +3 q particle, what will be the electric field and force from the +2 q particle experienced by the +3 q particle?

  1. E /3, 3 F
  2. E , 3 F
  3. E /3, F
  4. E , F
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The direction of the electric field of a negative charge is

  1. inward for both positive and negative charges.
  2. outward for both positive and negative charges.
  3. inward for other positive charges and outward for other negative charges.
  4. outward for other positive charges and inward for other negative charges.

(a)

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The force responsible for holding an atom together is

  1. frictional
  2. electric
  3. gravitational
  4. magnetic
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When a positively charged particle exerts an inward force on another particle P , what will be the charge of P ?

  1. positive
  2. negative
  3. neutral
  4. cannot be determined

(b)

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Find the force exerted due to a particle having a charge of 3.2×10 −19 C on another identical particle 5 cm away.

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Suppose that the force exerted on an electron is 5.6×10 −17 N, directed to the east.

  1. Find the magnitude of the electric field that exerts the force.
  2. What will be the direction of the electric field?
  3. If the electron is replaced by a proton, what will be the magnitude of force exerted?
  4. What will be the direction of force on the proton?

(a) 350 N/C, (b) west, (c) 5.6×10−17 N, (d) west.

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Section summary

  • The electrostatic force field surrounding a charged object extends out into space in all directions.
  • The electrostatic force exerted by a point charge on a test charge at a distance r size 12{r} {} depends on the charge of both charges, as well as the distance between the two.
  • The electric field E size 12{E} {} is defined to be
    E = F q , size 12{E= { {F} over {q,} } } {}

    where F size 12{F} {} is the Coulomb or electrostatic force exerted on a small positive test charge q size 12{q} {} . E size 12{E} {} has units of N/C.

  • The magnitude of the electric field E size 12{E} {} created by a point charge Q size 12{Q} {} is
    E = k | Q | r 2 . size 12{E=k { {Q} over {r rSup { size 8{2} } } } } {}

    where r size 12{r} {} is the distance from Q size 12{Q} {} . The electric field E size 12{E} {} is a vector and fields due to multiple charges add like vectors.

Conceptual questions

Why must the test charge q size 12{q} {} in the definition of the electric field be vanishingly small?

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Are the direction and magnitude of the Coulomb force unique at a given point in space? What about the electric field?

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Problem exercises

What is the magnitude and direction of an electric field that exerts a 2 . 00 × 10 - 5 N size 12{2 "." "00" times "10" rSup { size 8{5} } N} {} upward force on a –1.75 μ C charge?

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What is the magnitude and direction of the force exerted on a 3.50 μ C charge by a 250 N/C electric field that points due east?

8 . 75 × 10 4 size 12{8 "." "75" times "10" rSup { size 8{ - 4} } } {} N

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Calculate the magnitude of the electric field 2.00 m from a point charge of 5.00 mC (such as found on the terminal of a Van de Graaff).

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(a) What magnitude point charge creates a 10,000 N/C electric field at a distance of 0.250 m? (b) How large is the field at 10.0 m?

(a) 6 . 94 × 10 8 C size 12{ {underline {6 "." "94" times "10" rSup { size 8{ - 8} } " C"}} } {}

(b) 6 . 25 N/C size 12{ {underline {6 "." "25" N/C"}} } {}

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Calculate the initial (from rest) acceleration of a proton in a 5 . 00 × 10 6 N/C size 12{5 "." "00" times "10" rSup { size 8{6} } "N/C"} {} electric field (such as created by a research Van de Graaff). Explicitly show how you follow the steps in the Problem-Solving Strategy for electrostatics.

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(a) Find the direction and magnitude of an electric field that exerts a 4 . 80 × 10 17 N size 12{4 "." "80" times "10" rSup { size 8{ - "17"} } N} {} westward force on an electron. (b) What magnitude and direction force does this field exert on a proton?

(a) 300 N/C ( east ) size 12{ {underline {"300" N/C " \( "eas"}} {underline {t \) }} } {}

(b) 4 . 80 × 10 17 N ( east ) size 12{ {underline {4 "." "80" times "10" rSup { size 8{ - "17"} } " N " \( "east" \) }} } {}

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Questions & Answers

sound waves can be modeled as a change in pressure ,why is the change on in pressure used and not the actual pressure
Dotto Reply
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Water,air,fire
Maung
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Maung
two charges qA and qB are separated by a distance x. if we double the distance between the charges and triple the magnitude of the charge A, what happens to the magnitude of the force that charge A exerts on charge B. what happens to the magnitude of the force that charge B exerts on charge A
tanla Reply
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force is a pull or push action on an object or a body.
joseph
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Ibrahim
a reflected ray on a mirror makes an angle of 20degree with the incident ray when the mirror is rotated 15degree what angle will the incident ray now make with the reflected ray
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Roofs are sometimes pushed off vertically during a tropical cyclone, and buildings sometimes explode outward when hit by a tornado. Use Bernoulli’s principle to explain these phenomena.
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Aliraza
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ELLOIN Reply
Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.
Fabian Reply
Insulators (nonmetals) have a higher BE than metals, and it is more difficult for photons to eject electrons from insulators. Discuss how this relates to the free charges in metals that make them good conductors.
Muhammad Reply
Is the photoelectric effect a direct consequence of the wave character of EM radiation or of the particle character of EM radiation? Explain briefly.
Muhammad
Determine the total force and the absolute pressure on the bottom of a swimming pool 28.0m by 8.5m whose uniform depth is 1 .8m.
Henny Reply
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Foday
P(pressure)=density ×depth×acceleration due to gravity Force =P×Area(28.0x8.5)
Fomukom
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muqaddas Reply
That's just how the AP grades. Otherwise, you could be talking about m/s when the answer requires m/s^2. They need to know what you are referring to.
Kyle
Practice Key Terms 3

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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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