<< Chapter < Page Chapter >> Page >

For this question, consider the circuit shown in the following figure.

Circuit that across the top from left to right goes point b, battery with voltage E1, point c, resistor with resistance r1, and point d; across the middle goes point a, battery with voltage E2, point k, resistor with resistance r2, point l, resistor with resistance R2, and point e; across the bottom goes point j, battery with voltage E3, point i, resistor with resistance r3, and point h; along the left side from top to bottom goes a resistor with resistance R1, point a, and a resistor with resistance R3; and along the right side goes a resistor with resistance R5, point e, a resistor with resistance r4, point f, a battery with voltage E4, and point g. Additionally, there are three arrows showing the direction of the current: one between point a and the resistor with resistance R1 pointing up; another between point a and the battery with voltage E2 pointing right; and another between point j and the resistor with resistance R3 pointing up.
  1. Assuming that none of the three currents ( I 1 , I 2 , and I 3 ) are equal to zero, which of the following statements is false?

    1. I 3 = I 1 + I 2 at point a .
    2. I 2 = I 3 - I 1 at point e .
    3. The current through R 3 is equal to the current through R 5.
    4. The current through R 1 is equal to the current through R 5.
  2. Which of the following statements is true?

    1. E 1 + E 2 + I 1 R 1 - I 2 R 2 + I 1 r 1 - I 2 r 2 + I 1 R 5 = 0
    2. - E 1 + E 2 + I 1 R 1 - I 2 R 2 + I 1 r 1 - I 2 r 2 - I 1 R 5 = 0
    3. E 1 - E 2 - I 1 R 1 + I 2 R 2 - I 1 r 1 + I 2 r 2 - I 1 R 5 = 0
    4. E 1 + E 2 - I 1 R 1 + I 2 R 2 - I 1 r 1 + I 2 r 2 + I 1 R 5 = 0
  3. If I 1 = 5 A and I 3 = -2 A, which of the following statements is false?

    1. The current through R 1 will flow from a to b and will be equal to 5 A.
    2. The current through R 3 will flow from a to j and will be equal to 2 A.
    3. The current through R 5 will flow from d to e and will be equal to 5 A.
    4. None of the above.
  4. If I 1 = 5 A and I 3 = -2 A, I 2 will be equal to

    1. 3 A
    2. -3 A
    3. 7 A
    4. -7 A

a. (c)

b. (c)

c. (d)

d. (d)

Got questions? Get instant answers now!
A circuit with nothing on the top or bottom, but a battery marked E on the left, a resistor marked R1 in the middle, and a resistor marked R2 on the right.

In an experiment this circuit is set up. Three ammeters are used to record the currents in the three vertical branches (with R 1 , R 2 , and E) . The readings of the ammeters in the resistor branches (i.e. currents in R 1 and R 2 ) are 2 A and 3 A respectively.

  1. Find the equation obtained by applying Kirchhoff’s loop rule in the loop involving R 1 and R 2 .
  2. What will be the reading of the third ammeter (i.e. the branch with E )? If E were replaced by 3 E , how would this reading change?
  3. If the original circuit is modified by adding another voltage source (as shown in the following circuit), find the readings of the three ammeters.
A circuit a battery marked E on the left, a resistor marked R1 in the middle, and a resistor marked R2 on the right. There is nothing on the bottom, and on the top, there is a battery marked 2E between the two resistors.
Got questions? Get instant answers now!
Circuit with a battery with voltage E1 and resistor with resistance r1 across the top from left to right; point A, a resistor with resistance R1, and point B across the middle; and a battery marked E2 and a resistor with resistance r2 across the bottom. Additionally, on the left, from top to bottom there is a resistor with resistance R2 and point A; on the right, from top to bottom there is point B and a resistor with resistance R3.

In this circuit, assume the currents through R 1 , R 2 and R 3 are I 1 , I 2 and I 3 respectively and all are flowing in the clockwise direction.

  1. Find the equation obtained by applying Kirchhoff’s junction rule at point A.
  2. Find the equations obtained by applying Kirchhoff’s loop rule in the upper and lower loops.
  3. Assume R 1 = R 2 = 6 Ω, R 3 = 12 Ω, r 1 = r 2 = 0 Ω, E 1 = 6 V and E 2 = 4 V. Calculate I 1 , I 2 and I 3 .
  4. For the situation in which E 2 is replaced by a closed switch, repeat parts (a) and (b). Using the values for R 1 , R 2 , R 3 , r 1 and E 1 from part (c) calculate the currents through the three resistors.
  5. For the circuit in part (d) calculate the output power of the voltage source and across all the resistors. Examine if energy is conserved in the circuit.
  6. A student implemented the circuit of part (d) in the lab and measured the current though one of the resistors as 0.19 A. According to the results calculated in part (d) identify the resistor(s). Justify any difference in measured and calculated value.
  1. I 1 + I 3 = I 2
  2. E 1 - I 1 R 1 - I 2 R 2 - I 1 r 1 = 0; - E 2 + I 1 R 1 - I 3 R 3 - I 3 r 2 = 0
  3. I 1 = 8/15 A, I 2 = 7/15 A and I 3 = - 1/15 A
  4. I 1 = 2/5 A, I 2 = 3/5 A and I 3 = 1/5 A
  5. P E1 = 18/5 W and P R1 = 24/25 W, P R2 = 54/25 W, P R3 = 12/25 W. Yes, P E1 = P R1 + P R2 + P R3
  6. R 3, losses in the circuit
Got questions? Get instant answers now!

Section summary

  • Kirchhoff’s rules can be used to analyze any circuit, simple or complex.
  • Kirchhoff’s first rule—the junction rule: The sum of all currents entering a junction must equal the sum of all currents leaving the junction.
  • Kirchhoff’s second rule—the loop rule: The algebraic sum of changes in potential around any closed circuit path (loop) must be zero.
  • The two rules are based, respectively, on the laws of conservation of charge and energy.
  • When calculating potential and current using Kirchhoff’s rules, a set of conventions must be followed for determining the correct signs of various terms.
  • The simpler series and parallel rules are special cases of Kirchhoff’s rules.

Conceptual questions

Can all of the currents going into the junction in [link] be positive? Explain.

Got questions? Get instant answers now!
The diagram shows a T junction with currents I sub one, I sub two, and I sub three entering the T junction.

Apply the junction rule to junction b in [link] . Is any new information gained by applying the junction rule at e? (In the figure, each emf is represented by script E.)

Got questions? Get instant answers now!
The diagram shows a complex circuit with four voltage sources: E sub one, E sub two, E sub three, E sub four and several resistive loads, wired in two loops and two junctions. Several points on the diagram are marked with letters a through g. The current in each branch is labeled separately.

(a) What is the potential difference going from point a to point b in [link] ? (b) What is the potential difference going from c to b? (c) From e to g? (d) From e to d?

Got questions? Get instant answers now!

Apply the loop rule to loop afedcba in [link] .

Got questions? Get instant answers now!

Apply the loop rule to loops abgefa and cbgedc in [link] .

Got questions? Get instant answers now!

Problem exercises

Apply the loop rule to loop abcdefgha in [link] .

I 2 R 2 + emf 1 I 2 r 1 + I 3 R 3 + I 3 r 2 - emf 2 = 0 size 12{ {underline {-I rSub { size 8{2} } R rSub { size 8{3} } + "emf" rSub { size 8{1} } - ital " I" rSub { size 8{2} } r rSub { size 8{1} } + ital " I" rSub { size 8{3} } r rSub { size 8{3} } + ital " I" rSub { size 8{3} } r rSub { size 8{2} } +- "emf" rSub { size 8{2} } =" 0"}} } {}

Got questions? Get instant answers now!

Apply the loop rule to loop aedcba in [link] .

Got questions? Get instant answers now!

Verify the second equation in [link] by substituting the values found for the currents I 1 size 12{I rSub { size 8{1} } } {} and I 2 size 12{I rSub { size 8{2} } } {} .

Got questions? Get instant answers now!

Verify the third equation in [link] by substituting the values found for the currents I 1 size 12{I rSub { size 8{1} } } {} and I 3 size 12{I rSub { size 8{3} } } {} .

Got questions? Get instant answers now!

Apply the junction rule at point a in [link] .

The diagram shows a complex circuit with four voltage sources E sub one, E sub two, E sub three, E sub four and several resistive loads, wired in two loops and many junctions. Several points on the diagram are marked with letters a through j. The current in each branch is labeled separately.

I 3 = I 1 + I 2 size 12{I rSub { size 8{3} } = ital " I" rSub { size 8{1} } + ital " I" rSub { size 8{2} } } {}

Got questions? Get instant answers now!

Apply the loop rule to loop abcdefghija in [link] .

Got questions? Get instant answers now!

Apply the loop rule to loop akledcba in [link] .

emf 2 - I 2 r 2 - I 2 R 2 + I 1 R 5 + I 1 r 1 - emf 1 + I 1 R 1 = 0 size 12{ {underline { "emf" rSub { size 8{2} } +- ital " I" rSub { size 8{2} } r rSub { size 8{2} } +- ital " I" rSub { size 8{2} } R rSub { size 8{2} } + ital " I" rSub { size 8{1} } R rSub { size 8{5} } +I rSub { size 8{1} } r rSub { size 8{1} } +- "emf" rSub { size 8{1} } + ital " I" rSub { size 8{1} } R rSub { size 8{1} } = 0}} } {}

Got questions? Get instant answers now!

Find the currents flowing in the circuit in [link] . Explicitly show how you follow the steps in the Problem-Solving Strategies for Series and Parallel Resistors .

Got questions? Get instant answers now!

Solve [link] , but use loop abcdefgha instead of loop akledcba. Explicitly show how you follow the steps in the Problem-Solving Strategies for Series and Parallel Resistors .

(a) I 1 = 4.75 A size 12{I rSub { size 8{1} } =4 cdot "75 A"} {}

(b) I 2 = - 3 . 5 A size 12{I rSub { size 8{"2 "} } = +- 3 "." "5 A"} {} {}

(c) I 3 = 8 . 25 A size 12{I rSub { size 8{3} } =8 "." "25"" A"} {}

Got questions? Get instant answers now!

Find the currents flowing in the circuit in [link] .

Got questions? Get instant answers now!

Unreasonable Results

Consider the circuit in [link] , and suppose that the emfs are unknown and the currents are given to be I 1 = 5 . 00 A , I 2 = 3 .0 A size 12{I rSub { size 8{2} } =3 "." 0" A"} {} , and I 3 = –2 . 00 A size 12{I rSub { size 8{3} } "=-"2 "." "00"" A"} {} . (a) Could you find the emfs? (b) What is wrong with the assumptions?

The diagram shows a complex circuit with two voltage sources E sub one and E sub two, and three resistive loads, wired in two loops and two junctions. Several points on the diagram are marked with letters a through h. The current in each branch is labeled separately.

(a) No, you would get inconsistent equations to solve.

(b) I 1 I 2 + I 3 size 12{I rSub { size 8{1} }<>I rSub { size 8{2} } +I rSub { size 8{3} } } {} . The assumed currents violate the junction rule.

Got questions? Get instant answers now!

Questions & Answers

it is the relatively stable flow of income
Chidubem Reply
what is circular flow of income
Divine Reply
branches of macroeconomics
SHEDRACK Reply
what is Flexible exchang rate?
poudel Reply
is gdp a reliable measurement of wealth
Atega Reply
introduction to econometrics
Husseini Reply
Hi
mostafa
hi
LEMLEM
hello
Sammol
hi
Mahesh
bi
Ruqayat
hi
Ruqayat
Hi fellas
Nyawa
hey
Sammol
hi
God
hello
Jahara
Good morning
Jorge
hi
abubakar
hi
Nmesoma
hi
Mahesh
Hi
Tom
Why is unemployment rate never zero at full employment?
Priyanka Reply
bcoz of existence of frictional unemployment in our economy.
Umashankar
what is flexible exchang rate?
poudel
due to existence of the pple with disabilities
Abdulraufu
the demand of a good rises, causing the demand for another good to fall
Rushawn Reply
is it possible to leave every good at the same level
Joseph
I don't think so. because check it, if the demand for chicken increases, people will no longer consume fish like they used to causing a fall in the demand for fish
Anuolu
is not really possible to let the value of a goods to be same at the same time.....
Salome
Suppose the inflation rate is 6%, does it mean that all the goods you purchase will cost 6% more than previous year? Provide with reasoning.
Geetha Reply
Not necessarily. To measure the inflation rate economists normally use an averaged price index of a basket of certain goods. So if you purchase goods included in the basket, you will notice that you pay 6% more, otherwise not necessarily.
Waeth
discus major problems of macroeconomics
Alii Reply
what is the problem of macroeconomics
Yoal
Economic growth Stable prices and low unemployment
Ephraim
explain inflationcause and itis degre
Miresa Reply
what is inflation
Getu
increase in general price levels
WEETO
Good day How do I calculate this question: C= 100+5yd G= 2000 T= 2000 I(planned)=200. Suppose the actual output is 3000. What is the level of planned expenditures at this level of output?
Chisomo Reply
how to calculate actual output?
Chisomo
how to calculate the equilibrium income
Beshir
Criteria for determining money supply
Thapase Reply
who we can define macroeconomics in one line
Muhammad
Aggregate demand
Mohammed
C=k100 +9y and i=k50.calculate the equilibrium level of output
Mercy Reply
Hi
Isiaka
Hi
Geli
hy
Man
👋
Bahunda
hy how are you?
Man
ys
Amisha
how are you guys
Sekou
f9 guys
Amisha
how are you guys
Sekou
ys am also fine
Amisha
fine and you guys
Geli
from Nepal
Amisha
nawalparasi district from belatari
Amisha
nd u
Amisha
I am Camara from Guinea west Africa... happy to meet you guys here
Sekou
ma management ho
Amisha
ahile becheclor ho
Amisha
hjr ktm bta ho ani k kaam grnu hunxa tw
Amisha
belatari
Amisha
1st year ho
Amisha
nd u
Amisha
ahh
Amisha
kaha biratnagar
Amisha
ys
Amisha
kina k vo
Amisha
money as unit of account means what?
Kalombe
A unit of account is something that can be used to value goods and services and make calculations
Jim
all of you please speak in English I can't understand you're language
Muhammad
I want to know how can we define macroeconomics in one line
Muhammad
it must be .9 or 0.9 no Mpc is greater than 1 Y=100+.9Y+50 Y-.9Y=150 0.1Y/0.1=150/0.1 Y=1500
Kalombe
Mercy is it clear?😋
Kalombe
hi can someone help me on this question If a negative shocks shifts the IS curve to the left, what type of policy do you suggest so as to stabilize the level of output? discuss your answer using appropriate graph.
Galge Reply
if interest rate is increased this will will reduce the level of income shifting the curve to the left ◀️
Kalombe
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 4

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'College physics for ap® courses' conversation and receive update notifications?

Ask