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This module provides practice problems designed to develop concepts related to the rules of exponents.

Here are the first six powers of two.

  • 2 1 2
  • 2 2 4
  • 2 3 8
  • 2 4 16
  • 2 5 32
  • 2 6 64
  • A

    If I asked you for 2 7 (without a calculator), how would you get it? More generally, how do you always get from one term in this list to the next term ?
  • B

    IWrite an algebraic generalization to represent this rule.
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Suppose I want to multiply 2 5 times 2 3 . Well, 2 5 means 2×2×2×2×2, and 2 3 means 2×2×2. So we can write the whole thing out like this.

  • A

    This shows that ( 2 5 2 3 2 [ ]
  • B

    Using a similar drawing, demonstrate what 10 3 10 4 must be.
  • C

    Now, write an algebraic generalization for this rule.
  • D

    Show how your answer to 1b (the “getting from one power of two, to the next in line”) is a special case of the more general rule you came up with in 2c (“multiplying two exponents”).
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Now we turn our attention to division. What is 3 12 3 10 size 12{ { {3 rSup { size 8{"12"} } } over {3 rSup { size 8{"10"} } } } } {} ?

  • A

    Write it out explicitly. (Like earlier I wrote out explicitly what 2 5 2 3 was: expand the exponents into a big long fraction.)
  • B

    Now, cancel all the like terms on the top and the bottom. (That is, divide the top and bottom by all the 3s they have in common.)
  • C

    What you are left with is the answer. So fill this in: 3 12 3 10 size 12{ { {3 rSup { size 8{"12"} } } over {3 rSup { size 8{"10"} } } } } {} 3 [ ] .
  • D

    Write a generalization that represents this rule.
  • E

    Suppose we turn it upside-down. Now, we end up with some 3s on the bottom. Write it out explicitly and cancel 3s, as you did before: 3 10 3 12 size 12{ { {3 rSup { size 8{"10"} } } over {3 rSup { size 8{"12"} } } } } {} = ___________________________ = 1 3 size 12{ { {1} over {3 rSup { size 8{ left [~ right ]} } } } } {}
  • F

    Write a generalization for the rule in part (e). Be sure to mention when that generalization applies, as opposed to the one in part (d)!
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Use all those generalizations to simplify x 3 y 3 x 7 x 5 y 5 size 12{ { {x rSup { size 8{3} } y rSup { size 8{3} } x rSup { size 8{7} } } over {x rSup { size 8{5} } y rSup { size 8{5} } } } } {}

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Now we’re going to raise exponents, to exponents. What is 2 3 4 ? Well, 2 3 means 2×2×2. And when you raise anything to the fourth power, you multiply it by itself, four times. So we’ll multiply that by itself four times:

2 3 4 = (2×2×2) (2×2×2) (2×2×2) (2×2×2)

  • A

    So, just counting 2s, 2 3 4 2 [ ] .
  • B

    Expand out 10 5 3 in a similar way, and show what power of 10 it equals.
  • C

    Find the algebraic generalization that represents this rule.
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Source:  OpenStax, Advanced algebra ii: activities and homework. OpenStax CNX. Sep 15, 2009 Download for free at http://cnx.org/content/col10686/1.5
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