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Let X be the annual repayment, i is the interest rate, and M is the amount of the mortgage bond you will be taking out.

Time lines are particularly useful tools for visualizing the series of payments for calculations, and we can represent these payments on a time line as:

Time Line for an annuity (in arrears) of X for n periods.

The present value of all the payments (which includes interest) must equate to the (present) value of the mortgage loan amount.

Mathematically, you can write this as:

M = X ( 1 + i ) - 1 + X ( 1 + i ) - 2 + X ( 1 + i ) - 3 + . . . + X ( 1 + i ) - 20

The painful way of solving this problem would be to do the calculation for each of the terms above - which is 20 different calculations. Not only would you probably get bored along the way, but you are also likely to make a mistake.

Naturally, there is a simpler way of doing this! You can rewrite the above equation as follows:

M = X [ v 1 + v 2 + v 3 + . . . + v 20 ] where v i = ( 1 + i ) - 1 = 1 / ( 1 + i )

Of course, you do not have to use the method of substitution to solve this. We just find this a useful method because you can get rid of the negative exponents - which can be quite confusing! As an exercise - to show you are a real financial whizz - try to solve this without substitution. It is actually quite easy.

Now, the item in square brackets is the sum of a geometric sequence, as discussion in [link] . This can be re-written as follows, using what we know from Chapter  [link] of this text book:

v 1 + v 2 + v 3 + . . . + v n = v ( 1 + v + v 2 + . . . + v n - 1 ) = v ( 1 - v n 1 - v ) = 1 - v n 1 / v - 1 = 1 - ( 1 + i ) - n i

Note that we took out a common factor of v before using the formula for the geometric sequence.

So we can write:

M = X [ ( 1 - ( 1 + i ) - n ) i ]

This can be re-written:

X = M [ ( 1 - ( 1 + i ) - n ) i ] = M i 1 - ( 1 + i ) - n

So, this formula is useful if you know the amount of the mortgage bond you need and want to work out the repayment, or if you know how big a repayment you can afford and want to see what property you can buy.

For example, if I want to buy a house for R300 000 over 20 years, and the bank is going to charge me 15% per annum on the outstanding balance, then the annual repayment is:

X = M i 1 - ( 1 + i ) - n = R 300 000 × 0 , 15 1 - ( 1 + 0 , 15 ) - 20 = R 4 792 844

This means, each year for the next 20 years, I need to pay the bank R47 928,44 per year before I have paid off the mortgage bond.

On the other hand, if I know I will only have R30 000 a year to repay my bond, then how big a house can I buy? That is easy ....

M = X [ ( 1 - ( 1 + i ) - n ) i ] = R 30 000 [ ( 1 - ( 1 , 15 ) - 20 ) 0 , 15 ] = R 187 779 , 90

So, for R30 000 a year for 20 years, I can afford to buy a house of R187 800 (rounded to the nearest hundred).

The bad news is that R187 800 does not come close to the R300 000 you wanted to pay! The good news is that you do not have to memorise this formula. In fact , when you answer questions like this in an exam, you will be expected to start from the beginning - writing out the opening equation in full, showing that it is the sum of a geometric sequence, deriving the answer, and then coming up with the correct numerical answer.

Sam is looking to buy his first flat, and has R15 000 in cash savings which he will use as a deposit. He has viewed a flat which is on the market for R250 000, and he would like to work out how much the monthly repayments would be. He will be taking out a 30 year mortgage with monthly repayments. The annual interest rate is 11%.

  1. The following is given:

    • Deposit amount = R15 000
    • Price of flat = R250 000
    • interest rate, i = 11 %

    We are required to find the monthly repayment for a 30-year mortgage.

  2. We know that:

    X = M [ ( 1 - ( 1 + i ) - n ) i ]

    In order to use this equation, we need to calculate M , the amount of the mortgage bond, which is the purchase price of property less the deposit which Sam pays up-front.

    M = R 250 000 - R 15 000 = R 235 000

    Now because we are considering monthly repayments, but we have been given an annual interest rate, we need to convert this to a monthly interest rate, i 12 . (If you are not clear on this, go back and revise [link] .)

    ( 1 + i 12 ) 12 = ( 1 + i ) ( 1 + i 12 ) 12 = 1 , 11 i 12 = 0 , 873459 %

    We know that the mortgage bond is for 30 years, which equates to 360 months.

  3. Now it is easy, we can just plug the numbers in the formula, but do not forget that you can always deduce the formula from first principles as well!

    X = M [ ( 1 - ( 1 + i ) - n ) i ] = R 235 000 [ ( 1 - ( 1 . 00876459 ) - 360 ) 0 , 008734594 ] = R 2 146 , 39
  4. That means that to buy a flat for R250 000, after Sam pays a R15 000 deposit, he will make repayments to the bank each month for the next 30 years equal to R2 146,39.

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Source:  OpenStax, Siyavula textbooks: grade 12 maths. OpenStax CNX. Aug 03, 2011 Download for free at http://cnx.org/content/col11242/1.2
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