# Appendix a to applied probability: directory of m-functions and m  (Page 23/24)

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mgd.m Uses coefficients for the generating function for N and the distribution for simple Y to calculate the distribution for the compound demand.

% MGD file mgd.m Moment generating function for compound demand % Version of 5/19/97% Uses m-functions csort, mgsum disp('Do not forget zeros coefficients for missing')disp('powers in the generating function for N') disp(' ')g = input('Enter COEFFICIENTS for gN '); y = input('Enter VALUES for Y ');p = input('Enter PROBABILITIES for Y '); n = length(g); % Initializationa = 0; b = 1;D = a; PD = g(1);for i = 2:n [a,b]= mgsum(y,a,p,b); D = [D a]; PD = [PD b*g(i)]; [D,PD]= csort(D,PD); endr = find(PD>1e-13); D = D(r); % Values with positive probabilityPD = PD(r); % Corresponding probabilities mD = [D; PD]'; % Display details disp('Values are in row matrix D; probabilities are in PD.')disp('To view the distribution, call for mD.')

mgdf.m function [d,pd] = mgdf(pn,y,py) is a function version of mgd , which allows arbitrary naming of the variables. The input matrix $pn$ is the coefficient matrix for the counting random variable generating function. Zeros for the missing powers must be included.The matrices $y,py$ are the actual values and probabilities of the demand random variable.

function [d,pd] = mgdf(pn,y,py)% MGDF [d,pd] = mgdf(pn,y,py) Function version of mgD% Version of 5/19/97 % Uses m-functions mgsum and csort% Do not forget zeros coefficients for missing % powers in the generating function for Nn = length(pn); % Initialization a = 0;b = 1; d = a;pd = pn(1); for i = 2:n[a,b] = mgsum(y,a,py,b);d = [d a];pd = [pd b*pn(i)];[d,pd] = csort(d,pd);end a = find(pd>1e-13); % Location of positive probabilities pd = pd(a); % Positive probabilitiesd = d(a); % D values with positive probability

randbern.m Let S be the number of successes in a random number N of Bernoulli trials, with probability p of success on each trial. The procedure randbern takes as inputs the probability p of success and the distribution matrices $N,PN$ for the counting random variable N and calculates the joint distribution for $\left\{N,S\right\}$ and the marginal distribution for S .

% RANDBERN file randbern.m Random number of Bernoulli trials % Version of 12/19/96; notation modified 5/20/97% Joint and marginal distributions for a random number of Bernoulli trials % N is the number of trials% S is the number of successes p = input('Enter the probability of success ');N = input('Enter VALUES of N '); PN = input('Enter PROBABILITIES for N ');n = length(N); m = max(N);S = 0:m; P = zeros(n,m+1);for i = 1:n P(i,1:N(i)+1) = PN(i)*ibinom(N(i),p,0:N(i));end PS = sum(P);P = rot90(P); disp('Joint distribution N, S, P, and marginal PS')

## Simulation of markov systems

inventory1.m Calculates the transition matrix for an $\left(m,M\right)$ inventory policy. At the end of each period, if the stock is less than a reorder point m , stock is replenished to the level M . Demand in each period is an integer valued random variable Y . Input consists of the parameters $m,\phantom{\rule{0.166667em}{0ex}}M$ and the distribution for Y as a simple random variable (or a discrete approximation).

% INVENTORY1 file inventory1.m Generates P for (m,M) inventory policy % Version of 1/27/97% Data for transition probability calculations % for (m,M) inventory policyM = input('Enter value M of maximum stock '); m = input('Enter value m of reorder point ');Y = input('Enter row vector of demand values '); PY = input('Enter demand probabilities ');states = 0:M; ms = length(states);my = length(Y); % Calculations for determining P[y,s] = meshgrid(Y,states);T = max(0,M-y).*(s<m) + max(0,s-y).*(s>= m); P = zeros(ms,ms);for i = 1:ms [a,b]= meshgrid(T(i,:),states); P(i,:) = PY*(a==b)';end disp('Result is in matrix P')

#### Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
can someone help me with some logarithmic and exponential equations.
sure. what is your question?
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
hmm
Abhi
is it a question of log
Abhi
🤔.
Abhi
I rally confuse this number And equations too I need exactly help
salma
But this is not salma it's Faiza live in lousvile Ky I garbage this so I am going collage with JCTC that the of the collage thank you my friends
salma
Commplementary angles
hello
Sherica
im all ears I need to learn
Sherica
right! what he said ⤴⤴⤴
Tamia
hii
Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
a perfect square v²+2v+_
kkk nice
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
rolling four fair dice and getting an even number an all four dice
Kristine 2*2*2=8
Differences Between Laspeyres and Paasche Indices
No. 7x -4y is simplified from 4x + (3y + 3x) -7y
how do you translate this in Algebraic Expressions
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
what's the easiest and fastest way to the synthesize AgNP?
China
Cied
types of nano material
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
what is nano technology
what is system testing?
preparation of nanomaterial
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
what is system testing
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
how did you get the value of 2000N.What calculations are needed to arrive at it
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A fair die is tossed 180 times. Find the probability P that the face 6 will appear between 29 and 32 times inclusive