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Solving the problem of mood detection

Control flow

The classification is based upon a branching flow , with an appropriate test at each node. The emotions are divided into broad categories and further tests are performed to identity each emotion individually. For this, we divided our set of four emotions into good and bad emotions with happy and surprised being the happy moods and sad and angry being the bad moods.

Before any of the tests were performed, the image of the face woudl be cropped to the mouth which is our primary interest. This can be done in one of two ways, either using Matlab's ginput command or the function goodcrop .The highest level test, Test 1 , distinguishes between pictures representing a happy or positive emotion from those representing a bad or negative emotion. Once a mood was detected as either being a happy or a sad mood it would then be tested again to classify it as one of the two moods in each category. The two pictures which are identified as having positive emotions are then sent to Test 2 which distinguishes between an happy and a surprised emotion. The other two pictures are sent to Test 3 which distinguishes between sad and angry.

Control flow

This method was quite effective as it reduced the total number of tests to be performed to three. Having a single test to correctly detect a emotion was not feasible because it involved setting thresholds which wouldnt hold over a wide variety of test cases and also increase the total number of tests being performed.

Goodcrop : image cropping routine

This function is used to crop the mouth from an image. It is called with the original image and returns the part of the image containing the mouth. It is based on the sobel edge detector. Due to the image specifications, it is safe to assume that the mouth is located in the lower third of the picture. The function makes this basic assumption and does an inital crop to this size. It then perform the edge detection and counts the number of edge points along each row and column. It also does a 11 point smoothing on the row and column summations to negate the effects of the nose being part of the intial crop.

It then chooses the peak correponding to the mouth and the extent of the peak to decide on the location and extent of the mouth vertically and horizontally.

Pre and Post Cropping

Test 1: good mood or sad mood

This test is used to distinguish between a good mood and a sad mood. It is based on the use of the 2D Gabor wavelet transformation. Use of the 2D Gabor wavelet representation was pioneered by Daugman in the 1980s. A complex-valued 2D Gabor function is a plane wave restricted by a Gaussian envelope.

k x k 2 x 2 k 2 x 2 2 2 k x 2 2

The Gabor wavelet representation allows description of spatial frequency structure in the image while preserving information about spatial relations. The complex amplitude of the transforms is used to test for features.

Gabor representation of the four moods for subject 1.

Since the Gabar wavelet highlights and extracts features from a facial image, those images with stronger expressions have greater intensity in their transforms relative to those with weaker expressions. As can be seen from Figure 1 the happy and suprised pictures which are on top have relatively higher values when compared to the sad and angry picctures. After taking the 2-norm of each transform, we are able to classify the strongest two as happy or surprised and the weaker two as sad or angry.

Test 2 : happy or surprised

Intuitively, the distinguishing feature between a smile and a surprise is the teeth and a measure of how open the mouth is. While more teeth are visible during a smile, a surprise d emoution has a more open mouth. Because teeth are white (hopefully!) and because white corresponds to a high intensity, we apply a process to determine how much of the mouth is high intensity and consequently, whether the person is smiling or not.

Surf plots for happy and surprised

The detector first creates high-contrast versions of our original cropped pictures. It then designates a threshold value that is 95% of the maximum value, which is usually white, and determines the number of such peaks that exist. The image with the greater number is designated"happy", and the other as"surprised".

Test 3 : sad or angry

From the start of our project we had anticipated difficulty in deciphering a sad from angry image since both emotions usually entail a closed mouth. With a closed mouth there was no way for us to compare intensity or even edges, as teeth create in a happy picture. To our advantage early in the project we had consulted with CAAM Professor Dr. Mark Embree, who suggested that we try using a Singular Value Decomposition (SVD) transform to analyze our images.

The equation of SVD:

Where u.v* creates a m*n matrix that is essentially a basis for the matrix A and is the coefficient relating the matrix A to the corresponding basis matrix. The most remarkable aspect of SVD is that the first few values and corresponding basis are nearly sufficient to reconstruct an image. For our project the matrix A corresponds to the cropped rectangle of the mouth. To utilize the SVD transform we used MATLABS built in function S=SVD(S) where S corresponds to the vector of the values pertaining to a particular matrix. After A few test cases we quickly realized that the norm of S for a sad image compared to an angry image where roughly greater in magnitude by 1,000-2000, or 10%-20%. This discovery allowed us to take the images that have been passed into this branch of testing and correctly discern the sad image from the angry image by a simple comparison. Here is an image to help visualize the method used for this branch of testing:
Image and corresponding svd plot for sad and angry emotions

Questions & Answers

find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
salma
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
Abhi
how do they get the third part x = (32)5/4
kinnecy Reply
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
ninjadapaul
20/(×-6^2)
Salomon
okay, so you have 6 raised to the power of 2. what is that part of your answer
ninjadapaul
I don't understand what the A with approx sign and the boxed x mean
ninjadapaul
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
Salomon
I'm not sure why it wrote it the other way
Salomon
I got X =-6
Salomon
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
ninjadapaul
oops. ignore that.
ninjadapaul
so you not have an equal sign anywhere in the original equation?
ninjadapaul
hmm
Abhi
is it a question of log
Abhi
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salma
Commplementary angles
Idrissa Reply
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Sherica
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Sherica
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Uday
hi
salma
what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
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a perfect square v²+2v+_
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Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
The answer is neither. The function, 2 = 0 cannot exist. Hence, the function is undefined.
Al
y=10×
Embra Reply
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rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
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Differences Between Laspeyres and Paasche Indices
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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how do you translate this in Algebraic Expressions
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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what's the easiest and fastest way to the synthesize AgNP?
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China
Cied
types of nano material
abeetha Reply
I start with an easy one. carbon nanotubes woven into a long filament like a string
Porter
many many of nanotubes
Porter
what is the k.e before it land
Yasmin
what is the function of carbon nanotubes?
Cesar
I'm interested in nanotube
Uday
what is nanomaterials​ and their applications of sensors.
Ramkumar Reply
what is nano technology
Sravani Reply
what is system testing?
AMJAD
preparation of nanomaterial
Victor Reply
Yes, Nanotechnology has a very fast field of applications and their is always something new to do with it...
Himanshu Reply
good afternoon madam
AMJAD
what is system testing
AMJAD
what is the application of nanotechnology?
Stotaw
In this morden time nanotechnology used in many field . 1-Electronics-manufacturad IC ,RAM,MRAM,solar panel etc 2-Helth and Medical-Nanomedicine,Drug Dilivery for cancer treatment etc 3- Atomobile -MEMS, Coating on car etc. and may other field for details you can check at Google
Azam
anybody can imagine what will be happen after 100 years from now in nano tech world
Prasenjit
after 100 year this will be not nanotechnology maybe this technology name will be change . maybe aftet 100 year . we work on electron lable practically about its properties and behaviour by the different instruments
Azam
name doesn't matter , whatever it will be change... I'm taking about effect on circumstances of the microscopic world
Prasenjit
how hard could it be to apply nanotechnology against viral infections such HIV or Ebola?
Damian
silver nanoparticles could handle the job?
Damian
not now but maybe in future only AgNP maybe any other nanomaterials
Azam
Hello
Uday
I'm interested in Nanotube
Uday
this technology will not going on for the long time , so I'm thinking about femtotechnology 10^-15
Prasenjit
can nanotechnology change the direction of the face of the world
Prasenjit Reply
At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
Ali Reply
the Beer law works very well for dilute solutions but fails for very high concentrations. why?
bamidele Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Source:  OpenStax, Ece 301 projects fall 2003. OpenStax CNX. Jan 22, 2004 Download for free at http://cnx.org/content/col10223/1.5
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