<< Chapter < Page Chapter >> Page >
This module includes a table of properties of the DTFS.

Introduction

In this module we will discuss the basic properties of the Discrete-Time Fourier Series. We will begin by refreshing your memory of our basic Fourier series equations:

f n k N 1 0 c k ω 0 k n
c k 1 N n N 1 0 f n 2 N k n
Let · denote the transformation from f n to the Fourier coefficients f n k k c k · maps complex valued functions to sequences of complex numbers .

Linearity

· is a linear transformation .

If f n c k and g n d k . Then α α α f n α c k and f n g n c k d k

Easy. Just linearity of integral.

f n g n k k n 0 N f n g n ω 0 k n k k 1 N n 0 N f n ω 0 k n 1 N n 0 N g n ω 0 k n k k c k d k c k d k

Shifting

Shifting in time equals a phase shift of Fourier coefficients

f n n 0 ω 0 k n 0 c k if c k c k c k , then ω 0 k n 0 c k ω 0 k n 0 c k c k ω 0 n 0 k c k ω 0 n 0 k

f n n 0 k k 1 N n 0 N f n n 0 ω 0 k n k k 1 N n n 0 N n 0 f n n 0 ω 0 k n n 0 ω 0 k n 0 k k 1 N n n 0 N n 0 f n ~ ω 0 k n ~ ω 0 k n 0 k k ω 0 k n ~ c k

Parseval's relation

n 0 N f n 2 N k N 1 0 c k 2
Parseval's relation tells us that the energy of a signal is equal to the energy of its Fourier transform.
Parseval tells us that the Fourier series maps L 0 N 2 to l 2 .

For f n to have "finite energy," what do the c k do as k ?

c k 2 for f n to have finite energy.

Got questions? Get instant answers now!

If k k 0 c k 1 k , is f L 0 N 2 ?

Yes, because c k 2 1 k 2 , which is summable.

Got questions? Get instant answers now!

Now, if k k 0 c k 1 k , is f L 0 N 2 ?

No, because c k 2 1 k , which is not summable.

Got questions? Get instant answers now!

The rate of decay of the Fourier series determines if f n has finite energy .

Parsevalstheorem demonstration

ParsevalsDemo
Interact (when online) with a Mathematica CDF demonstrating Parsevals Theorem. To download, right-click and save as .cdf.

Symmetry properties

Even signals

    Even signals

  • f [ n ] = f [ - n ]
  • c k = c - k
  • c k = 1 N Σ 0 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ n ] exp [ - ı ω 0 k n ] + 1 N Σ N 2 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ - n ] exp [ - ı ω 0 k n ] + 1 N Σ N 2 N f [ - n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N f [ n ] exp [ ı ω 0 k n ] + exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N f [ n ] 2 cos [ ω 0 k n ]

Odd signals

    Odd signals

  • f [ n ] = -f [ -n ]
  • c k = c - k *
  • c k = 1 N Σ 0 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ n ] exp [ - ı ω 0 k n ] + 1 N Σ N 2 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ n ] exp [ - ı ω 0 k n ] - 1 N Σ N 2 N f [ - n ] exp [ ı ω 0 k n ]
  • = - 1 N Σ 0 N f [ n ] exp [ ı ω 0 k n ] - exp [ - ı ω 0 k n ]
  • = - 1 N Σ 0 N f [ n ] 2 ı sin [ ω 0 k n ]

Real signals

    Real signals

  • f [ n ] = f * [ n ]
  • c k = c - k *
  • c k = 1 N Σ 0 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ n ] exp [ - ı ω 0 k n ] + 1 N Σ N 2 N f [ n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N 2 f [ - n ] exp [ - ı ω 0 k n ] + 1 N Σ N 2 N f [ - n ] exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N f [ n ] exp [ ı ω 0 k n ] + exp [ - ı ω 0 k n ]
  • = 1 N Σ 0 N f [ n ] 2 cos [ ω 0 k n ]

Differentiation in fourier domain

f n c k n f n k ω 0 c k

Since

f n k 0 N c k ω 0 k n
then
n f n k 0 N c k n ω 0 k n k 0 N c k ω 0 k ω 0 k n
A differentiator attenuates the low frequencies in f n and accentuates the high frequencies. It removes general trends and accentuates areas of sharpvariation.
A common way to mathematically measure the smoothness of a function f n is to see how many derivatives are finite energy.
This is done by looking at the Fourier coefficients of thesignal, specifically how fast they decay as k .If f n c k and c k has the form 1 k l , then n m f n k ω 0 m c k and has the form k m k l .So for the m th derivative to have finite energy, we need k k m k l 2 thus k m k l decays faster than 1 k which implies that 2 l 2 m 1 or l 2 m 1 2 Thus the decay rate of the Fourier series dictates smoothness.

Fourier differentiation demo

FourierDiffDiscreteDemo
Interact (when online) with a Mathematica CDF demonstrating Differentiation in a Fourier Domain. To download, right-click and save as .cdf.

Integration in the fourier domain

If

f n c k
then
η 0 n f η 1 ω 0 k c k
If c 0 0 , this expression doesn't make sense.

Integration accentuates low frequencies and attenuates high frequencies. Integrators bring out the general trends in signals and suppress short term variation(which is noise in many cases). Integrators are much nicer than differentiators.

Fourier integration demo

FourierIntDemo
Interact (when online) with a Mathematica CDF demonstrating the effect of Integration in a Fourier Domain.To download, right-click and save as .cdf.

Signal multiplication

Given a signal f n with Fourier coefficients c k and a signal g n with Fourier coefficients d k , we can define a new signal, y n , where y n f n g n . We find that the Fourier Series representation of y n , e k , is such that e k l 0 N c l d k - l . This is to say that signal multiplication in the time domainis equivalent to discrete-time circular convolution in the frequency domain.The proof of this is as follows

e k 1 N n 0 N f n g n ω 0 k n 1 N n 0 N l 0 N c l ω 0 l n g n ω 0 k n l 0 N c l 1 N n 0 N g n ω 0 k l n l 0 N c l d k - l

Conclusion

Like other Fourier transforms, the DTFS has many useful properties, including linearity, equal energy in the time and frequency domains, and analogs for shifting, differentation, and integration.

Properties of the Discrete Fourier Transform
Property Signal DTFS
Linearity a x ( n ) + b y ( n ) a X ( k ) + b Y ( k )
Time Shifting x ( n - m ) X ( k ) e - j 2 π m k / N
Time Modulation x ( n ) e j 2 π m n / N X ( k - m )
Multiplication x ( n ) y ( n ) X ( k ) * Y ( k )
Circular Convolution x ( n ) * y ( n ) X ( k ) Y ( K )

Questions & Answers

what is phylogeny
Odigie Reply
evolutionary history and relationship of an organism or group of organisms
AI-Robot
ok
Deng
what is biology
Hajah Reply
the study of living organisms and their interactions with one another and their environments
AI-Robot
what is biology
Victoria Reply
HOW CAN MAN ORGAN FUNCTION
Alfred Reply
the diagram of the digestive system
Assiatu Reply
allimentary cannel
Ogenrwot
How does twins formed
William Reply
They formed in two ways first when one sperm and one egg are splited by mitosis or two sperm and two eggs join together
Oluwatobi
what is genetics
Josephine Reply
Genetics is the study of heredity
Misack
how does twins formed?
Misack
What is manual
Hassan Reply
discuss biological phenomenon and provide pieces of evidence to show that it was responsible for the formation of eukaryotic organelles
Joseph Reply
what is biology
Yousuf Reply
the study of living organisms and their interactions with one another and their environment.
Wine
discuss the biological phenomenon and provide pieces of evidence to show that it was responsible for the formation of eukaryotic organelles in an essay form
Joseph Reply
what is the blood cells
Shaker Reply
list any five characteristics of the blood cells
Shaker
lack electricity and its more savely than electronic microscope because its naturally by using of light
Abdullahi Reply
advantage of electronic microscope is easily and clearly while disadvantage is dangerous because its electronic. advantage of light microscope is savely and naturally by sun while disadvantage is not easily,means its not sharp and not clear
Abdullahi
cell theory state that every organisms composed of one or more cell,cell is the basic unit of life
Abdullahi
is like gone fail us
DENG
cells is the basic structure and functions of all living things
Ramadan
What is classification
ISCONT Reply
is organisms that are similar into groups called tara
Yamosa
in what situation (s) would be the use of a scanning electron microscope be ideal and why?
Kenna Reply
A scanning electron microscope (SEM) is ideal for situations requiring high-resolution imaging of surfaces. It is commonly used in materials science, biology, and geology to examine the topography and composition of samples at a nanoscale level. SEM is particularly useful for studying fine details,
Hilary
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Signals and systems. OpenStax CNX. Aug 14, 2014 Download for free at http://legacy.cnx.org/content/col10064/1.15
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Signals and systems' conversation and receive update notifications?

Ask