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30 ( x 2 + 1 ) ( x 2 9 )

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In the following exercises, express each series as a rational function.

n = 1 1 x n

1 x n = 0 1 x n = 1 x 1 1 1 x = 1 x 1

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n = 1 1 ( x 3 ) 2 n 1

1 x 3 1 1 1 ( x 3 ) 2 = x 3 ( x 3 ) 2 1

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n = 1 ( 1 ( x 3 ) 2 n 1 1 ( x 2 ) 2 n 1 )

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The following exercises explore applications of annuities .

Calculate the present values P of an annuity in which $10,000 is to be paid out annually for a period of 20 years, assuming interest rates of r = 0.03 , r = 0.05 , and r = 0.07 .

P = P 1 + + P 20 where P k = 10,000 1 ( 1 + r ) k . Then P = 10,000 k = 1 20 1 ( 1 + r ) k = 10,000 1 ( 1 + r ) −20 r . When r = 0.03 , P 10,000 × 14.8775 = 148,775 . When r = 0.05 , P 10,000 × 12.4622 = 124,622 . When r = 0.07 , P 105,940 .

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Calculate the present values P of annuities in which $9,000 is to be paid out annually perpetually, assuming interest rates of r = 0.03 , r = 0.05 and r = 0.07 .

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Calculate the annual payouts C to be given for 20 years on annuities having present value $100,000 assuming respective interest rates of r = 0.03 , r = 0.05 , and r = 0.07 .

In general, P = C ( 1 ( 1 + r ) N ) r for N years of payouts, or C = P r 1 ( 1 + r ) N . For N = 20 and P = 100,000 , one has C = 6721.57 when r = 0.03 ; C = 8024.26 when r = 0.05 ; and C 9439.29 when r = 0.07 .

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Calculate the annual payouts C to be given perpetually on annuities having present value $100,000 assuming respective interest rates of r = 0.03 , r = 0.05 , and r = 0.07 .

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Suppose that an annuity has a present value P = 1 million dollars . What interest rate r would allow for perpetual annual payouts of $50,000?

In general, P = C r . Thus, r = C P = 5 × 10 4 10 6 = 0.05 .

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Suppose that an annuity has a present value P = 10 million dollars . What interest rate r would allow for perpetual annual payouts of $100,000?

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In the following exercises, express the sum of each power series in terms of geometric series, and then express the sum as a rational function.

x + x 2 x 3 + x 4 + x 5 x 6 + ( Hint: Group powers x 3 k , x 3 k 1 , and x 3 k 2 . )

( x + x 2 x 3 ) ( 1 + x 3 + x 6 + ) = x + x 2 x 3 1 x 3

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x + x 2 x 3 x 4 + x 5 + x 6 x 7 x 8 + ( Hint: Group powers x 4 k , x 4 k 1 , etc.)

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x x 2 x 3 + x 4 x 5 x 6 + x 7 ( Hint: Group powers x 3 k , x 3 k 1 , and x 3 k 2 . )

( x x 2 x 3 ) ( 1 + x 3 + x 6 + ) = x x 2 x 3 1 x 3

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x 2 + x 2 4 x 3 8 + x 4 16 + x 5 32 x 6 64 + ( Hint: Group powers ( x 2 ) 3 k , ( x 2 ) 3 k 1 , and ( x 2 ) 3 k 2 . )

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In the following exercises, find the power series of f ( x ) g ( x ) given f and g as defined.

f ( x ) = 2 n = 0 x n , g ( x ) = n = 0 n x n

a n = 2 , b n = n so c n = k = 0 n b k a n k = 2 k = 0 n k = ( n ) ( n + 1 ) and f ( x ) g ( x ) = n = 1 n ( n + 1 ) x n

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f ( x ) = n = 1 x n , g ( x ) = n = 1 1 n x n . Express the coefficients of f ( x ) g ( x ) in terms of H n = k = 1 n 1 k .

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f ( x ) = g ( x ) = n = 1 ( x 2 ) n

a n = b n = 2 n so c n = k = 1 n b k a n k = 2 n k = 1 n 1 = n 2 n and f ( x ) g ( x ) = n = 1 n ( x 2 ) n

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f ( x ) = g ( x ) = n = 1 n x n

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In the following exercises, differentiate the given series expansion of f term-by-term to obtain the corresponding series expansion for the derivative of f .

f ( x ) = 1 1 + x = n = 0 ( −1 ) n x n

The derivative of f is 1 ( 1 + x ) 2 = n = 0 ( −1 ) n ( n + 1 ) x n .

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f ( x ) = 1 1 x 2 = n = 0 x 2 n

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In the following exercises, integrate the given series expansion of f term-by-term from zero to x to obtain the corresponding series expansion for the indefinite integral of f .

f ( x ) = 2 x ( 1 + x 2 ) 2 = n = 1 ( −1 ) n ( 2 n ) x 2 n 1

The indefinite integral of f is 1 1 + x 2 = n = 0 ( −1 ) n x 2 n .

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f ( x ) = 2 x 1 + x 2 = 2 n = 0 ( −1 ) n x 2 n + 1

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In the following exercises, evaluate each infinite series by identifying it as the value of a derivative or integral of geometric series.

Evaluate n = 1 n 2 n as f ( 1 2 ) where f ( x ) = n = 0 x n .

f ( x ) = n = 0 x n = 1 1 x ; f ( 1 2 ) = n = 1 n 2 n 1 = d d x ( 1 x ) −1 | x = 1 / 2 = 1 ( 1 x ) 2 | x = 1 / 2 = 4 so n = 1 n 2 n = 2 .

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Practice Key Terms 2

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Source:  OpenStax, Calculus volume 2. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11965/1.2
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