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Conservative vector fields also have a special property called the cross-partial property . This property helps test whether a given vector field is conservative.

The cross-partial property of conservative vector fields

Let F be a vector field in two or three dimensions such that the component functions of F have continuous second-order mixed-partial derivatives on the domain of F .

If F ( x , y ) = P ( x , y ) , Q ( x , y ) is a conservative vector field in 2 , then P y = Q x . If F ( x , y , z ) = P ( x , y , z ) , Q ( x , y , z ) , R ( x , y , z ) is a conservative vector field in 3 , then

P y = Q x , Q z = R y , and R x = P z .

Proof

Since F is conservative, there is a function f ( x , y ) such that f = F . Therefore, by the definition of the gradient, f x = P and f y = Q . By Clairaut’s theorem, f x y = f y x , But, f x y = P y and f y x = Q x , and thus P y = Q x .

Clairaut’s theorem gives a fast proof of the cross-partial property of conservative vector fields in 3 , just as it did for vector fields in 2 .

[link] shows that most vector fields are not conservative. The cross-partial property is difficult to satisfy in general, so most vector fields won’t have equal cross-partials.

Showing a vector field is not conservative

Show that rotational vector field F ( x , y ) = y , x is not conservative.

Let P ( x , y ) = y and Q ( x , y ) = x . If F is conservative, then the cross-partials would be equal—that is, P y would equal Q x . Therefore, to show that F is not conservative, check that P y Q x . Since P y = 1 and Q x = −1 , the vector field is not conservative.

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Show that vector field F ( x , y ) x y i x 2 y j is not conservative.

P y = x Q x = −2 x y

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Showing a vector field is not conservative

Is vector field F ( x , y , z ) = 7 , −2 , x 3 conservative?

Let P ( x , y , z ) = 7 , Q ( x , y , z ) = −2 , and R ( x , y , z ) = x 3 . If F is conservative, then all three cross-partial equations will be satisfied—that is, if F is conservative, then P y would equal Q x , Q z would equal R y , and R x would equal P z . Note that P y = Q x = R y = Q z = 0 , so the first two necessary equalities hold. However, R x = x 3 and P z = 0 so R x P z . Therefore, F is not conservative.

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Is vector field G ( x , y , z ) = y , x , x y z conservative?

No

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We conclude this section with a word of warning: [link] says that if F is conservative, then F has the cross-partial property. The theorem does not say that, if F has the cross-partial property, then F is conservative (the converse of an implication is not logically equivalent to the original implication). In other words, [link] can only help determine that a field is not conservative; it does not let you conclude that a vector field is conservative. For example, consider vector field F ( x , y ) = x 2 y , x 3 3 . This field has the cross-partial property, so it is natural to try to use [link] to conclude this vector field is conservative. However, this is a misapplication of the theorem. We learn later how to conclude that F is conservative.

Key concepts

  • A vector field assigns a vector F ( x , y ) to each point ( x , y ) in a subset D of 2 or 3 . F ( x , y , z ) to each point ( x , y , z ) in a subset D of 3 .
  • Vector fields can describe the distribution of vector quantities such as forces or velocities over a region of the plane or of space. They are in common use in such areas as physics, engineering, meteorology, oceanography.
  • We can sketch a vector field by examining its defining equation to determine relative magnitudes in various locations and then drawing enough vectors to determine a pattern.
  • A vector field F is called conservative if there exists a scalar function f such that f = F .

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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